We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^2)).

Strict Trs:
  { selects(x', revprefix, Cons(x, xs)) ->
    Cons(Cons(x', revapp(revprefix, Cons(x, xs))),
         selects(x, Cons(x', revprefix), xs))
  , selects(x, revprefix, Nil()) ->
    Cons(Cons(x, revapp(revprefix, Nil())), Nil())
  , revapp(Cons(x, xs), rest) -> revapp(xs, Cons(x, rest))
  , revapp(Nil(), rest) -> rest
  , select(Cons(x, xs)) -> selects(x, Nil(), xs)
  , select(Nil()) -> Nil() }
Obligation:
  innermost runtime complexity
Answer:
  YES(O(1),O(n^2))

We add the following weak dependency pairs:

Strict DPs:
  { selects^#(x', revprefix, Cons(x, xs)) ->
    c_1(revapp^#(revprefix, Cons(x, xs)),
        selects^#(x, Cons(x', revprefix), xs))
  , selects^#(x, revprefix, Nil()) -> c_2(revapp^#(revprefix, Nil()))
  , revapp^#(Cons(x, xs), rest) -> c_3(revapp^#(xs, Cons(x, rest)))
  , revapp^#(Nil(), rest) -> c_4()
  , select^#(Cons(x, xs)) -> c_5(selects^#(x, Nil(), xs))
  , select^#(Nil()) -> c_6() }

and mark the set of starting terms.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^2)).

Strict DPs:
  { selects^#(x', revprefix, Cons(x, xs)) ->
    c_1(revapp^#(revprefix, Cons(x, xs)),
        selects^#(x, Cons(x', revprefix), xs))
  , selects^#(x, revprefix, Nil()) -> c_2(revapp^#(revprefix, Nil()))
  , revapp^#(Cons(x, xs), rest) -> c_3(revapp^#(xs, Cons(x, rest)))
  , revapp^#(Nil(), rest) -> c_4()
  , select^#(Cons(x, xs)) -> c_5(selects^#(x, Nil(), xs))
  , select^#(Nil()) -> c_6() }
Strict Trs:
  { selects(x', revprefix, Cons(x, xs)) ->
    Cons(Cons(x', revapp(revprefix, Cons(x, xs))),
         selects(x, Cons(x', revprefix), xs))
  , selects(x, revprefix, Nil()) ->
    Cons(Cons(x, revapp(revprefix, Nil())), Nil())
  , revapp(Cons(x, xs), rest) -> revapp(xs, Cons(x, rest))
  , revapp(Nil(), rest) -> rest
  , select(Cons(x, xs)) -> selects(x, Nil(), xs)
  , select(Nil()) -> Nil() }
Obligation:
  innermost runtime complexity
Answer:
  YES(O(1),O(n^2))

No rule is usable, rules are removed from the input problem.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^2)).

Strict DPs:
  { selects^#(x', revprefix, Cons(x, xs)) ->
    c_1(revapp^#(revprefix, Cons(x, xs)),
        selects^#(x, Cons(x', revprefix), xs))
  , selects^#(x, revprefix, Nil()) -> c_2(revapp^#(revprefix, Nil()))
  , revapp^#(Cons(x, xs), rest) -> c_3(revapp^#(xs, Cons(x, rest)))
  , revapp^#(Nil(), rest) -> c_4()
  , select^#(Cons(x, xs)) -> c_5(selects^#(x, Nil(), xs))
  , select^#(Nil()) -> c_6() }
Obligation:
  innermost runtime complexity
Answer:
  YES(O(1),O(n^2))

The weightgap principle applies (using the following constant
growth matrix-interpretation)

The following argument positions are usable:
  Uargs(c_1) = {1, 2}, Uargs(c_2) = {1}, Uargs(c_3) = {1},
  Uargs(c_5) = {1}

TcT has computed the following constructor-restricted matrix
interpretation.

           [Cons](x1, x2) = [0]                      
                            [0]                      
                                                     
                    [Nil] = [0]                      
                            [0]                      
                                                     
  [selects^#](x1, x2, x3) = [0]                      
                            [0]                      
                                                     
            [c_1](x1, x2) = [1 0] x1 + [1 0] x2 + [0]
                            [0 1]      [0 1]      [0]
                                                     
       [revapp^#](x1, x2) = [0]                      
                            [0]                      
                                                     
                [c_2](x1) = [1 0] x1 + [0]           
                            [0 1]      [0]           
                                                     
                [c_3](x1) = [1 0] x1 + [0]           
                            [0 1]      [0]           
                                                     
