We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict Trs:
  { admit(x, nil()) -> nil()
  , admit(x, .(u, .(v, .(w(), z)))) ->
    cond(=(sum(x, u, v), w()),
         .(u, .(v, .(w(), admit(carry(x, u, v), z)))))
  , cond(true(), y) -> y }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

We add the following weak dependency pairs:

Strict DPs:
  { admit^#(x, nil()) -> c_1()
  , admit^#(x, .(u, .(v, .(w(), z)))) ->
    c_2(cond^#(=(sum(x, u, v), w()),
               .(u, .(v, .(w(), admit(carry(x, u, v), z))))))
  , cond^#(true(), y) -> c_3(y) }

and mark the set of starting terms.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict DPs:
  { admit^#(x, nil()) -> c_1()
  , admit^#(x, .(u, .(v, .(w(), z)))) ->
    c_2(cond^#(=(sum(x, u, v), w()),
               .(u, .(v, .(w(), admit(carry(x, u, v), z))))))
  , cond^#(true(), y) -> c_3(y) }
Strict Trs:
  { admit(x, nil()) -> nil()
  , admit(x, .(u, .(v, .(w(), z)))) ->
    cond(=(sum(x, u, v), w()),
         .(u, .(v, .(w(), admit(carry(x, u, v), z)))))
  , cond(true(), y) -> y }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

The weightgap principle applies (using the following constant
growth matrix-interpretation)

The following argument positions are usable:
  Uargs(.) = {2}, Uargs(cond) = {2}, Uargs(c_2) = {1},
  Uargs(cond^#) = {2}, Uargs(c_3) = {1}

TcT has computed the following constructor-restricted matrix
interpretation.

      [admit](x1, x2) = [0 2] x1 + [0 1] x2 + [0]
                        [0 0]      [0 1]      [0]
                                                 
                [nil] = [0]                      
                        [1]                      
                                                 
          [.](x1, x2) = [0 1] x1 + [1 0] x2 + [0]
                        [0 1]      [0 1]      [1]
                                                 
                  [w] = [0]                      
                        [2]                      
                                                 
       [cond](x1, x2) = [1 0] x2 + [2]           
                        [0 1]      [0]           
                                                 
          [=](x1, x2) = [0]                      
                        [0]                      
                                                 
    [sum](x1, x2, x3) = [0]                      
                        [0]                      
                                                 
  [carry](x1, x2, x3) = [1]                      
                        [0]                      
                                                 
               [true] = [0]                      
                        [0]                      
                                                 
    [admit^#](x1, x2) = [1 2] x1 + [0 1] x2 + [0]
                        [0 0]      [0 0]      [0]
                                                 
                [c_1] = [0]                      
                        [0]                      
                                                 
            [c_2](x1) = [1 0] x1 + [0]           
                        [0 1]      [0]           
                                                 
     [cond^#](x1, x2) = [1 0] x2 + [0]           
                        [0 0]      [0]           
                                                 
            [c_3](x1) = [1 0] x1 + [0]           
                        [0 1]      [0]           

The order satisfies the following ordering constraints:

                    [admit(x, nil())] = [0 2] x + [1]                                              
                                        [0 0]     [1]                                              
                                      > [0]                                                        
                                        [1]                                                        
                                      = [nil()]                                                    
                                                                                                   
    [admit(x, .(u, .(v, .(w(), z))))] = [0 2] x + [0 1] u + [0 1] v + [0 1] z + [5]                
                                        [0 0]     [0 1]     [0 1]     [0 1]     [5]                
                                      > [0 1] u + [0 1] v + [0 1] z + [4]                          
                                        [0 1]     [0 1]     [0 1]     [5]                          
                                      = [cond(=(sum(x, u, v), w()),                                
                                              .(u, .(v, .(w(), admit(carry(x, u, v), z)))))]       
                                                                                                   
