*** 1 Progress [(?,O(n^1))]  ***
    Considered Problem:
      Strict DP Rules:
        
      Strict TRS Rules:
        f(x,0()) -> s(0())
        f(s(x),s(y)) -> s(f(x,y))
        g(0(),x) -> g(f(x,x),x)
      Weak DP Rules:
        
      Weak TRS Rules:
        
      Signature:
        {f/2,g/2} / {0/0,s/1}
      Obligation:
        Innermost
        basic terms: {f,g}/{0,s}
    Applied Processor:
      DependencyPairs {dpKind_ = DT}
    Proof:
      We add the following dependency tuples:
      
      Strict DPs
        f#(x,0()) -> c_1()
        f#(s(x),s(y)) -> c_2(f#(x,y))
        g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
      Weak DPs
        
      
      and mark the set of starting terms.
*** 1.1 Progress [(?,O(n^1))]  ***
    Considered Problem:
      Strict DP Rules:
        f#(x,0()) -> c_1()
        f#(s(x),s(y)) -> c_2(f#(x,y))
        g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
      Strict TRS Rules:
        
      Weak DP Rules:
        
      Weak TRS Rules:
        f(x,0()) -> s(0())
        f(s(x),s(y)) -> s(f(x,y))
        g(0(),x) -> g(f(x,x),x)
      Signature:
        {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
      Obligation:
        Innermost
        basic terms: {f#,g#}/{0,s}
    Applied Processor:
      UsableRules
    Proof:
      We replace rewrite rules by usable rules:
        f(x,0()) -> s(0())
        f(s(x),s(y)) -> s(f(x,y))
        f#(x,0()) -> c_1()
        f#(s(x),s(y)) -> c_2(f#(x,y))
        g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
*** 1.1.1 Progress [(?,O(n^1))]  ***
    Considered Problem:
      Strict DP Rules:
        f#(x,0()) -> c_1()
        f#(s(x),s(y)) -> c_2(f#(x,y))
        g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
      Strict TRS Rules:
        
      Weak DP Rules:
        
      Weak TRS Rules:
        f(x,0()) -> s(0())
        f(s(x),s(y)) -> s(f(x,y))
      Signature:
        {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
      Obligation:
        Innermost
        basic terms: {f#,g#}/{0,s}
    Applied Processor:
      PredecessorEstimation {onSelection = all simple predecessor estimation selector}
    Proof:
      We estimate the number of application of
        {1}
      by application of
        Pre({1}) = {2,3}.
      Here rules are labelled as follows:
        1: f#(x,0()) -> c_1()           
        2: f#(s(x),s(y)) -> c_2(f#(x,y))
        3: g#(0(),x) -> c_3(g#(f(x,x),x)
                           ,f#(x,x))    
*** 1.1.1.1 Progress [(?,O(n^1))]  ***
    Considered Problem:
      Strict DP Rules:
        f#(s(x),s(y)) -> c_2(f#(x,y))
        g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
      Strict TRS Rules:
        
      Weak DP Rules:
        f#(x,0()) -> c_1()
      Weak TRS Rules:
        f(x,0()) -> s(0())
        f(s(x),s(y)) -> s(f(x,y))
      Signature:
        {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
      Obligation:
        Innermost
        basic terms: {f#,g#}/{0,s}
    Applied Processor:
      RemoveWeakSuffixes
    Proof:
      Consider the dependency graph
        1:S:f#(s(x),s(y)) -> c_2(f#(x,y))
           -->_1 f#(x,0()) -> c_1():3
           -->_1 f#(s(x),s(y)) -> c_2(f#(x,y)):1
        
        2:S:g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
           -->_2 f#(x,0()) -> c_1():3
           -->_1 g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x)):2
           -->_2 f#(s(x),s(y)) -> c_2(f#(x,y)):1
        
        3:W:f#(x,0()) -> c_1()
           
        
      The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed.
        3: f#(x,0()) -> c_1()
*** 1.1.1.1.1 Progress [(?,O(n^1))]  ***
    Considered Problem:
      Strict DP Rules:
        f#(s(x),s(y)) -> c_2(f#(x,y))
        g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
      Strict TRS Rules:
        