                    [c_4] = [0]                      
                            [0]                      
                                                     
           [select^#](x1) = [1]                      
                            [0]                      
                                                     
                [c_5](x1) = [1 0] x1 + [0]           
                            [0 1]      [0]           
                                                     
                    [c_6] = [0]                      
                            [0]                      

The order satisfies the following ordering constraints:

  [selects^#(x', revprefix, Cons(x, xs))] =  [0]                                         
                                             [0]                                         
                                          >= [0]                                         
                                             [0]                                         
                                          =  [c_1(revapp^#(revprefix, Cons(x, xs)),      
                                                  selects^#(x, Cons(x', revprefix), xs))]
                                                                                         
         [selects^#(x, revprefix, Nil())] =  [0]                                         
                                             [0]                                         
                                          >= [0]                                         
                                             [0]                                         
                                          =  [c_2(revapp^#(revprefix, Nil()))]           
                                                                                         
            [revapp^#(Cons(x, xs), rest)] =  [0]                                         
                                             [0]                                         
                                          >= [0]                                         
                                             [0]                                         
                                          =  [c_3(revapp^#(xs, Cons(x, rest)))]          
                                                                                         
                  [revapp^#(Nil(), rest)] =  [0]                                         
                                             [0]                                         
                                          >= [0]                                         
                                             [0]                                         
                                          =  [c_4()]                                     
                                                                                         
                  [select^#(Cons(x, xs))] =  [1]                                         
                                             [0]                                         
                                          >  [0]                                         
                                             [0]                                         
                                          =  [c_5(selects^#(x, Nil(), xs))]              
                                                                                         
                        [select^#(Nil())] =  [1]                                         
                                             [0]                                         
                                          >  [0]                                         
                                             [0]                                         
                                          =  [c_6()]                                     
                                                                                         

Further, it can be verified that all rules not oriented are covered by the weightgap condition.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^2)).

Strict DPs:
  { selects^#(x', revprefix, Cons(x, xs)) ->
    c_1(revapp^#(revprefix, Cons(x, xs)),
        selects^#(x, Cons(x', revprefix), xs))
  , selects^#(x, revprefix, Nil()) -> c_2(revapp^#(revprefix, Nil()))
  , revapp^#(Cons(x, xs), rest) -> c_3(revapp^#(xs, Cons(x, rest)))
  , revapp^#(Nil(), rest) -> c_4() }
Weak DPs:
  { select^#(Cons(x, xs)) -> c_5(selects^#(x, Nil(), xs))
  , select^#(Nil()) -> c_6() }
Obligation:
  innermost runtime complexity
Answer:
  YES(O(1),O(n^2))

We estimate the number of application of {4} by applications of
Pre({4}) = {1,2,3}. Here rules are labeled as follows:

  DPs:
    { 1: selects^#(x', revprefix, Cons(x, xs)) ->
         c_1(revapp^#(revprefix, Cons(x, xs)),
             selects^#(x, Cons(x', revprefix), xs))
    , 2: selects^#(x, revprefix, Nil()) ->
         c_2(revapp^#(revprefix, Nil()))
    , 3: revapp^#(Cons(x, xs), rest) ->
         c_3(revapp^#(xs, Cons(x, rest)))
    , 4: revapp^#(Nil(), rest) -> c_4()
    , 5: select^#(Cons(x, xs)) -> c_5(selects^#(x, Nil(), xs))
    , 6: select^#(Nil()) -> c_6() }

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^2)).

Strict DPs:
  { selects^#(x', revprefix, Cons(x, xs)) ->
    c_1(revapp^#(revprefix, Cons(x, xs)),
        selects^#(x, Cons(x', revprefix), xs))
  , selects^#(x, revprefix, Nil()) -> c_2(revapp^#(revprefix, Nil()))
  , revapp^#(Cons(x, xs), rest) -> c_3(revapp^#(xs, Cons(x, rest))) }
Weak DPs:
  { revapp^#(Nil(), rest) -> c_4()
  , select^#(Cons(x, xs)) -> c_5(selects^#(x, Nil(), xs))
  , select^#(Nil()) -> c_6() }
Obligation:
  innermost runtime complexity
Answer:
  YES(O(1),O(n^2))

The following weak DPs constitute a sub-graph of the DG that is
closed under successors. The DPs are removed.

{ revapp^#(Nil(), rest) -> c_4()
, select^#(Nil()) -> c_6() }

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^2)).

