We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict Trs: { f(g(x), y, y) -> g(f(x, x, y)) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) We add the following weak dependency pairs: Strict DPs: { f^#(g(x), y, y) -> c_1(f^#(x, x, y)) } and mark the set of starting terms. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict DPs: { f^#(g(x), y, y) -> c_1(f^#(x, x, y)) } Strict Trs: { f(g(x), y, y) -> g(f(x, x, y)) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) No rule is usable, rules are removed from the input problem. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict DPs: { f^#(g(x), y, y) -> c_1(f^#(x, x, y)) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) The weightgap principle applies (using the following constant growth matrix-interpretation) The following argument positions are usable: Uargs(c_1) = {1} TcT has computed the following constructor-restricted matrix interpretation. [g](x1) = [1 0] x1 + [0] [0 1] [2] [f^#](x1, x2, x3) = [0 1] x1 + [0] [0 0] [0] [c_1](x1) = [1 0] x1 + [0] [0 1] [0] The order satisfies the following ordering constraints: [f^#(g(x), y, y)] = [0 1] x + [2] [0 0] [0] > [0 1] x + [0] [0 0] [0] = [c_1(f^#(x, x, y))] Further, it can be verified that all rules not oriented are covered by the weightgap condition. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(1)). Weak DPs: { f^#(g(x), y, y) -> c_1(f^#(x, x, y)) } Obligation: innermost runtime complexity Answer: YES(O(1),O(1)) The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed. { f^#(g(x), y, y) -> c_1(f^#(x, x, y)) } We are left with following problem, upon which TcT provides the certificate YES(O(1),O(1)). Rules: Empty Obligation: innermost runtime complexity Answer: YES(O(1),O(1)) Empty rules are trivially bounded Hurray, we answered YES(O(1),O(n^1))