*** 1 Progress [(O(1),O(n^1))]  ***
    Considered Problem:
      Strict DP Rules:
        
      Strict TRS Rules:
        ++(x,++(y,z)) -> ++(++(x,y),z)
        ++(x,nil()) -> x
        ++(.(x,y),z) -> .(x,++(y,z))
        ++(nil(),y) -> y
        make(x) -> .(x,nil())
        rev(++(x,y)) -> ++(rev(y),rev(x))
        rev(nil()) -> nil()
        rev(rev(x)) -> x
      Weak DP Rules:
        
      Weak TRS Rules:
        
      Signature:
        {++/2,make/1,rev/1} / {./2,nil/0}
      Obligation:
        Full
        basic terms: {++,make,rev}/{.,nil}
    Applied Processor:
      Bounds {initialAutomaton = perSymbol, enrichment = match}
    Proof:
      The problem is match-bounded by 1.
      The enriched problem is compatible with follwoing automaton.
        ++_0(2,2) -> 1
        ++_0(2,4) -> 1
        ++_0(4,2) -> 1
        ++_0(4,4) -> 1
        ++_1(2,2) -> 6
        ++_1(2,4) -> 6
        ++_1(4,2) -> 6
        ++_1(4,4) -> 6
        ._0(2,2) -> 1
        ._0(2,2) -> 2
        ._0(2,2) -> 6
        ._0(2,4) -> 1
        ._0(2,4) -> 2
        ._0(2,4) -> 6
        ._0(4,2) -> 1
        ._0(4,2) -> 2
        ._0(4,2) -> 6
        ._0(4,4) -> 1
        ._0(4,4) -> 2
        ._0(4,4) -> 6
        ._1(2,6) -> 1
        ._1(2,6) -> 6
        ._1(2,7) -> 3
        ._1(4,6) -> 1
        ._1(4,6) -> 6
        ._1(4,7) -> 3
        make_0(2) -> 3
        make_0(4) -> 3
        nil_0() -> 1
        nil_0() -> 4
        nil_0() -> 6
        nil_1() -> 5
        nil_1() -> 7
        rev_0(2) -> 5
        rev_0(4) -> 5
        2 -> 1
        2 -> 6
        4 -> 1
        4 -> 6
*** 1.1 Progress [(O(1),O(1))]  ***
    Considered Problem:
      Strict DP Rules:
        
      Strict TRS Rules:
        
      Weak DP Rules:
        
      Weak TRS Rules:
        ++(x,++(y,z)) -> ++(++(x,y),z)
        ++(x,nil()) -> x
        ++(.(x,y),z) -> .(x,++(y,z))
        ++(nil(),y) -> y
        make(x) -> .(x,nil())
        rev(++(x,y)) -> ++(rev(y),rev(x))
        rev(nil()) -> nil()
        rev(rev(x)) -> x
      Signature:
        {++/2,make/1,rev/1} / {./2,nil/0}
      Obligation:
        Full
        basic terms: {++,make,rev}/{.,nil}
    Applied Processor:
      EmptyProcessor
    Proof:
      The problem is already closed. The intended complexity is O(1).