      Weak DP Rules:
        
      Weak TRS Rules:
        f(x,0()) -> s(0())
        f(s(x),s(y)) -> s(f(x,y))
      Signature:
        {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
      Obligation:
        Innermost
        basic terms: {f#,g#}/{0,s}
    Applied Processor:
      Decompose {onSelection = all cycle independent sub-graph, withBound = RelativeAdd}
    Proof:
      We analyse the complexity of following sub-problems (R) and (S).
      Problem (S) is obtained from the input problem by shifting strict rules from (R) into the weak component.
      
      Problem (R)
        Strict DP Rules:
          f#(s(x),s(y)) -> c_2(f#(x,y))
        Strict TRS Rules:
          
        Weak DP Rules:
          g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
        Weak TRS Rules:
          f(x,0()) -> s(0())
          f(s(x),s(y)) -> s(f(x,y))
        Signature:
          {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
        Obligation:
          Innermost
          basic terms: {f#,g#}/{0,s}
      
      Problem (S)
        Strict DP Rules:
          g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
        Strict TRS Rules:
          
        Weak DP Rules:
          f#(s(x),s(y)) -> c_2(f#(x,y))
        Weak TRS Rules:
          f(x,0()) -> s(0())
          f(s(x),s(y)) -> s(f(x,y))
        Signature:
          {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
        Obligation:
          Innermost
          basic terms: {f#,g#}/{0,s}
  *** 1.1.1.1.1.1 Progress [(?,O(n^1))]  ***
      Considered Problem:
        Strict DP Rules:
          f#(s(x),s(y)) -> c_2(f#(x,y))
        Strict TRS Rules:
          
        Weak DP Rules:
          g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
        Weak TRS Rules:
          f(x,0()) -> s(0())
          f(s(x),s(y)) -> s(f(x,y))
        Signature:
          {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
        Obligation:
          Innermost
          basic terms: {f#,g#}/{0,s}
      Applied Processor:
        DecomposeDG {onSelection = all below first cut in WDG, onUpper = Just someStrategy, onLower = Nothing}
      Proof:
        We decompose the input problem according to the dependency graph into the upper component
          g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
        and a lower component
          f#(s(x),s(y)) -> c_2(f#(x,y))
        Further, following extension rules are added to the lower component.
          g#(0(),x) -> f#(x,x)
          g#(0(),x) -> g#(f(x,x),x)
    *** 1.1.1.1.1.1.1 Progress [(?,O(1))]  ***
        Considered Problem:
          Strict DP Rules:
            g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
          Strict TRS Rules:
            
          Weak DP Rules:
            
          Weak TRS Rules:
            f(x,0()) -> s(0())
            f(s(x),s(y)) -> s(f(x,y))
          Signature:
            {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
          Obligation:
            Innermost
            basic terms: {f#,g#}/{0,s}
        Applied Processor:
          PredecessorEstimationCP {onSelectionCP = any intersect of rules of CDG leaf and strict-rules, withComplexityPair = NaturalMI {miDimension = 1, miDegree = 0, miKind = Algebraic, uargs = UArgs, urules = URules, selector = Nothing, greedy = NoGreedy}}
        Proof:
          We first use the processor NaturalMI {miDimension = 1, miDegree = 0, miKind = Algebraic, uargs = UArgs, urules = URules, selector = Nothing, greedy = NoGreedy} to orient following rules strictly:
            1: g#(0(),x) -> c_3(g#(f(x,x),x)
                               ,f#(x,x))    
            
          The strictly oriented rules are moved into the weak component.
      *** 1.1.1.1.1.1.1.1 Progress [(?,O(1))]  ***
          Considered Problem:
            Strict DP Rules:
              g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
            Strict TRS Rules:
              
            Weak DP Rules:
              
