*** 1 Progress [(O(1),O(n^2))]  ***
    Considered Problem:
      Strict DP Rules:
        
      Strict TRS Rules:
        main(x5,x12) -> map#2(plus_x(x12),x5)
        map#2(plus_x(x2),Nil()) -> Nil()
        map#2(plus_x(x6),Cons(x4,x2)) -> Cons(plus_x#1(x6,x4),map#2(plus_x(x6),x2))
        plus_x#1(0(),x8) -> x8
        plus_x#1(S(x12),x14) -> S(plus_x#1(x12,x14))
      Weak DP Rules:
        
      Weak TRS Rules:
        
      Signature:
        {main/2,map#2/2,plus_x#1/2} / {0/0,Cons/2,Nil/0,S/1,plus_x/1}
      Obligation:
        Innermost
        basic terms: {main,map#2,plus_x#1}/{0,Cons,Nil,S,plus_x}
    Applied Processor:
      WeightGap {wgDimension = 1, wgDegree = 1, wgKind = Algebraic, wgUArgs = UArgs, wgOn = WgOnAny}
    Proof:
      The weightgap principle applies using the following nonconstant growth matrix-interpretation:
        We apply a matrix interpretation of kind constructor based matrix interpretation:
        The following argument positions are considered usable:
          uargs(Cons) = {1,2},
          uargs(S) = {1}
        
        Following symbols are considered usable:
          {}
        TcT has computed the following interpretation:
                 p(0) = [1]                  
              p(Cons) = [1] x1 + [1] x2 + [6]
               p(Nil) = [10]                 
                 p(S) = [1] x1 + [1]         
              p(main) = [2] x1 + [13]        
             p(map#2) = [1] x1 + [2] x2 + [5]
            p(plus_x) = [4]                  
          p(plus_x#1) = [2] x2 + [4]         
        
        Following rules are strictly oriented:
                         main(x5,x12) = [2] x5 + [13]             
                                      > [2] x5 + [9]              
                                      = map#2(plus_x(x12),x5)     
        
              map#2(plus_x(x2),Nil()) = [29]                      
                                      > [10]                      
                                      = Nil()                     
        
        map#2(plus_x(x6),Cons(x4,x2)) = [2] x2 + [2] x4 + [21]    
                                      > [2] x2 + [2] x4 + [19]    
                                      = Cons(plus_x#1(x6,x4)      
                                            ,map#2(plus_x(x6),x2))
        
                     plus_x#1(0(),x8) = [2] x8 + [4]              
                                      > [1] x8 + [0]              
                                      = x8                        
        
        
        Following rules are (at-least) weakly oriented:
        plus_x#1(S(x12),x14) =  [2] x14 + [4]       
                             >= [2] x14 + [5]       
                             =  S(plus_x#1(x12,x14))
        
      Further, it can be verified that all rules not oriented are covered by the weightgap condition.
*** 1.1 Progress [(O(1),O(n^2))]  ***
    Considered Problem:
      Strict DP Rules:
        
      Strict TRS Rules:
        plus_x#1(S(x12),x14) -> S(plus_x#1(x12,x14))
      Weak DP Rules:
        
      Weak TRS Rules:
        main(x5,x12) -> map#2(plus_x(x12),x5)
        map#2(plus_x(x2),Nil()) -> Nil()
        map#2(plus_x(x6),Cons(x4,x2)) -> Cons(plus_x#1(x6,x4),map#2(plus_x(x6),x2))
        plus_x#1(0(),x8) -> x8
      Signature:
        {main/2,map#2/2,plus_x#1/2} / {0/0,Cons/2,Nil/0,S/1,plus_x/1}
      Obligation:
        Innermost
        basic terms: {main,map#2,plus_x#1}/{0,Cons,Nil,S,plus_x}
    Applied Processor:
      NaturalPI {shape = Mixed 2, restrict = Restrict, uargs = UArgs, urules = URules, selector = Just any strict-rules, greedy = NoGreedy}
    Proof:
      We apply a polynomial interpretation of kind constructor-based(mixed(2)):
      The following argument positions are considered usable:
        uargs(Cons) = {1,2},
        uargs(S) = {1}
      
      Following symbols are considered usable:
        {main,map#2,plus_x#1}
      TcT has computed the following interpretation:
               p(0) = 1                                      
            p(Cons) = 1 + x1 + x2                            
             p(Nil) = 1                                      
               p(S) = 1 + x1                                 
            p(main) = 5*x1 + 4*x1*x2 + 4*x1^2 + 4*x2 + 6*x2^2
           p(map#2) = x1 + 2*x1*x2 + 4*x1^2 + 3*x2 + 2*x2^2  
          p(plus_x) = x1                                     
        p(plus_x#1) = 2*x1 + x2                              
      
      Following rules are strictly oriented:
      plus_x#1(S(x12),x14) = 2 + 2*x12 + x14     
                           > 1 + 2*x12 + x14     
                           = S(plus_x#1(x12,x14))
      
      
      Following rules are (at-least) weakly oriented:
                       main(x5,x12) =  4*x12 + 4*x12*x5 + 6*x12^2 + 5*x5 + 4*x5^2                                     
                                    >= x12 + 2*x12*x5 + 4*x12^2 + 3*x5 + 2*x5^2                                       
                                    =  map#2(plus_x(x12),x5)                                                          
      
            map#2(plus_x(x2),Nil()) =  5 + 3*x2 + 4*x2^2                                                              
                                    >= 1                                                                              
                                    =  Nil()                                                                          
      
      map#2(plus_x(x6),Cons(x4,x2)) =  5 + 7*x2 + 4*x2*x4 + 2*x2*x6 + 2*x2^2 + 7*x4 + 2*x4*x6 + 2*x4^2 + 3*x6 + 4*x6^2
                                    >= 1 + 3*x2 + 2*x2*x6 + 2*x2^2 + x4 + 3*x6 + 4*x6^2                               
                                    =  Cons(plus_x#1(x6,x4)                                                           
                                           ,map#2(plus_x(x6),x2))                                                     
      
                   plus_x#1(0(),x8) =  2 + x8                                                                         
                                    >= x8                                                                             
                                    =  x8                                                                             
      
*** 1.1.1 Progress [(O(1),O(1))]  ***
    Considered Problem:
      Strict DP Rules:
        
      Strict TRS Rules:
        
      Weak DP Rules:
        
      Weak TRS Rules:
        main(x5,x12) -> map#2(plus_x(x12),x5)
        map#2(plus_x(x2),Nil()) -> Nil()
        map#2(plus_x(x6),Cons(x4,x2)) -> Cons(plus_x#1(x6,x4),map#2(plus_x(x6),x2))
        plus_x#1(0(),x8) -> x8
        plus_x#1(S(x12),x14) -> S(plus_x#1(x12,x14))
      Signature:
        {main/2,map#2/2,plus_x#1/2} / {0/0,Cons/2,Nil/0,S/1,plus_x/1}
      Obligation:
        Innermost
        basic terms: {main,map#2,plus_x#1}/{0,Cons,Nil,S,plus_x}
    Applied Processor:
      EmptyProcessor
    Proof:
      The problem is already closed. The intended complexity is O(1).