We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict Trs:
  { sum(0()) -> 0()
  , sum(s(x)) -> +(sum(x), s(x))
  , sum1(0()) -> 0()
  , sum1(s(x)) -> s(+(sum1(x), +(x, x))) }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

We add the following weak dependency pairs:

Strict DPs:
  { sum^#(0()) -> c_1()
  , sum^#(s(x)) -> c_2(sum^#(x), x)
  , sum1^#(0()) -> c_3()
  , sum1^#(s(x)) -> c_4(sum1^#(x), x, x) }

and mark the set of starting terms.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict DPs:
  { sum^#(0()) -> c_1()
  , sum^#(s(x)) -> c_2(sum^#(x), x)
  , sum1^#(0()) -> c_3()
  , sum1^#(s(x)) -> c_4(sum1^#(x), x, x) }
Strict Trs:
  { sum(0()) -> 0()
  , sum(s(x)) -> +(sum(x), s(x))
  , sum1(0()) -> 0()
  , sum1(s(x)) -> s(+(sum1(x), +(x, x))) }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

No rule is usable, rules are removed from the input problem.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict DPs:
  { sum^#(0()) -> c_1()
  , sum^#(s(x)) -> c_2(sum^#(x), x)
  , sum1^#(0()) -> c_3()
  , sum1^#(s(x)) -> c_4(sum1^#(x), x, x) }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

The weightgap principle applies (using the following constant
growth matrix-interpretation)

The following argument positions are usable:
  Uargs(c_2) = {1}, Uargs(c_4) = {1}

TcT has computed the following constructor-restricted matrix
interpretation.

                [0] = [0]           
                      [0]           
                                    
            [s](x1) = [1 0] x1 + [0]
                      [0 0]      [0]
                                    
        [sum^#](x1) = [0]           
                      [0]           
                                    
              [c_1] = [0]           
                      [0]           
                                    
      [c_2](x1, x2) = [1 0] x1 + [0]
                      [0 1]      [2]
                                    
       [sum1^#](x1) = [1]           
                      [0]           
                                    
              [c_3] = [0]           
                      [0]           
                                    
  [c_4](x1, x2, x3) = [1 0] x1 + [0]
                      [0 1]      [0]

The order satisfies the following ordering constraints:

    [sum^#(0())] =  [0]                   
                    [0]                   
                 >= [0]                   
                    [0]                   
                 =  [c_1()]               
                                          
   [sum^#(s(x))] =  [0]                   
                    [0]                   
                 ?  [0]                   
                    [2]                   
                 =  [c_2(sum^#(x), x)]    
                                          
   [sum1^#(0())] =  [1]                   
                    [0]                   
                 >  [0]                   
                    [0]                   
                 =  [c_3()]               
                                          
  [sum1^#(s(x))] =  [1]                   
                    [0]                   
                 >= [1]                   
                    [0]                   
                 =  [c_4(sum1^#(x), x, x)]
                                          

Further, it can be verified that all rules not oriented are covered by the weightgap condition.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict DPs:
  { sum^#(0()) -> c_1()
  , sum^#(s(x)) -> c_2(sum^#(x), x)
  , sum1^#(s(x)) -> c_4(sum1^#(x), x, x) }
Weak DPs: { sum1^#(0()) -> c_3() }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

We estimate the number of application of {1} by applications of
Pre({1}) = {2,3}. Here rules are labeled as follows:

  DPs:
    { 1: sum^#(0()) -> c_1()
    , 2: sum^#(s(x)) -> c_2(sum^#(x), x)
    , 3: sum1^#(s(x)) -> c_4(sum1^#(x), x, x)
    , 4: sum1^#(0()) -> c_3() }

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict DPs:
  { sum^#(s(x)) -> c_2(sum^#(x), x)
  , sum1^#(s(x)) -> c_4(sum1^#(x), x, x) }
Weak DPs:
  { sum^#(0()) -> c_1()
  , sum1^#(0()) -> c_3() }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

The following weak DPs constitute a sub-graph of the DG that is
closed under successors. The DPs are removed.

{ sum^#(0()) -> c_1()
, sum1^#(0()) -> c_3() }

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict DPs:
  { sum^#(s(x)) -> c_2(sum^#(x), x)
  , sum1^#(s(x)) -> c_4(sum1^#(x), x, x) }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

We use the processor 'matrix interpretation of dimension 1' to
orient following rules strictly.

DPs:
  { 1: sum^#(s(x)) -> c_2(sum^#(x), x) }

Sub-proof:
----------
  The following argument positions are usable:
    Uargs(c_2) = {1}, Uargs(c_4) = {1}
  
  TcT has computed the following constructor-based matrix
  interpretation satisfying not(EDA).
  
              [s](x1) = [1] x1 + [4]
                                    
          [sum^#](x1) = [2] x1 + [0]
                                    
        [c_2](x1, x2) = [1] x1 + [7]
                                    
         [sum1^#](x1) = [6]         
                                    
    [c_4](x1, x2, x3) = [1] x1 + [0]
  
  The order satisfies the following ordering constraints:
  
     [sum^#(s(x))] =  [2] x + [8]           
                   >  [2] x + [7]           
                   =  [c_2(sum^#(x), x)]    
                                            
    [sum1^#(s(x))] =  [6]                   
                   >= [6]                   
                   =  [c_4(sum1^#(x), x, x)]
                                            

The strictly oriented rules are moved into the weak component.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict DPs: { sum1^#(s(x)) -> c_4(sum1^#(x), x, x) }
Weak DPs: { sum^#(s(x)) -> c_2(sum^#(x), x) }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

We use the processor 'matrix interpretation of dimension 1' to
orient following rules strictly.

DPs:
  { 1: sum1^#(s(x)) -> c_4(sum1^#(x), x, x) }

Sub-proof:
----------
  The following argument positions are usable:
    Uargs(c_2) = {1}, Uargs(c_4) = {1}
  
  TcT has computed the following constructor-based matrix
  interpretation satisfying not(EDA).
  
              [s](x1) = [1] x1 + [4]
                                    
          [sum^#](x1) = [0]         
                                    
        [c_2](x1, x2) = [1] x1 + [0]
                                    
         [sum1^#](x1) = [2] x1 + [0]
                                    
    [c_4](x1, x2, x3) = [1] x1 + [1]
  
  The order satisfies the following ordering constraints:
  
     [sum^#(s(x))] =  [0]                   
                   >= [0]                   
                   =  [c_2(sum^#(x), x)]    
                                            
    [sum1^#(s(x))] =  [2] x + [8]           
                   >  [2] x + [1]           
                   =  [c_4(sum1^#(x), x, x)]
                                            

The strictly oriented rules are moved into the weak component.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(1)).

Weak DPs:
  { sum^#(s(x)) -> c_2(sum^#(x), x)
  , sum1^#(s(x)) -> c_4(sum1^#(x), x, x) }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(1))

The following weak DPs constitute a sub-graph of the DG that is
closed under successors. The DPs are removed.

{ sum^#(s(x)) -> c_2(sum^#(x), x)
, sum1^#(s(x)) -> c_4(sum1^#(x), x, x) }

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(1)).

Rules: Empty
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(1))

Empty rules are trivially bounded

Hurray, we answered YES(O(1),O(n^1))