            Weak TRS Rules:
              f(x,0()) -> s(0())
              f(s(x),s(y)) -> s(f(x,y))
            Signature:
              {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
            Obligation:
              Innermost
              basic terms: {f#,g#}/{0,s}
          Applied Processor:
            NaturalMI {miDimension = 1, miDegree = 0, miKind = Algebraic, uargs = UArgs, urules = URules, selector = Just first alternative for predecessorEstimation any intersect of rules of CDG leaf and strict-rules, greedy = NoGreedy}
          Proof:
            We apply a matrix interpretation of kind constructor based matrix interpretation (containing no more than 0 non-zero interpretation-entries in the diagonal of the component-wise maxima):
            The following argument positions are considered usable:
              uargs(c_3) = {1}
            
            Following symbols are considered usable:
              {f,f#,g#}
            TcT has computed the following interpretation:
                p(0) = [3]                  
                p(f) = [0]                  
                p(g) = [1] x1 + [1]         
                p(s) = [0]                  
               p(f#) = [2]                  
               p(g#) = [8] x1 + [4]         
              p(c_1) = [2]                  
              p(c_2) = [1]                  
              p(c_3) = [4] x1 + [4] x2 + [0]
            
            Following rules are strictly oriented:
            g#(0(),x) = [28]                     
                      > [24]                     
                      = c_3(g#(f(x,x),x),f#(x,x))
            
            
            Following rules are (at-least) weakly oriented:
                f(x,0()) =  [0]      
                         >= [0]      
                         =  s(0())   
            
            f(s(x),s(y)) =  [0]      
                         >= [0]      
                         =  s(f(x,y))
            
      *** 1.1.1.1.1.1.1.1.1 Progress [(?,O(1))]  ***
          Considered Problem:
            Strict DP Rules:
              
            Strict TRS Rules:
              
            Weak DP Rules:
              g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
            Weak TRS Rules:
              f(x,0()) -> s(0())
              f(s(x),s(y)) -> s(f(x,y))
            Signature:
              {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
            Obligation:
              Innermost
              basic terms: {f#,g#}/{0,s}
          Applied Processor:
            Assumption
          Proof:
            ()
      
      *** 1.1.1.1.1.1.1.2 Progress [(O(1),O(1))]  ***
          Considered Problem:
            Strict DP Rules:
              
            Strict TRS Rules:
              
            Weak DP Rules:
              g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
            Weak TRS Rules:
              f(x,0()) -> s(0())
              f(s(x),s(y)) -> s(f(x,y))
            Signature:
              {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
            Obligation:
              Innermost
              basic terms: {f#,g#}/{0,s}
          Applied Processor:
            RemoveWeakSuffixes
          Proof:
            Consider the dependency graph
              1:W:g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
                 -->_1 g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x)):1
              
            The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed.
              1: g#(0(),x) -> c_3(g#(f(x,x),x)
                                 ,f#(x,x))    
      *** 1.1.1.1.1.1.1.2.1 Progress [(O(1),O(1))]  ***
          Considered Problem:
            Strict DP Rules:
              
            Strict TRS Rules:
              
            Weak DP Rules:
              
            Weak TRS Rules:
              f(x,0()) -> s(0())
              f(s(x),s(y)) -> s(f(x,y))
            Signature:
              {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
            Obligation:
              Innermost
              basic terms: {f#,g#}/{0,s}
          Applied Processor:
            EmptyProcessor
          Proof:
            The problem is already closed. The intended complexity is O(1).
      
    *** 1.1.1.1.1.1.2 Progress [(?,O(n^1))]  ***
        Considered Problem:
          Strict DP Rules:
            f#(s(x),s(y)) -> c_2(f#(x,y))
          Strict TRS Rules:
            
          Weak DP Rules:
            g#(0(),x) -> f#(x,x)
            g#(0(),x) -> g#(f(x,x),x)
          Weak TRS Rules:
            f(x,0()) -> s(0())
            f(s(x),s(y)) -> s(f(x,y))
          Signature:
            {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
          Obligation:
            Innermost
            basic terms: {f#,g#}/{0,s}
        Applied Processor:
          PredecessorEstimationCP {onSelectionCP = any intersect of rules of CDG leaf and strict-rules, withComplexityPair = NaturalMI {miDimension = 1, miDegree = 1, miKind = Algebraic, uargs = UArgs, urules = URules, selector = Nothing, greedy = NoGreedy}}
        Proof:
          We first use the processor NaturalMI {miDimension = 1, miDegree = 1, miKind = Algebraic, uargs = UArgs, urules = URules, selector = Nothing, greedy = NoGreedy} to orient following rules strictly:
            1: f#(s(x),s(y)) -> c_2(f#(x,y))
            
