* Step 1: Sum WORST_CASE(Omega(n^1),O(n^1))
    + Considered Problem:
        - Strict TRS:
            a(b(x)) -> b(b(a(x)))
        - Signature:
            {a/1} / {b/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {a} and constructors {b}
    + Applied Processor:
        Sum {left = someStrategy, right = someStrategy}
    + Details:
        ()
** Step 1.a:1: DecreasingLoops WORST_CASE(Omega(n^1),?)
    + Considered Problem:
        - Strict TRS:
            a(b(x)) -> b(b(a(x)))
        - Signature:
            {a/1} / {b/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {a} and constructors {b}
    + Applied Processor:
        DecreasingLoops {bound = AnyLoop, narrow = 10}
    + Details:
        The system has following decreasing Loops:
          a(x){x -> b(x)} =
            a(b(x)) ->^+ b(b(a(x)))
              = C[a(x) = a(x){}]

** Step 1.b:1: Bounds WORST_CASE(?,O(n^1))
    + Considered Problem:
        - Strict TRS:
            a(b(x)) -> b(b(a(x)))
        - Signature:
            {a/1} / {b/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {a} and constructors {b}
    + Applied Processor:
        Bounds {initialAutomaton = minimal, enrichment = match}
    + Details:
        The problem is match-bounded by 1.
        The enriched problem is compatible with follwoing automaton.
          a_0(2) -> 1
          a_1(2) -> 4
          b_0(2) -> 2
          b_1(3) -> 1
          b_1(3) -> 4
          b_1(4) -> 3
** Step 1.b:2: EmptyProcessor WORST_CASE(?,O(1))
    + Considered Problem:
        - Weak TRS:
            a(b(x)) -> b(b(a(x)))
        - Signature:
            {a/1} / {b/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {a} and constructors {b}
    + Applied Processor:
        EmptyProcessor
    + Details:
        The problem is already closed. The intended complexity is O(1).

WORST_CASE(Omega(n^1),O(n^1))