*** 1 Progress [(O(1),O(1))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: f(s(x),y,y) -> f(y,x,s(x)) Weak DP Rules: Weak TRS Rules: Signature: {f/3} / {s/1} Obligation: Innermost basic terms: {f}/{s} Applied Processor: DependencyPairs {dpKind_ = DT} Proof: We add the following dependency tuples: Strict DPs f#(s(x),y,y) -> c_1(f#(y,x,s(x))) Weak DPs and mark the set of starting terms. *** 1.1 Progress [(O(1),O(1))] *** Considered Problem: Strict DP Rules: f#(s(x),y,y) -> c_1(f#(y,x,s(x))) Strict TRS Rules: Weak DP Rules: Weak TRS Rules: f(s(x),y,y) -> f(y,x,s(x)) Signature: {f/3,f#/3} / {s/1,c_1/1} Obligation: Innermost basic terms: {f#}/{s} Applied Processor: UsableRules Proof: We replace rewrite rules by usable rules: f#(s(x),y,y) -> c_1(f#(y,x,s(x))) *** 1.1.1 Progress [(O(1),O(1))] *** Considered Problem: Strict DP Rules: f#(s(x),y,y) -> c_1(f#(y,x,s(x))) Strict TRS Rules: Weak DP Rules: Weak TRS Rules: Signature: {f/3,f#/3} / {s/1,c_1/1} Obligation: Innermost basic terms: {f#}/{s} Applied Processor: Trivial Proof: Consider the dependency graph 1:S:f#(s(x),y,y) -> c_1(f#(y,x,s(x))) The dependency graph contains no loops, we remove all dependency pairs. *** 1.1.1.1 Progress [(O(1),O(1))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: Weak DP Rules: Weak TRS Rules: Signature: {f/3,f#/3} / {s/1,c_1/1} Obligation: Innermost basic terms: {f#}/{s} Applied Processor: EmptyProcessor Proof: The problem is already closed. The intended complexity is O(1).