          The strictly oriented rules are moved into the weak component.
      *** 1.1.1.1.1.1.2.1 Progress [(?,O(n^1))]  ***
          Considered Problem:
            Strict DP Rules:
              f#(s(x),s(y)) -> c_2(f#(x,y))
            Strict TRS Rules:
              
            Weak DP Rules:
              g#(0(),x) -> f#(x,x)
              g#(0(),x) -> g#(f(x,x),x)
            Weak TRS Rules:
              f(x,0()) -> s(0())
              f(s(x),s(y)) -> s(f(x,y))
            Signature:
              {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
            Obligation:
              Innermost
              basic terms: {f#,g#}/{0,s}
          Applied Processor:
            NaturalMI {miDimension = 1, miDegree = 1, miKind = Algebraic, uargs = UArgs, urules = URules, selector = Just first alternative for predecessorEstimation any intersect of rules of CDG leaf and strict-rules, greedy = NoGreedy}
          Proof:
            We apply a matrix interpretation of kind constructor based matrix interpretation:
            The following argument positions are considered usable:
              uargs(c_2) = {1}
            
            Following symbols are considered usable:
              {f#,g#}
            TcT has computed the following interpretation:
                p(0) = [0]                  
                p(f) = [4]                  
                p(g) = [1] x1 + [2] x2 + [0]
                p(s) = [1] x1 + [1]         
               p(f#) = [2] x2 + [0]         
               p(g#) = [5] x2 + [0]         
              p(c_1) = [0]                  
              p(c_2) = [1] x1 + [0]         
              p(c_3) = [4] x1 + [1] x2 + [0]
            
            Following rules are strictly oriented:
            f#(s(x),s(y)) = [2] y + [2] 
                          > [2] y + [0] 
                          = c_2(f#(x,y))
            
            
            Following rules are (at-least) weakly oriented:
            g#(0(),x) =  [5] x + [0] 
                      >= [2] x + [0] 
                      =  f#(x,x)     
            
            g#(0(),x) =  [5] x + [0] 
                      >= [5] x + [0] 
                      =  g#(f(x,x),x)
            
      *** 1.1.1.1.1.1.2.1.1 Progress [(?,O(1))]  ***
          Considered Problem:
            Strict DP Rules:
              
            Strict TRS Rules:
              
            Weak DP Rules:
              f#(s(x),s(y)) -> c_2(f#(x,y))
              g#(0(),x) -> f#(x,x)
              g#(0(),x) -> g#(f(x,x),x)
            Weak TRS Rules:
              f(x,0()) -> s(0())
              f(s(x),s(y)) -> s(f(x,y))
            Signature:
              {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
            Obligation:
              Innermost
              basic terms: {f#,g#}/{0,s}
          Applied Processor:
            Assumption
          Proof:
            ()
      
      *** 1.1.1.1.1.1.2.2 Progress [(O(1),O(1))]  ***
          Considered Problem:
            Strict DP Rules:
              
            Strict TRS Rules:
              
            Weak DP Rules:
              f#(s(x),s(y)) -> c_2(f#(x,y))
              g#(0(),x) -> f#(x,x)
              g#(0(),x) -> g#(f(x,x),x)
            Weak TRS Rules:
              f(x,0()) -> s(0())
              f(s(x),s(y)) -> s(f(x,y))
            Signature:
              {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
            Obligation:
              Innermost
              basic terms: {f#,g#}/{0,s}
          Applied Processor:
            RemoveWeakSuffixes
          Proof:
            Consider the dependency graph
              1:W:f#(s(x),s(y)) -> c_2(f#(x,y))
                 -->_1 f#(s(x),s(y)) -> c_2(f#(x,y)):1
              
