*** 1 Progress [(?,O(n^1))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: f(g(x),s(0())) -> f(g(x),g(x)) g(0()) -> 0() g(s(x)) -> s(g(x)) Weak DP Rules: Weak TRS Rules: Signature: {f/2,g/1} / {0/0,s/1} Obligation: Full basic terms: {f,g}/{0,s} Applied Processor: DependencyPairs {dpKind_ = WIDP} Proof: We add the following weak dependency pairs: Strict DPs f#(g(x),s(0())) -> c_1(f#(g(x),g(x))) g#(0()) -> c_2() g#(s(x)) -> c_3(g#(x)) Weak DPs and mark the set of starting terms. *** 1.1 Progress [(?,O(n^1))] *** Considered Problem: Strict DP Rules: f#(g(x),s(0())) -> c_1(f#(g(x),g(x))) g#(0()) -> c_2() g#(s(x)) -> c_3(g#(x)) Strict TRS Rules: f(g(x),s(0())) -> f(g(x),g(x)) g(0()) -> 0() g(s(x)) -> s(g(x)) Weak DP Rules: Weak TRS Rules: Signature: {f/2,g/1,f#/2,g#/1} / {0/0,s/1,c_1/1,c_2/0,c_3/1} Obligation: Full basic terms: {f#,g#}/{0,s} Applied Processor: UsableRules Proof: We replace rewrite rules by usable rules: g#(0()) -> c_2() g#(s(x)) -> c_3(g#(x)) *** 1.1.1 Progress [(?,O(n^1))] *** Considered Problem: Strict DP Rules: g#(0()) -> c_2() g#(s(x)) -> c_3(g#(x)) Strict TRS Rules: Weak DP Rules: Weak TRS Rules: Signature: {f/2,g/1,f#/2,g#/1} / {0/0,s/1,c_1/1,c_2/0,c_3/1} Obligation: Full basic terms: {f#,g#}/{0,s} Applied Processor: Succeeding Proof: () *** 1.1.1.1 Progress [(?,O(n^1))] *** Considered Problem: Strict DP Rules: g#(0()) -> c_2() g#(s(x)) -> c_3(g#(x)) Strict TRS Rules: Weak DP Rules: Weak TRS Rules: Signature: {f/2,g/1,f#/2,g#/1} / {0/0,s/1,c_1/1,c_2/0,c_3/1} Obligation: Full basic terms: {f#,g#}/{0,s} Applied Processor: PredecessorEstimation {onSelection = all simple predecessor estimation selector} Proof: We estimate the number of application of {1} by application of Pre({1}) = {2}. Here rules are labelled as follows: 1: g#(0()) -> c_2() 2: g#(s(x)) -> c_3(g#(x)) *** 1.1.1.1.1 Progress [(?,O(n^1))] *** Considered Problem: Strict DP Rules: g#(s(x)) -> c_3(g#(x)) Strict TRS Rules: Weak DP Rules: g#(0()) -> c_2() Weak TRS Rules: Signature: {f/2,g/1,f#/2,g#/1} / {0/0,s/1,c_1/1,c_2/0,c_3/1} Obligation: Full basic terms: {f#,g#}/{0,s} Applied Processor: RemoveWeakSuffixes Proof: Consider the dependency graph 1:S:g#(s(x)) -> c_3(g#(x)) -->_1 g#(0()) -> c_2():2 -->_1 g#(s(x)) -> c_3(g#(x)):1 2:W:g#(0()) -> c_2() The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed. 2: g#(0()) -> c_2() *** 1.1.1.1.1.1 Progress [(?,O(n^1))] *** Considered Problem: Strict DP Rules: g#(s(x)) -> c_3(g#(x)) Strict TRS Rules: Weak DP Rules: Weak TRS Rules: Signature: {f/2,g/1,f#/2,g#/1} / {0/0,s/1,c_1/1,c_2/0,c_3/1} Obligation: Full basic terms: {f#,g#}/{0,s} Applied Processor: PredecessorEstimationCP {onSelectionCP = any intersect of rules of CDG leaf and strict-rules, withComplexityPair = NaturalMI {miDimension = 1, miDegree = 1, miKind = Algebraic, uargs = UArgs, urules = URules, selector = Nothing, greedy = NoGreedy}} Proof: We first use the processor NaturalMI {miDimension = 1, miDegree = 1, miKind = Algebraic, uargs = UArgs, urules = URules, selector = Nothing, greedy = NoGreedy} to orient following rules strictly: 1: g#(s(x)) -> c_3(g#(x)) The strictly oriented rules are moved into the weak component. *** 1.1.1.1.1.1.1 Progress [(?,O(n^1))] *** Considered Problem: Strict DP Rules: g#(s(x)) -> c_3(g#(x)) Strict TRS Rules: Weak DP Rules: Weak TRS Rules: Signature: {f/2,g/1,f#/2,g#/1} / {0/0,s/1,c_1/1,c_2/0,c_3/1} Obligation: Full basic terms: {f#,g#}/{0,s} Applied Processor: NaturalMI {miDimension = 1, miDegree = 1, miKind = Algebraic, uargs = UArgs, urules = URules, selector = Just first alternative for predecessorEstimation any intersect of rules of CDG leaf and strict-rules, greedy = NoGreedy} Proof: We apply a matrix interpretation of kind constructor based matrix interpretation: The following argument positions are considered usable: uargs(c_3) = {1} Following symbols are considered usable: {} TcT has computed the following interpretation: p(0) = [0] p(f) = [2] x2 + [1] p(g) = [8] x1 + [1] p(s) = [1] x1 + [8] p(f#) = [1] x1 + [1] x2 + [0] p(g#) = [1] x1 + [8] p(c_1) = [2] x1 + [1] p(c_2) = [1] p(c_3) = [1] x1 + [7] Following rules are strictly oriented: g#(s(x)) = [1] x + [16] > [1] x + [15] = c_3(g#(x)) Following rules are (at-least) weakly oriented: *** 1.1.1.1.1.1.1.1 Progress [(?,O(1))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: Weak DP Rules: g#(s(x)) -> c_3(g#(x)) Weak TRS Rules: Signature: {f/2,g/1,f#/2,g#/1} / {0/0,s/1,c_1/1,c_2/0,c_3/1} Obligation: Full basic terms: {f#,g#}/{0,s} Applied Processor: Assumption Proof: () *** 1.1.1.1.1.1.2 Progress [(O(1),O(1))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: Weak DP Rules: g#(s(x)) -> c_3(g#(x)) Weak TRS Rules: Signature: {f/2,g/1,f#/2,g#/1} / {0/0,s/1,c_1/1,c_2/0,c_3/1} Obligation: Full basic terms: {f#,g#}/{0,s} Applied Processor: RemoveWeakSuffixes Proof: Consider the dependency graph 1:W:g#(s(x)) -> c_3(g#(x)) -->_1 g#(s(x)) -> c_3(g#(x)):1 The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed. 1: g#(s(x)) -> c_3(g#(x)) *** 1.1.1.1.1.1.2.1 Progress [(O(1),O(1))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: Weak DP Rules: Weak TRS Rules: Signature: {f/2,g/1,f#/2,g#/1} / {0/0,s/1,c_1/1,c_2/0,c_3/1} Obligation: Full basic terms: {f#,g#}/{0,s} Applied Processor: EmptyProcessor Proof: The problem is already closed. The intended complexity is O(1).