*** 1 Progress [(O(1),O(n^1))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: f(x,y,s(z)) -> s(f(0(),1(),z)) f(0(),1(),x) -> f(s(x),x,x) Weak DP Rules: Weak TRS Rules: Signature: {f/3} / {0/0,1/0,s/1} Obligation: Innermost basic terms: {f}/{0,1,s} Applied Processor: WeightGap {wgDimension = 1, wgDegree = 1, wgKind = Algebraic, wgUArgs = UArgs, wgOn = WgOnAny} Proof: The weightgap principle applies using the following nonconstant growth matrix-interpretation: We apply a matrix interpretation of kind constructor based matrix interpretation: The following argument positions are considered usable: uargs(s) = {1} Following symbols are considered usable: {} TcT has computed the following interpretation: p(0) = [1] p(1) = [1] p(f) = [8] x3 + [14] p(s) = [1] x1 + [2] Following rules are strictly oriented: f(x,y,s(z)) = [8] z + [30] > [8] z + [16] = s(f(0(),1(),z)) Following rules are (at-least) weakly oriented: f(0(),1(),x) = [8] x + [14] >= [8] x + [14] = f(s(x),x,x) Further, it can be verified that all rules not oriented are covered by the weightgap condition. *** 1.1 Progress [(O(1),O(n^1))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: f(0(),1(),x) -> f(s(x),x,x) Weak DP Rules: Weak TRS Rules: f(x,y,s(z)) -> s(f(0(),1(),z)) Signature: {f/3} / {0/0,1/0,s/1} Obligation: Innermost basic terms: {f}/{0,1,s} Applied Processor: NaturalMI {miDimension = 2, miDegree = 1, miKind = Algebraic, uargs = UArgs, urules = URules, selector = Just any strict-rules, greedy = NoGreedy} Proof: We apply a matrix interpretation of kind constructor based matrix interpretation (containing no more than 1 non-zero interpretation-entries in the diagonal of the component-wise maxima): The following argument positions are considered usable: uargs(s) = {1} Following symbols are considered usable: {f} TcT has computed the following interpretation: p(0) = [1] [2] p(1) = [0] [4] p(f) = [0 4] x1 + [5 4] x3 + [1] [0 0] [0 0] [8] p(s) = [1 2] x1 + [5] [0 0] [1] Following rules are strictly oriented: f(0(),1(),x) = [5 4] x + [9] [0 0] [8] > [5 4] x + [5] [0 0] [8] = f(s(x),x,x) Following rules are (at-least) weakly oriented: f(x,y,s(z)) = [0 4] x + [5 10] z + [30] [0 0] [0 0] [8] >= [5 4] z + [30] [0 0] [1] = s(f(0(),1(),z)) *** 1.1.1 Progress [(O(1),O(1))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: Weak DP Rules: Weak TRS Rules: f(x,y,s(z)) -> s(f(0(),1(),z)) f(0(),1(),x) -> f(s(x),x,x) Signature: {f/3} / {0/0,1/0,s/1} Obligation: Innermost basic terms: {f}/{0,1,s} Applied Processor: EmptyProcessor Proof: The problem is already closed. The intended complexity is O(1).