We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).
Strict Trs: { *(x, +(y, z)) -> +(*(x, y), *(x, z)) }
Obligation:
innermost runtime complexity
Answer:
YES(O(1),O(n^1))
We add the following weak dependency pairs:
Strict DPs: { *^#(x, +(y, z)) -> c_1(*^#(x, y), *^#(x, z)) }
and mark the set of starting terms.
We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).
Strict DPs: { *^#(x, +(y, z)) -> c_1(*^#(x, y), *^#(x, z)) }
Strict Trs: { *(x, +(y, z)) -> +(*(x, y), *(x, z)) }
Obligation:
innermost runtime complexity
Answer:
YES(O(1),O(n^1))
No rule is usable, rules are removed from the input problem.
We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).
Strict DPs: { *^#(x, +(y, z)) -> c_1(*^#(x, y), *^#(x, z)) }
Obligation:
innermost runtime complexity
Answer:
YES(O(1),O(n^1))
The weightgap principle applies (using the following constant
growth matrix-interpretation)
The following argument positions are usable:
Uargs(c_1) = {1, 2}
TcT has computed the following constructor-restricted matrix
interpretation.
[+](x1, x2) = [1 0] x1 + [1 0] x2 + [1]
[0 0] [0 0] [0]
[*^#](x1, x2) = [1 0] x2 + [0]
[0 0] [0]
[c_1](x1, x2) = [1 0] x1 + [1 0] x2 + [0]
[0 1] [0 1] [0]
The order satisfies the following ordering constraints:
[*^#(x, +(y, z))] = [1 0] y + [1 0] z + [1]
[0 0] [0 0] [0]
> [1 0] y + [1 0] z + [0]
[0 0] [0 0] [0]
= [c_1(*^#(x, y), *^#(x, z))]
Further, it can be verified that all rules not oriented are covered by the weightgap condition.
We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(1)).
Weak DPs: { *^#(x, +(y, z)) -> c_1(*^#(x, y), *^#(x, z)) }
Obligation:
innermost runtime complexity
Answer:
YES(O(1),O(1))
The following weak DPs constitute a sub-graph of the DG that is
closed under successors. The DPs are removed.
{ *^#(x, +(y, z)) -> c_1(*^#(x, y), *^#(x, z)) }
We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(1)).
Rules: Empty
Obligation:
innermost runtime complexity
Answer:
YES(O(1),O(1))
Empty rules are trivially bounded
Hurray, we answered YES(O(1),O(n^1))