We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).
Strict Trs: { h(f(x, y)) -> f(y, f(h(h(x)), a())) }
Obligation:
innermost runtime complexity
Answer:
YES(O(1),O(n^1))
We add the following dependency tuples:
Strict DPs: { h^#(f(x, y)) -> c_1(h^#(h(x)), h^#(x)) }
and mark the set of starting terms.
We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).
Strict DPs: { h^#(f(x, y)) -> c_1(h^#(h(x)), h^#(x)) }
Weak Trs: { h(f(x, y)) -> f(y, f(h(h(x)), a())) }
Obligation:
innermost runtime complexity
Answer:
YES(O(1),O(n^1))
We use the processor 'matrix interpretation of dimension 2' to
orient following rules strictly.
DPs:
{ 1: h^#(f(x, y)) -> c_1(h^#(h(x)), h^#(x)) }
Sub-proof:
----------
The following argument positions are usable:
Uargs(c_1) = {1, 2}
TcT has computed the following constructor-based matrix
interpretation satisfying not(EDA) and not(IDA(1)).
[h](x1) = [0 1] x1 + [0]
[4 0] [2]
[f](x1, x2) = [1 1] x1 + [0 0] x2 + [2]
[0 0] [1 1] [2]
[a] = [0]
[0]
[h^#](x1) = [3 0] x1 + [0]
[0 1] [0]
[c_1](x1, x2) = [1 0] x1 + [1 0] x2 + [1]
[0 0] [0 0] [0]
The order satisfies the following ordering constraints:
[h(f(x, y))] = [0 0] x + [1 1] y + [2]
[4 4] [0 0] [10]
>= [0 0] x + [1 1] y + [2]
[4 4] [0 0] [10]
= [f(y, f(h(h(x)), a()))]
[h^#(f(x, y))] = [3 3] x + [0 0] y + [6]
[0 0] [1 1] [2]
> [3 3] x + [1]
[0 0] [0]
= [c_1(h^#(h(x)), h^#(x))]
The strictly oriented rules are moved into the weak component.
We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(1)).
Weak DPs: { h^#(f(x, y)) -> c_1(h^#(h(x)), h^#(x)) }
Weak Trs: { h(f(x, y)) -> f(y, f(h(h(x)), a())) }
Obligation:
innermost runtime complexity
Answer:
YES(O(1),O(1))
The following weak DPs constitute a sub-graph of the DG that is
closed under successors. The DPs are removed.
{ h^#(f(x, y)) -> c_1(h^#(h(x)), h^#(x)) }
We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(1)).
Weak Trs: { h(f(x, y)) -> f(y, f(h(h(x)), a())) }
Obligation:
innermost runtime complexity
Answer:
YES(O(1),O(1))
No rule is usable, rules are removed from the input problem.
We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(1)).
Rules: Empty
Obligation:
innermost runtime complexity
Answer:
YES(O(1),O(1))
Empty rules are trivially bounded
Hurray, we answered YES(O(1),O(n^1))