(0) Obligation:
Runtime Complexity TRS:
The TRS R consists of the following rules:
f(g(x), s(0), y) → f(y, y, g(x))
g(s(x)) → s(g(x))
g(0) → 0
Rewrite Strategy: INNERMOST
(1) CpxTrsToCdtProof (BOTH BOUNDS(ID, ID) transformation)
Converted Cpx (relative) TRS to CDT
(2) Obligation:
Complexity Dependency Tuples Problem
Rules:
f(g(z0), s(0), z1) → f(z1, z1, g(z0))
g(s(z0)) → s(g(z0))
g(0) → 0
Tuples:
F(g(z0), s(0), z1) → c(F(z1, z1, g(z0)), G(z0))
G(s(z0)) → c1(G(z0))
G(0) → c2
S tuples:
F(g(z0), s(0), z1) → c(F(z1, z1, g(z0)), G(z0))
G(s(z0)) → c1(G(z0))
G(0) → c2
K tuples:none
Defined Rule Symbols:
f, g
Defined Pair Symbols:
F, G
Compound Symbols:
c, c1, c2
(3) CdtLeafRemovalProof (ComplexityIfPolyImplication transformation)
Removed 1 leading nodes:
F(g(z0), s(0), z1) → c(F(z1, z1, g(z0)), G(z0))
Removed 1 trailing nodes:
G(0) → c2
(4) Obligation:
Complexity Dependency Tuples Problem
Rules:
f(g(z0), s(0), z1) → f(z1, z1, g(z0))
g(s(z0)) → s(g(z0))
g(0) → 0
Tuples:
G(s(z0)) → c1(G(z0))
S tuples:
G(s(z0)) → c1(G(z0))
K tuples:none
Defined Rule Symbols:
f, g
Defined Pair Symbols:
G
Compound Symbols:
c1
(5) CdtUsableRulesProof (EQUIVALENT transformation)
The following rules are not usable and were removed:
f(g(z0), s(0), z1) → f(z1, z1, g(z0))
g(s(z0)) → s(g(z0))
g(0) → 0
(6) Obligation:
Complexity Dependency Tuples Problem
Rules:none
Tuples:
G(s(z0)) → c1(G(z0))
S tuples:
G(s(z0)) → c1(G(z0))
K tuples:none
Defined Rule Symbols:none
Defined Pair Symbols:
G
Compound Symbols:
c1
(7) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1)) transformation)
Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.
G(s(z0)) → c1(G(z0))
We considered the (Usable) Rules:none
And the Tuples:
G(s(z0)) → c1(G(z0))
The order we found is given by the following interpretation:
Polynomial interpretation :
POL(G(x1)) = [5]x1
POL(c1(x1)) = x1
POL(s(x1)) = [1] + x1
(8) Obligation:
Complexity Dependency Tuples Problem
Rules:none
Tuples:
G(s(z0)) → c1(G(z0))
S tuples:none
K tuples:
G(s(z0)) → c1(G(z0))
Defined Rule Symbols:none
Defined Pair Symbols:
G
Compound Symbols:
c1
(9) SIsEmptyProof (BOTH BOUNDS(ID, ID) transformation)
The set S is empty
(10) BOUNDS(1, 1)