* Step 1: Sum WORST_CASE(?,O(n^1))
    + Considered Problem:
        - Strict TRS:
            f(0()) -> cons(0())
            f(s(0())) -> f(p(s(0())))
            p(s(X)) -> X
        - Signature:
            {f/1,p/1} / {0/0,cons/1,s/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {f,p} and constructors {0,cons,s}
    + Applied Processor:
        Sum {left = someStrategy, right = someStrategy}
    + Details:
        ()
* Step 2: Bounds WORST_CASE(?,O(n^1))
    + Considered Problem:
        - Strict TRS:
            f(0()) -> cons(0())
            f(s(0())) -> f(p(s(0())))
            p(s(X)) -> X
        - Signature:
            {f/1,p/1} / {0/0,cons/1,s/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {f,p} and constructors {0,cons,s}
    + Applied Processor:
        Bounds {initialAutomaton = minimal, enrichment = match}
    + Details:
        The problem is match-bounded by 2.
        The enriched problem is compatible with follwoing automaton.
          0_0() -> 1
          0_0() -> 2
          0_1() -> 3
          0_1() -> 4
          0_2() -> 6
          cons_0(2) -> 1
          cons_0(2) -> 2
          cons_1(3) -> 1
          cons_2(6) -> 1
          f_0(2) -> 1
          f_1(4) -> 1
          p_0(2) -> 1
          p_1(5) -> 4
          s_0(2) -> 1
          s_0(2) -> 2
          s_1(3) -> 5
          2 -> 1
          3 -> 4
* Step 3: EmptyProcessor WORST_CASE(?,O(1))
    + Considered Problem:
        - Weak TRS:
            f(0()) -> cons(0())
            f(s(0())) -> f(p(s(0())))
            p(s(X)) -> X
        - Signature:
            {f/1,p/1} / {0/0,cons/1,s/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {f,p} and constructors {0,cons,s}
    + Applied Processor:
        EmptyProcessor
    + Details:
        The problem is already closed. The intended complexity is O(1).

WORST_CASE(?,O(n^1))