              2:W:g#(0(),x) -> f#(x,x)
                 -->_1 f#(s(x),s(y)) -> c_2(f#(x,y)):1
              
              3:W:g#(0(),x) -> g#(f(x,x),x)
                 -->_1 g#(0(),x) -> g#(f(x,x),x):3
                 -->_1 g#(0(),x) -> f#(x,x):2
              
            The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed.
              3: g#(0(),x) -> g#(f(x,x),x)    
              2: g#(0(),x) -> f#(x,x)         
              1: f#(s(x),s(y)) -> c_2(f#(x,y))
      *** 1.1.1.1.1.1.2.2.1 Progress [(O(1),O(1))]  ***
          Considered Problem:
            Strict DP Rules:
              
            Strict TRS Rules:
              
            Weak DP Rules:
              
            Weak TRS Rules:
              f(x,0()) -> s(0())
              f(s(x),s(y)) -> s(f(x,y))
            Signature:
              {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
            Obligation:
              Innermost
              basic terms: {f#,g#}/{0,s}
          Applied Processor:
            EmptyProcessor
          Proof:
            The problem is already closed. The intended complexity is O(1).
      
  *** 1.1.1.1.1.2 Progress [(?,O(1))]  ***
      Considered Problem:
        Strict DP Rules:
          g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
        Strict TRS Rules:
          
        Weak DP Rules:
          f#(s(x),s(y)) -> c_2(f#(x,y))
        Weak TRS Rules:
          f(x,0()) -> s(0())
          f(s(x),s(y)) -> s(f(x,y))
        Signature:
          {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
        Obligation:
          Innermost
          basic terms: {f#,g#}/{0,s}
      Applied Processor:
        RemoveWeakSuffixes
      Proof:
        Consider the dependency graph
          1:S:g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
             -->_2 f#(s(x),s(y)) -> c_2(f#(x,y)):2
             -->_1 g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x)):1
          
          2:W:f#(s(x),s(y)) -> c_2(f#(x,y))
             -->_1 f#(s(x),s(y)) -> c_2(f#(x,y)):2
          
        The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed.
          2: f#(s(x),s(y)) -> c_2(f#(x,y))
  *** 1.1.1.1.1.2.1 Progress [(?,O(1))]  ***
      Considered Problem:
        Strict DP Rules:
          g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
        Strict TRS Rules:
          
        Weak DP Rules:
          
        Weak TRS Rules:
          f(x,0()) -> s(0())
          f(s(x),s(y)) -> s(f(x,y))
        Signature:
          {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/2}
        Obligation:
          Innermost
          basic terms: {f#,g#}/{0,s}
      Applied Processor:
        SimplifyRHS
      Proof:
        Consider the dependency graph
          1:S:g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x))
             -->_1 g#(0(),x) -> c_3(g#(f(x,x),x),f#(x,x)):1
          
        Due to missing edges in the depndency graph, the right-hand sides of following rules could be simplified:
          g#(0(),x) -> c_3(g#(f(x,x),x))
  *** 1.1.1.1.1.2.1.1 Progress [(?,O(1))]  ***
      Considered Problem:
        Strict DP Rules:
          g#(0(),x) -> c_3(g#(f(x,x),x))
        Strict TRS Rules:
          
        Weak DP Rules:
          
        Weak TRS Rules:
          f(x,0()) -> s(0())
          f(s(x),s(y)) -> s(f(x,y))
        Signature:
          {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/1}
        Obligation:
          Innermost
          basic terms: {f#,g#}/{0,s}
      Applied Processor:
        PredecessorEstimationCP {onSelectionCP = any intersect of rules of CDG leaf and strict-rules, withComplexityPair = NaturalMI {miDimension = 1, miDegree = 0, miKind = Algebraic, uargs = UArgs, urules = URules, selector = Nothing, greedy = NoGreedy}}
      Proof:
        We first use the processor NaturalMI {miDimension = 1, miDegree = 0, miKind = Algebraic, uargs = UArgs, urules = URules, selector = Nothing, greedy = NoGreedy} to orient following rules strictly:
          1: g#(0(),x) -> c_3(g#(f(x,x),x))
          