Strict DPs:
  { selects^#(x', revprefix, Cons(x, xs)) ->
    c_1(revapp^#(revprefix, Cons(x, xs)),
        selects^#(x, Cons(x', revprefix), xs))
  , selects^#(x, revprefix, Nil()) -> c_2(revapp^#(revprefix, Nil()))
  , revapp^#(Cons(x, xs), rest) -> c_3(revapp^#(xs, Cons(x, rest))) }
Weak DPs: { select^#(Cons(x, xs)) -> c_5(selects^#(x, Nil(), xs)) }
Obligation:
  innermost runtime complexity
Answer:
  YES(O(1),O(n^2))

Consider the dependency graph

  1: selects^#(x', revprefix, Cons(x, xs)) ->
     c_1(revapp^#(revprefix, Cons(x, xs)),
         selects^#(x, Cons(x', revprefix), xs))
     -->_1 revapp^#(Cons(x, xs), rest) ->
           c_3(revapp^#(xs, Cons(x, rest))) :3
     -->_2 selects^#(x, revprefix, Nil()) ->
           c_2(revapp^#(revprefix, Nil())) :2
     -->_2 selects^#(x', revprefix, Cons(x, xs)) ->
           c_1(revapp^#(revprefix, Cons(x, xs)),
               selects^#(x, Cons(x', revprefix), xs)) :1
  
  2: selects^#(x, revprefix, Nil()) ->
     c_2(revapp^#(revprefix, Nil()))
     -->_1 revapp^#(Cons(x, xs), rest) ->
           c_3(revapp^#(xs, Cons(x, rest))) :3
  
  3: revapp^#(Cons(x, xs), rest) -> c_3(revapp^#(xs, Cons(x, rest)))
     -->_1 revapp^#(Cons(x, xs), rest) ->
           c_3(revapp^#(xs, Cons(x, rest))) :3
  
  4: select^#(Cons(x, xs)) -> c_5(selects^#(x, Nil(), xs))
     -->_1 selects^#(x, revprefix, Nil()) ->
           c_2(revapp^#(revprefix, Nil())) :2
     -->_1 selects^#(x', revprefix, Cons(x, xs)) ->
           c_1(revapp^#(revprefix, Cons(x, xs)),
               selects^#(x, Cons(x', revprefix), xs)) :1
  

Following roots of the dependency graph are removed, as the
considered set of starting terms is closed under reduction with
respect to these rules (modulo compound contexts).

  { select^#(Cons(x, xs)) -> c_5(selects^#(x, Nil(), xs)) }


We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^2)).

Strict DPs:
  { selects^#(x', revprefix, Cons(x, xs)) ->
    c_1(revapp^#(revprefix, Cons(x, xs)),
        selects^#(x, Cons(x', revprefix), xs))
  , selects^#(x, revprefix, Nil()) -> c_2(revapp^#(revprefix, Nil()))
  , revapp^#(Cons(x, xs), rest) -> c_3(revapp^#(xs, Cons(x, rest))) }
Obligation:
  innermost runtime complexity
Answer:
  YES(O(1),O(n^2))

We decompose the input problem according to the dependency graph
into the upper component

  { selects^#(x', revprefix, Cons(x, xs)) ->
    c_1(revapp^#(revprefix, Cons(x, xs)),
        selects^#(x, Cons(x', revprefix), xs)) }

and lower component

  { selects^#(x, revprefix, Nil()) -> c_2(revapp^#(revprefix, Nil()))
  , revapp^#(Cons(x, xs), rest) -> c_3(revapp^#(xs, Cons(x, rest))) }

Further, following extension rules are added to the lower
component.

{ selects^#(x', revprefix, Cons(x, xs)) ->
  selects^#(x, Cons(x', revprefix), xs)
, selects^#(x', revprefix, Cons(x, xs)) ->
  revapp^#(revprefix, Cons(x, xs)) }

TcT solves the upper component with certificate YES(O(1),O(n^1)).

Sub-proof:
----------
  We are left with following problem, upon which TcT provides the
  certificate YES(O(1),O(n^1)).
  
  Strict DPs:
    { selects^#(x', revprefix, Cons(x, xs)) ->
      c_1(revapp^#(revprefix, Cons(x, xs)),
          selects^#(x, Cons(x', revprefix), xs)) }
  Obligation:
    innermost runtime complexity
  Answer:
    YES(O(1),O(n^1))
  
  We use the processor 'Small Polynomial Path Order (PS,1-bounded)'
  to orient following rules strictly.
  
