### (0) Obligation:

Runtime Complexity TRS:
The TRS R consists of the following rules:

g(f(x, y), z) → f(x, g(y, z))
g(h(x, y), z) → g(x, f(y, z))
g(x, h(y, z)) → h(g(x, y), z)

Rewrite Strategy: INNERMOST

### (1) CpxTrsToCdtProof (BOTH BOUNDS(ID, ID) transformation)

Converted Cpx (relative) TRS to CDT

### (2) Obligation:

Complexity Dependency Tuples Problem
Rules:

g(f(z0, z1), z2) → f(z0, g(z1, z2))
g(h(z0, z1), z2) → g(z0, f(z1, z2))
g(z0, h(z1, z2)) → h(g(z0, z1), z2)
Tuples:

G(f(z0, z1), z2) → c(G(z1, z2))
G(h(z0, z1), z2) → c1(G(z0, f(z1, z2)))
G(z0, h(z1, z2)) → c2(G(z0, z1))
S tuples:

G(f(z0, z1), z2) → c(G(z1, z2))
G(h(z0, z1), z2) → c1(G(z0, f(z1, z2)))
G(z0, h(z1, z2)) → c2(G(z0, z1))
K tuples:none
Defined Rule Symbols:

g

Defined Pair Symbols:

G

Compound Symbols:

c, c1, c2

### (3) CdtUsableRulesProof (EQUIVALENT transformation)

The following rules are not usable and were removed:

g(f(z0, z1), z2) → f(z0, g(z1, z2))
g(h(z0, z1), z2) → g(z0, f(z1, z2))
g(z0, h(z1, z2)) → h(g(z0, z1), z2)

### (4) Obligation:

Complexity Dependency Tuples Problem
Rules:none
Tuples:

G(f(z0, z1), z2) → c(G(z1, z2))
G(h(z0, z1), z2) → c1(G(z0, f(z1, z2)))
G(z0, h(z1, z2)) → c2(G(z0, z1))
S tuples:

G(f(z0, z1), z2) → c(G(z1, z2))
G(h(z0, z1), z2) → c1(G(z0, f(z1, z2)))
G(z0, h(z1, z2)) → c2(G(z0, z1))
K tuples:none
Defined Rule Symbols:none

Defined Pair Symbols:

G

Compound Symbols:

c, c1, c2

### (5) CdtRuleRemovalProof (UPPER BOUND (ADD(O(n^1))) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

G(f(z0, z1), z2) → c(G(z1, z2))
G(h(z0, z1), z2) → c1(G(z0, f(z1, z2)))
G(z0, h(z1, z2)) → c2(G(z0, z1))
We considered the (Usable) Rules:none
And the Tuples:

G(f(z0, z1), z2) → c(G(z1, z2))
G(h(z0, z1), z2) → c1(G(z0, f(z1, z2)))
G(z0, h(z1, z2)) → c2(G(z0, z1))
The order we found is given by the following interpretation:
Polynomial interpretation :

POL(G(x1, x2)) = [4]x1 + [5]x2
POL(c(x1)) = x1
POL(c1(x1)) = x1
POL(c2(x1)) = x1
POL(f(x1, x2)) = [2] + x2
POL(h(x1, x2)) = [5] + x1 + x2

### (6) Obligation:

Complexity Dependency Tuples Problem
Rules:none
Tuples:

G(f(z0, z1), z2) → c(G(z1, z2))
G(h(z0, z1), z2) → c1(G(z0, f(z1, z2)))
G(z0, h(z1, z2)) → c2(G(z0, z1))
S tuples:none
K tuples:

G(f(z0, z1), z2) → c(G(z1, z2))
G(h(z0, z1), z2) → c1(G(z0, f(z1, z2)))
G(z0, h(z1, z2)) → c2(G(z0, z1))
Defined Rule Symbols:none

Defined Pair Symbols:

G

Compound Symbols:

c, c1, c2

### (7) SIsEmptyProof (BOTH BOUNDS(ID, ID) transformation)

The set S is empty