*** 1 Progress [(O(1),O(1))] ***
Considered Problem:
Strict DP Rules:
Strict TRS Rules:
f(s(X),Y) -> h(s(f(h(Y),X)))
Weak DP Rules:
Weak TRS Rules:
Signature:
{f/2} / {h/1,s/1}
Obligation:
Innermost
basic terms: {f}/{h,s}
Applied Processor:
DependencyPairs {dpKind_ = DT}
Proof:
We add the following dependency tuples:
Strict DPs
f#(s(X),Y) -> c_1(f#(h(Y),X))
Weak DPs
and mark the set of starting terms.
*** 1.1 Progress [(O(1),O(1))] ***
Considered Problem:
Strict DP Rules:
f#(s(X),Y) -> c_1(f#(h(Y),X))
Strict TRS Rules:
Weak DP Rules:
Weak TRS Rules:
f(s(X),Y) -> h(s(f(h(Y),X)))
Signature:
{f/2,f#/2} / {h/1,s/1,c_1/1}
Obligation:
Innermost
basic terms: {f#}/{h,s}
Applied Processor:
UsableRules
Proof:
We replace rewrite rules by usable rules:
f#(s(X),Y) -> c_1(f#(h(Y),X))
*** 1.1.1 Progress [(O(1),O(1))] ***
Considered Problem:
Strict DP Rules:
f#(s(X),Y) -> c_1(f#(h(Y),X))
Strict TRS Rules:
Weak DP Rules:
Weak TRS Rules:
Signature:
{f/2,f#/2} / {h/1,s/1,c_1/1}
Obligation:
Innermost
basic terms: {f#}/{h,s}
Applied Processor:
Trivial
Proof:
Consider the dependency graph
1:S:f#(s(X),Y) -> c_1(f#(h(Y),X))
The dependency graph contains no loops, we remove all dependency pairs.
*** 1.1.1.1 Progress [(O(1),O(1))] ***
Considered Problem:
Strict DP Rules:
Strict TRS Rules:
Weak DP Rules:
Weak TRS Rules:
Signature:
{f/2,f#/2} / {h/1,s/1,c_1/1}
Obligation:
Innermost
basic terms: {f#}/{h,s}
Applied Processor:
EmptyProcessor
Proof:
The problem is already closed. The intended complexity is O(1).