We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict Trs: { f(0(), y) -> 0() , f(s(x), y) -> f(f(x, y), y) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) We add the following weak dependency pairs: Strict DPs: { f^#(0(), y) -> c_1() , f^#(s(x), y) -> c_2(f^#(f(x, y), y)) } and mark the set of starting terms. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict DPs: { f^#(0(), y) -> c_1() , f^#(s(x), y) -> c_2(f^#(f(x, y), y)) } Strict Trs: { f(0(), y) -> 0() , f(s(x), y) -> f(f(x, y), y) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) The weightgap principle applies (using the following constant growth matrix-interpretation) The following argument positions are usable: Uargs(f) = {1}, Uargs(f^#) = {1}, Uargs(c_2) = {1} TcT has computed the following constructor-restricted matrix interpretation. [f](x1, x2) = [1 1] x1 + [0] [0 0] [1] [0] = [0] [1] [s](x1) = [1 0] x1 + [2] [0 1] [2] [f^#](x1, x2) = [1 1] x1 + [0] [0 0] [0] [c_1] = [0] [0] [c_2](x1) = [1 0] x1 + [0] [0 1] [0] The order satisfies the following ordering constraints: [f(0(), y)] = [1] [1] > [0] [1] = [0()] [f(s(x), y)] = [1 1] x + [4] [0 0] [1] > [1 1] x + [1] [0 0] [1] = [f(f(x, y), y)] [f^#(0(), y)] = [1] [0] > [0] [0] = [c_1()] [f^#(s(x), y)] = [1 1] x + [4] [0 0] [0] > [1 1] x + [1] [0 0] [0] = [c_2(f^#(f(x, y), y))] Further, it can be verified that all rules not oriented are covered by the weightgap condition. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(1)). Weak DPs: { f^#(0(), y) -> c_1() , f^#(s(x), y) -> c_2(f^#(f(x, y), y)) } Weak Trs: { f(0(), y) -> 0() , f(s(x), y) -> f(f(x, y), y) } Obligation: innermost runtime complexity Answer: YES(O(1),O(1)) The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed. { f^#(0(), y) -> c_1() , f^#(s(x), y) -> c_2(f^#(f(x, y), y)) } We are left with following problem, upon which TcT provides the certificate YES(O(1),O(1)). Weak Trs: { f(0(), y) -> 0() , f(s(x), y) -> f(f(x, y), y) } Obligation: innermost runtime complexity Answer: YES(O(1),O(1)) No rule is usable, rules are removed from the input problem. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(1)). Rules: Empty Obligation: innermost runtime complexity Answer: YES(O(1),O(1)) Empty rules are trivially bounded Hurray, we answered YES(O(1),O(n^1))