* Step 1: Sum WORST_CASE(?,O(n^1))
    + Considered Problem:
        - Strict TRS:
            even(Cons(x,xs)) -> odd(xs)
            even(Nil()) -> True()
            evenodd(x) -> even(x)
            notEmpty(Cons(x,xs)) -> True()
            notEmpty(Nil()) -> False()
            odd(Cons(x,xs)) -> even(xs)
            odd(Nil()) -> False()
        - Signature:
            {even/1,evenodd/1,notEmpty/1,odd/1} / {Cons/2,False/0,Nil/0,True/0}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {even,evenodd,notEmpty,odd} and constructors {Cons,False
            ,Nil,True}
    + Applied Processor:
        Sum {left = someStrategy, right = someStrategy}
    + Details:
        ()
* Step 2: Bounds WORST_CASE(?,O(n^1))
    + Considered Problem:
        - Strict TRS:
            even(Cons(x,xs)) -> odd(xs)
            even(Nil()) -> True()
            evenodd(x) -> even(x)
            notEmpty(Cons(x,xs)) -> True()
            notEmpty(Nil()) -> False()
            odd(Cons(x,xs)) -> even(xs)
            odd(Nil()) -> False()
        - Signature:
            {even/1,evenodd/1,notEmpty/1,odd/1} / {Cons/2,False/0,Nil/0,True/0}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {even,evenodd,notEmpty,odd} and constructors {Cons,False
            ,Nil,True}
    + Applied Processor:
        Bounds {initialAutomaton = minimal, enrichment = match}
    + Details:
        The problem is match-bounded by 1.
        The enriched problem is compatible with follwoing automaton.
          Cons_0(2,2) -> 2
          False_0() -> 2
          False_1() -> 1
          Nil_0() -> 2
          True_0() -> 2
          True_1() -> 1
          even_0(2) -> 1
          even_1(2) -> 1
          evenodd_0(2) -> 1
          notEmpty_0(2) -> 1
          odd_0(2) -> 1
          odd_1(2) -> 1
* Step 3: EmptyProcessor WORST_CASE(?,O(1))
    + Considered Problem:
        - Weak TRS:
            even(Cons(x,xs)) -> odd(xs)
            even(Nil()) -> True()
            evenodd(x) -> even(x)
            notEmpty(Cons(x,xs)) -> True()
            notEmpty(Nil()) -> False()
            odd(Cons(x,xs)) -> even(xs)
            odd(Nil()) -> False()
        - Signature:
            {even/1,evenodd/1,notEmpty/1,odd/1} / {Cons/2,False/0,Nil/0,True/0}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {even,evenodd,notEmpty,odd} and constructors {Cons,False
            ,Nil,True}
    + Applied Processor:
        EmptyProcessor
    + Details:
        The problem is already closed. The intended complexity is O(1).

WORST_CASE(?,O(n^1))