        The strictly oriented rules are moved into the weak component.
    *** 1.1.1.1.1.2.1.1.1 Progress [(?,O(1))]  ***
        Considered Problem:
          Strict DP Rules:
            g#(0(),x) -> c_3(g#(f(x,x),x))
          Strict TRS Rules:
            
          Weak DP Rules:
            
          Weak TRS Rules:
            f(x,0()) -> s(0())
            f(s(x),s(y)) -> s(f(x,y))
          Signature:
            {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/1}
          Obligation:
            Innermost
            basic terms: {f#,g#}/{0,s}
        Applied Processor:
          NaturalMI {miDimension = 1, miDegree = 0, miKind = Algebraic, uargs = UArgs, urules = URules, selector = Just first alternative for predecessorEstimation any intersect of rules of CDG leaf and strict-rules, greedy = NoGreedy}
        Proof:
          We apply a matrix interpretation of kind constructor based matrix interpretation (containing no more than 0 non-zero interpretation-entries in the diagonal of the component-wise maxima):
          The following argument positions are considered usable:
            uargs(c_3) = {1}
          
          Following symbols are considered usable:
            {f,f#,g#}
          TcT has computed the following interpretation:
              p(0) = [14]        
              p(f) = [0]         
              p(g) = [0]         
              p(s) = [0]         
             p(f#) = [1] x2 + [0]
             p(g#) = [1] x1 + [0]
            p(c_1) = [1]         
            p(c_2) = [2]         
            p(c_3) = [8] x1 + [6]
          
          Following rules are strictly oriented:
          g#(0(),x) = [14]             
                    > [6]              
                    = c_3(g#(f(x,x),x))
          
          
          Following rules are (at-least) weakly oriented:
              f(x,0()) =  [0]      
                       >= [0]      
                       =  s(0())   
          
          f(s(x),s(y)) =  [0]      
                       >= [0]      
                       =  s(f(x,y))
          
    *** 1.1.1.1.1.2.1.1.1.1 Progress [(?,O(1))]  ***
        Considered Problem:
          Strict DP Rules:
            
          Strict TRS Rules:
            
          Weak DP Rules:
            g#(0(),x) -> c_3(g#(f(x,x),x))
          Weak TRS Rules:
            f(x,0()) -> s(0())
            f(s(x),s(y)) -> s(f(x,y))
          Signature:
            {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/1}
          Obligation:
            Innermost
            basic terms: {f#,g#}/{0,s}
        Applied Processor:
          Assumption
        Proof:
          ()
    
    *** 1.1.1.1.1.2.1.1.2 Progress [(O(1),O(1))]  ***
        Considered Problem:
          Strict DP Rules:
            
          Strict TRS Rules:
            
          Weak DP Rules:
            g#(0(),x) -> c_3(g#(f(x,x),x))
          Weak TRS Rules:
            f(x,0()) -> s(0())
            f(s(x),s(y)) -> s(f(x,y))
          Signature:
            {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/1}
          Obligation:
            Innermost
            basic terms: {f#,g#}/{0,s}
        Applied Processor:
          RemoveWeakSuffixes
        Proof:
          Consider the dependency graph
            1:W:g#(0(),x) -> c_3(g#(f(x,x),x))
               -->_1 g#(0(),x) -> c_3(g#(f(x,x),x)):1
            
          The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed.
            1: g#(0(),x) -> c_3(g#(f(x,x),x))
    *** 1.1.1.1.1.2.1.1.2.1 Progress [(O(1),O(1))]  ***
        Considered Problem:
          Strict DP Rules:
            
          Strict TRS Rules:
            
          Weak DP Rules:
            
          Weak TRS Rules:
            f(x,0()) -> s(0())
            f(s(x),s(y)) -> s(f(x,y))
          Signature:
            {f/2,g/2,f#/2,g#/2} / {0/0,s/1,c_1/0,c_2/1,c_3/1}
          Obligation:
            Innermost
            basic terms: {f#,g#}/{0,s}
        Applied Processor:
          EmptyProcessor
        Proof:
          The problem is already closed. The intended complexity is O(1).