* Step 1: Sum WORST_CASE(Omega(n^1),O(n^1))
    + Considered Problem:
        - Strict TRS:
            f(0()) -> s(0())
            f(s(0())) -> s(0())
            f(s(s(x))) -> f(f(s(x)))
        - Signature:
            {f/1} / {0/0,s/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {f} and constructors {0,s}
    + Applied Processor:
        Sum {left = someStrategy, right = someStrategy}
    + Details:
        ()
** Step 1.a:1: DecreasingLoops WORST_CASE(Omega(n^1),?)
    + Considered Problem:
        - Strict TRS:
            f(0()) -> s(0())
            f(s(0())) -> s(0())
            f(s(s(x))) -> f(f(s(x)))
        - Signature:
            {f/1} / {0/0,s/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {f} and constructors {0,s}
    + Applied Processor:
        DecreasingLoops {bound = AnyLoop, narrow = 10}
    + Details:
        The system has following decreasing Loops:
          f(s(x)){x -> s(x)} =
            f(s(s(x))) ->^+ f(f(s(x)))
              = C[f(s(x)) = f(s(x)){}]

** Step 1.b:1: Bounds WORST_CASE(?,O(n^1))
    + Considered Problem:
        - Strict TRS:
            f(0()) -> s(0())
            f(s(0())) -> s(0())
            f(s(s(x))) -> f(f(s(x)))
        - Signature:
            {f/1} / {0/0,s/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {f} and constructors {0,s}
    + Applied Processor:
        Bounds {initialAutomaton = minimal, enrichment = match}
    + Details:
        The problem is match-bounded by 2.
        The enriched problem is compatible with follwoing automaton.
          0_0() -> 2
          0_1() -> 3
          0_2() -> 6
          f_0(2) -> 1
          f_1(4) -> 1
          f_1(4) -> 4
          f_1(5) -> 4
          s_0(2) -> 2
          s_1(2) -> 5
          s_1(3) -> 1
          s_1(3) -> 4
          s_2(6) -> 1
          s_2(6) -> 4
** Step 1.b:2: EmptyProcessor WORST_CASE(?,O(1))
    + Considered Problem:
        - Weak TRS:
            f(0()) -> s(0())
            f(s(0())) -> s(0())
            f(s(s(x))) -> f(f(s(x)))
        - Signature:
            {f/1} / {0/0,s/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {f} and constructors {0,s}
    + Applied Processor:
        EmptyProcessor
    + Details:
        The problem is already closed. The intended complexity is O(1).

WORST_CASE(Omega(n^1),O(n^1))