  DPs:
    { 1: selects^#(x', revprefix, Cons(x, xs)) ->
         c_1(revapp^#(revprefix, Cons(x, xs)),
             selects^#(x, Cons(x', revprefix), xs)) }
  
  Sub-proof:
  ----------
    The input was oriented with the instance of 'Small Polynomial Path
    Order (PS,1-bounded)' as induced by the safe mapping
    
     safe(Cons) = {1, 2}, safe(selects^#) = {1, 2}, safe(c_1) = {},
     safe(revapp^#) = {}
    
    and precedence
    
     empty .
    
    Following symbols are considered recursive:
    
     {selects^#}
    
    The recursion depth is 1.
    
    Further, following argument filtering is employed:
    
     pi(Cons) = [2], pi(selects^#) = [2, 3], pi(c_1) = [1, 2],
     pi(revapp^#) = []
    
    Usable defined function symbols are a subset of:
    
     {selects^#, revapp^#}
    
    For your convenience, here are the satisfied ordering constraints:
    
      pi(selects^#(x', revprefix, Cons(x, xs))) = selects^#(Cons(; xs); revprefix)                   
                                                > c_1(revapp^#(),  selects^#(xs; Cons(; revprefix));)
                                                = pi(c_1(revapp^#(revprefix, Cons(x, xs)),           
                                                         selects^#(x, Cons(x', revprefix), xs)))     
                                                                                                     
  
  The strictly oriented rules are moved into the weak component.
  
  We are left with following problem, upon which TcT provides the
  certificate YES(O(1),O(1)).
  
  Weak DPs:
    { selects^#(x', revprefix, Cons(x, xs)) ->
      c_1(revapp^#(revprefix, Cons(x, xs)),
          selects^#(x, Cons(x', revprefix), xs)) }
  Obligation:
    innermost runtime complexity
  Answer:
    YES(O(1),O(1))
  
  The following weak DPs constitute a sub-graph of the DG that is
  closed under successors. The DPs are removed.
  
  { selects^#(x', revprefix, Cons(x, xs)) ->
    c_1(revapp^#(revprefix, Cons(x, xs)),
        selects^#(x, Cons(x', revprefix), xs)) }
  
  We are left with following problem, upon which TcT provides the
  certificate YES(O(1),O(1)).
  
  Rules: Empty
  Obligation:
    innermost runtime complexity
  Answer:
    YES(O(1),O(1))
  
  Empty rules are trivially bounded

We return to the main proof.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict DPs:
  { selects^#(x, revprefix, Nil()) -> c_2(revapp^#(revprefix, Nil()))
  , revapp^#(Cons(x, xs), rest) -> c_3(revapp^#(xs, Cons(x, rest))) }
Weak DPs:
  { selects^#(x', revprefix, Cons(x, xs)) ->
    selects^#(x, Cons(x', revprefix), xs)
  , selects^#(x', revprefix, Cons(x, xs)) ->
    revapp^#(revprefix, Cons(x, xs)) }
Obligation:
  innermost runtime complexity
Answer:
  YES(O(1),O(n^1))

We use the processor 'matrix interpretation of dimension 1' to
orient following rules strictly.

DPs:
  { 2: revapp^#(Cons(x, xs), rest) ->
       c_3(revapp^#(xs, Cons(x, rest)))
  , 4: selects^#(x', revprefix, Cons(x, xs)) ->
       revapp^#(revprefix, Cons(x, xs)) }

Sub-proof:
----------
  The following argument positions are usable:
    Uargs(c_2) = {1}, Uargs(c_3) = {1}
  
  TcT has computed the following constructor-based matrix
  interpretation satisfying not(EDA).
  
             [Cons](x1, x2) = [1] x2 + [2]         
                                                   
                      [Nil] = [0]                  
                                                   
    [selects^#](x1, x2, x3) = [4] x2 + [4] x3 + [0]
                                                   
         [revapp^#](x1, x2) = [4] x1 + [0]         
                                                   
                  [c_2](x1) = [1] x1 + [0]         
                                                   
                  [c_3](x1) = [1] x1 + [7]         
  
  The order satisfies the following ordering constraints:
  
    [selects^#(x', revprefix, Cons(x, xs))] =  [4] revprefix + [4] xs + [8]           
                                            >= [4] revprefix + [4] xs + [8]           
                                            =  [selects^#(x, Cons(x', revprefix), xs)]
                                                                                      
    [selects^#(x', revprefix, Cons(x, xs))] =  [4] revprefix + [4] xs + [8]           
                                            >  [4] revprefix + [0]                    
                                            =  [revapp^#(revprefix, Cons(x, xs))]     
                                                                                      
           [selects^#(x, revprefix, Nil())] =  [4] revprefix + [0]                    
                                            >= [4] revprefix + [0]                    
                                            =  [c_2(revapp^#(revprefix, Nil()))]      
                                                                                      
              [revapp^#(Cons(x, xs), rest)] =  [4] xs + [8]                           
                                            >  [4] xs + [7]                           
                                            =  [c_3(revapp^#(xs, Cons(x, rest)))]     
                                                                                      

The strictly oriented rules are moved into the weak component.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(1)).

