*** 1 Progress [(O(1),O(n^1))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: active(f(x)) -> f(active(x)) active(f(x)) -> mark(x) check(x) -> start(match(f(X()),x)) check(f(x)) -> f(check(x)) f(found(x)) -> found(f(x)) f(mark(x)) -> mark(f(x)) f(ok(x)) -> ok(f(x)) match(X(),x) -> proper(x) match(f(x),f(y)) -> f(match(x,y)) proper(c()) -> ok(c()) proper(f(x)) -> f(proper(x)) start(ok(x)) -> found(x) top(active(c())) -> top(mark(c())) top(found(x)) -> top(active(x)) top(mark(x)) -> top(check(x)) Weak DP Rules: Weak TRS Rules: Signature: {active/1,check/1,f/1,match/2,proper/1,start/1,top/1} / {X/0,c/0,found/1,mark/1,ok/1} Obligation: Innermost basic terms: {active,check,f,match,proper,start,top}/{X,c,found,mark,ok} Applied Processor: Bounds {initialAutomaton = perSymbol, enrichment = match} Proof: The problem is match-bounded by 3. The enriched problem is compatible with follwoing automaton. X_0() -> 1 X_1() -> 15 X_2() -> 21 X_3() -> 25 active_0(1) -> 2 active_0(3) -> 2 active_0(6) -> 2 active_0(7) -> 2 active_0(9) -> 2 active_1(1) -> 18 active_1(3) -> 18 active_1(6) -> 18 active_1(7) -> 18 active_1(9) -> 18 c_0() -> 3 c_1() -> 17 check_0(1) -> 4 check_0(3) -> 4 check_0(6) -> 4 check_0(7) -> 4 check_0(9) -> 4 check_1(1) -> 18 check_1(3) -> 18 check_1(6) -> 18 check_1(7) -> 18 check_1(9) -> 18 check_2(17) -> 22 f_0(1) -> 5 f_0(3) -> 5 f_0(6) -> 5 f_0(7) -> 5 f_0(9) -> 5 f_1(1) -> 16 f_1(3) -> 16 f_1(6) -> 16 f_1(7) -> 16 f_1(9) -> 16 f_1(15) -> 14 f_2(21) -> 20 f_3(25) -> 24 found_0(1) -> 6 found_0(3) -> 6 found_0(6) -> 6 found_0(7) -> 6 found_0(9) -> 6 found_1(1) -> 11 found_1(3) -> 11 found_1(6) -> 11 found_1(7) -> 11 found_1(9) -> 11 found_1(16) -> 5 found_1(16) -> 16 mark_0(1) -> 7 mark_0(3) -> 7 mark_0(6) -> 7 mark_0(7) -> 7 mark_0(9) -> 7 mark_1(16) -> 5 mark_1(16) -> 16 mark_1(17) -> 18 match_0(1,1) -> 8 match_0(1,3) -> 8 match_0(1,6) -> 8 match_0(1,7) -> 8 match_0(1,9) -> 8 match_0(3,1) -> 8 match_0(3,3) -> 8 match_0(3,6) -> 8 match_0(3,7) -> 8 match_0(3,9) -> 8 match_0(6,1) -> 8 match_0(6,3) -> 8 match_0(6,6) -> 8 match_0(6,7) -> 8 match_0(6,9) -> 8 match_0(7,1) -> 8 match_0(7,3) -> 8 match_0(7,6) -> 8 match_0(7,7) -> 8 match_0(7,9) -> 8 match_0(9,1) -> 8 match_0(9,3) -> 8 match_0(9,6) -> 8 match_0(9,7) -> 8 match_0(9,9) -> 8 match_1(14,1) -> 13 match_1(14,3) -> 13 match_1(14,6) -> 13 match_1(14,7) -> 13 match_1(14,9) -> 13 match_2(20,1) -> 19 match_2(20,3) -> 19 match_2(20,6) -> 19 match_2(20,7) -> 19 match_2(20,9) -> 19 match_3(24,17) -> 23 ok_0(1) -> 9 ok_0(3) -> 9 ok_0(6) -> 9 ok_0(7) -> 9 ok_0(9) -> 9 ok_1(16) -> 5 ok_1(16) -> 16 ok_1(17) -> 8 ok_1(17) -> 10 proper_0(1) -> 10 proper_0(3) -> 10 proper_0(6) -> 10 proper_0(7) -> 10 proper_0(9) -> 10 proper_1(1) -> 8 proper_1(3) -> 8 proper_1(6) -> 8 proper_1(7) -> 8 proper_1(9) -> 8 start_0(1) -> 11 start_0(3) -> 11 start_0(6) -> 11 start_0(7) -> 11 start_0(9) -> 11 start_1(13) -> 4 start_2(19) -> 18 start_3(23) -> 22 top_0(1) -> 12 top_0(3) -> 12 top_0(6) -> 12 top_0(7) -> 12 top_0(9) -> 12 top_1(18) -> 12 top_2(22) -> 12 *** 1.1 Progress [(O(1),O(1))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: Weak DP Rules: Weak TRS Rules: active(f(x)) -> f(active(x)) active(f(x)) -> mark(x) check(x) -> start(match(f(X()),x)) check(f(x)) -> f(check(x)) f(found(x)) -> found(f(x)) f(mark(x)) -> mark(f(x)) f(ok(x)) -> ok(f(x)) match(X(),x) -> proper(x) match(f(x),f(y)) -> f(match(x,y)) proper(c()) -> ok(c()) proper(f(x)) -> f(proper(x)) start(ok(x)) -> found(x) top(active(c())) -> top(mark(c())) top(found(x)) -> top(active(x)) top(mark(x)) -> top(check(x)) Signature: {active/1,check/1,f/1,match/2,proper/1,start/1,top/1} / {X/0,c/0,found/1,mark/1,ok/1} Obligation: Innermost basic terms: {active,check,f,match,proper,start,top}/{X,c,found,mark,ok} Applied Processor: EmptyProcessor Proof: The problem is already closed. The intended complexity is O(1).