                    [cond(true(), y)] = [1 0] y + [2]                                              
                                        [0 1]     [0]                                              
                                      > [1 0] y + [0]                                              
                                        [0 1]     [0]                                              
                                      = [y]                                                        
                                                                                                   
                  [admit^#(x, nil())] = [1 2] x + [1]                                              
                                        [0 0]     [0]                                              
                                      > [0]                                                        
                                        [0]                                                        
                                      = [c_1()]                                                    
                                                                                                   
  [admit^#(x, .(u, .(v, .(w(), z))))] = [1 2] x + [0 1] u + [0 1] v + [0 1] z + [5]                
                                        [0 0]     [0 0]     [0 0]     [0 0]     [0]                
                                      > [0 1] u + [0 1] v + [0 1] z + [2]                          
                                        [0 0]     [0 0]     [0 0]     [0]                          
                                      = [c_2(cond^#(=(sum(x, u, v), w()),                          
                                                    .(u, .(v, .(w(), admit(carry(x, u, v), z))))))]
                                                                                                   
                  [cond^#(true(), y)] = [1 0] y + [0]                                              
                                        [0 0]     [0]                                              
                                      ? [1 0] y + [0]                                              
                                        [0 1]     [0]                                              
                                      = [c_3(y)]                                                   
                                                                                                   

Further, it can be verified that all rules not oriented are covered by the weightgap condition.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict DPs: { cond^#(true(), y) -> c_3(y) }
Weak DPs:
  { admit^#(x, nil()) -> c_1()
  , admit^#(x, .(u, .(v, .(w(), z)))) ->
    c_2(cond^#(=(sum(x, u, v), w()),
               .(u, .(v, .(w(), admit(carry(x, u, v), z)))))) }
Weak Trs:
  { admit(x, nil()) -> nil()
  , admit(x, .(u, .(v, .(w(), z)))) ->
    cond(=(sum(x, u, v), w()),
         .(u, .(v, .(w(), admit(carry(x, u, v), z)))))
  , cond(true(), y) -> y }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

The following weak DPs constitute a sub-graph of the DG that is
closed under successors. The DPs are removed.

{ admit^#(x, nil()) -> c_1()
, admit^#(x, .(u, .(v, .(w(), z)))) ->
  c_2(cond^#(=(sum(x, u, v), w()),
             .(u, .(v, .(w(), admit(carry(x, u, v), z)))))) }

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict DPs: { cond^#(true(), y) -> c_3(y) }
Weak Trs:
  { admit(x, nil()) -> nil()
  , admit(x, .(u, .(v, .(w(), z)))) ->
    cond(=(sum(x, u, v), w()),
         .(u, .(v, .(w(), admit(carry(x, u, v), z)))))
  , cond(true(), y) -> y }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

No rule is usable, rules are removed from the input problem.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict DPs: { cond^#(true(), y) -> c_3(y) }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

We use the processor 'matrix interpretation of dimension 1' to
orient following rules strictly.

DPs:
  { 1: cond^#(true(), y) -> c_3(y) }

Sub-proof:
----------
  The following argument positions are usable:
    none
  
  TcT has computed the following constructor-based matrix
  interpretation satisfying not(EDA).
  
              [true] = [1]         
                                   
    [cond^#](x1, x2) = [1] x1 + [4]
                                   
           [c_3](x1) = [0]         
  
  The order satisfies the following ordering constraints:
  
    [cond^#(true(), y)] = [5]     
                        > [0]     
                        = [c_3(y)]
                                  

The strictly oriented rules are moved into the weak component.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(1)).

Weak DPs: { cond^#(true(), y) -> c_3(y) }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(1))

The following weak DPs constitute a sub-graph of the DG that is
closed under successors. The DPs are removed.

{ cond^#(true(), y) -> c_3(y) }

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(1)).

Rules: Empty
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(1))

Empty rules are trivially bounded

Hurray, we answered YES(O(1),O(n^1))