Strict DPs:
  { selects^#(x, revprefix, Nil()) ->
    c_2(revapp^#(revprefix, Nil())) }
Weak DPs:
  { selects^#(x', revprefix, Cons(x, xs)) ->
    selects^#(x, Cons(x', revprefix), xs)
  , selects^#(x', revprefix, Cons(x, xs)) ->
    revapp^#(revprefix, Cons(x, xs))
  , revapp^#(Cons(x, xs), rest) -> c_3(revapp^#(xs, Cons(x, rest))) }
Obligation:
  innermost runtime complexity
Answer:
  YES(O(1),O(1))

The following weak DPs constitute a sub-graph of the DG that is
closed under successors. The DPs are removed.

{ selects^#(x', revprefix, Cons(x, xs)) ->
  revapp^#(revprefix, Cons(x, xs))
, revapp^#(Cons(x, xs), rest) -> c_3(revapp^#(xs, Cons(x, rest))) }

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(1)).

Strict DPs:
  { selects^#(x, revprefix, Nil()) ->
    c_2(revapp^#(revprefix, Nil())) }
Weak DPs:
  { selects^#(x', revprefix, Cons(x, xs)) ->
    selects^#(x, Cons(x', revprefix), xs) }
Obligation:
  innermost runtime complexity
Answer:
  YES(O(1),O(1))

Due to missing edges in the dependency-graph, the right-hand sides
of following rules could be simplified:

  { selects^#(x, revprefix, Nil()) ->
    c_2(revapp^#(revprefix, Nil())) }

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(1)).

Strict DPs: { selects^#(x, revprefix, Nil()) -> c_1() }
Weak DPs:
  { selects^#(x', revprefix, Cons(x, xs)) ->
    c_2(selects^#(x, Cons(x', revprefix), xs)) }
Obligation:
  innermost runtime complexity
Answer:
  YES(O(1),O(1))

We use the processor 'matrix interpretation of dimension 1' to
orient following rules strictly.

DPs:
  { 1: selects^#(x, revprefix, Nil()) -> c_1() }

Sub-proof:
----------
  The following argument positions are usable:
    Uargs(c_2) = {1}
  
  TcT has computed the following constructor-restricted matrix
  interpretation. Note that the diagonal of the component-wise maxima
  of interpretation-entries (of constructors) contains no more than 0
  non-zero entries.
  
             [Cons](x1, x2) = [0]         
                                          
                      [Nil] = [0]         
                                          
    [selects^#](x1, x2, x3) = [1] x2 + [1]
                                          
         [revapp^#](x1, x2) = [0]         
                                          
                  [c_2](x1) = [0]         
                                          
                  [c_3](x1) = [0]         
                                          
                        [c] = [0]         
                                          
                      [c_1] = [0]         
                                          
                  [c_2](x1) = [1] x1 + [0]
  
  The order satisfies the following ordering constraints:
  
    [selects^#(x', revprefix, Cons(x, xs))] =  [1] revprefix + [1]                         
                                            >= [1]                                         
                                            =  [c_2(selects^#(x, Cons(x', revprefix), xs))]
                                                                                           
           [selects^#(x, revprefix, Nil())] =  [1] revprefix + [1]                         
                                            >  [0]                                         
                                            =  [c_1()]                                     
                                                                                           

The strictly oriented rules are moved into the weak component.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(1)).

Weak DPs:
  { selects^#(x', revprefix, Cons(x, xs)) ->
    c_2(selects^#(x, Cons(x', revprefix), xs))
  , selects^#(x, revprefix, Nil()) -> c_1() }
Obligation:
  innermost runtime complexity
Answer:
  YES(O(1),O(1))

The following weak DPs constitute a sub-graph of the DG that is
closed under successors. The DPs are removed.

{ selects^#(x', revprefix, Cons(x, xs)) ->
  c_2(selects^#(x, Cons(x', revprefix), xs))
, selects^#(x, revprefix, Nil()) -> c_1() }

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(1)).

Rules: Empty
Obligation:
  innermost runtime complexity
Answer:
  YES(O(1),O(1))

Empty rules are trivially bounded

Hurray, we answered YES(O(1),O(n^2))