*** 1 Progress [(O(1),O(n^2))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: f(x,0()) -> x f(0(),y) -> y f(1(),g(x,y)) -> x f(2(),g(x,y)) -> y f(f(x,y),z) -> f(x,f(y,z)) f(g(x,y),z) -> g(f(x,z),f(y,z)) f(i(x),y) -> i(x) Weak DP Rules: Weak TRS Rules: Signature: {f/2} / {0/0,1/0,2/0,g/2,i/1} Obligation: Full basic terms: {f}/{0,1,2,g,i} Applied Processor: NaturalPI {shape = Mixed 2, restrict = Restrict, uargs = UArgs, urules = URules, selector = Just any strict-rules, greedy = NoGreedy} Proof: We apply a polynomial interpretation of kind constructor-based(mixed(2)): The following argument positions are considered usable: uargs(f) = {2}, uargs(g) = {1,2} Following symbols are considered usable: {} TcT has computed the following interpretation: p(0) = 0 p(1) = 0 p(2) = 0 p(f) = 1 + 2*x1 + 2*x1*x2 + 2*x2 p(g) = 1 + x1 + x2 p(i) = 1 Following rules are strictly oriented: f(x,0()) = 1 + 2*x > x = x f(0(),y) = 1 + 2*y > y = y f(1(),g(x,y)) = 3 + 2*x + 2*y > x = x f(2(),g(x,y)) = 3 + 2*x + 2*y > y = y f(i(x),y) = 3 + 4*y > 1 = i(x) Following rules are (at-least) weakly oriented: f(f(x,y),z) = 3 + 4*x + 4*x*y + 4*x*y*z + 4*x*z + 4*y + 4*y*z + 4*z >= 3 + 4*x + 4*x*y + 4*x*y*z + 4*x*z + 4*y + 4*y*z + 4*z = f(x,f(y,z)) f(g(x,y),z) = 3 + 2*x + 2*x*z + 2*y + 2*y*z + 4*z >= 3 + 2*x + 2*x*z + 2*y + 2*y*z + 4*z = g(f(x,z),f(y,z)) *** 1.1 Progress [(O(1),O(n^2))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: f(f(x,y),z) -> f(x,f(y,z)) f(g(x,y),z) -> g(f(x,z),f(y,z)) Weak DP Rules: Weak TRS Rules: f(x,0()) -> x f(0(),y) -> y f(1(),g(x,y)) -> x f(2(),g(x,y)) -> y f(i(x),y) -> i(x) Signature: {f/2} / {0/0,1/0,2/0,g/2,i/1} Obligation: Full basic terms: {f}/{0,1,2,g,i} Applied Processor: NaturalPI {shape = Mixed 2, restrict = Restrict, uargs = UArgs, urules = URules, selector = Just any strict-rules, greedy = NoGreedy} Proof: We apply a polynomial interpretation of kind constructor-based(mixed(2)): The following argument positions are considered usable: uargs(f) = {2}, uargs(g) = {1,2} Following symbols are considered usable: {} TcT has computed the following interpretation: p(0) = 0 p(1) = 1 p(2) = 0 p(f) = x1 + 2*x1*x2 + x1^2 + x2 p(g) = 1 + x1 + x2 p(i) = x1 Following rules are strictly oriented: f(g(x,y),z) = 2 + 3*x + 2*x*y + 2*x*z + x^2 + 3*y + 2*y*z + y^2 + 3*z > 1 + x + 2*x*z + x^2 + y + 2*y*z + y^2 + 2*z = g(f(x,z),f(y,z)) Following rules are (at-least) weakly oriented: f(x,0()) = x + x^2 >= x = x f(0(),y) = y >= y = y f(1(),g(x,y)) = 5 + 3*x + 3*y >= x = x f(2(),g(x,y)) = 1 + x + y >= y = y f(f(x,y),z) = x + 4*x*y + 4*x*y*z + 4*x*y^2 + 2*x*z + 2*x^2 + 6*x^2*y + 4*x^2*y^2 + 2*x^2*z + 2*x^3 + 4*x^3*y + x^4 + y + 2*y*z + y^2 + z >= x + 2*x*y + 4*x*y*z + 2*x*y^2 + 2*x*z + x^2 + y + 2*y*z + y^2 + z = f(x,f(y,z)) f(i(x),y) = x + 2*x*y + x^2 + y >= x = i(x) *** 1.1.1 Progress [(O(1),O(n^2))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: f(f(x,y),z) -> f(x,f(y,z)) Weak DP Rules: Weak TRS Rules: f(x,0()) -> x f(0(),y) -> y f(1(),g(x,y)) -> x f(2(),g(x,y)) -> y f(g(x,y),z) -> g(f(x,z),f(y,z)) f(i(x),y) -> i(x) Signature: {f/2} / {0/0,1/0,2/0,g/2,i/1} Obligation: Full basic terms: {f}/{0,1,2,g,i} Applied Processor: NaturalPI {shape = Mixed 2, restrict = Restrict, uargs = UArgs, urules = URules, selector = Just any strict-rules, greedy = NoGreedy} Proof: We apply a polynomial interpretation of kind constructor-based(mixed(2)): The following argument positions are considered usable: uargs(f) = {2}, uargs(g) = {1,2} Following symbols are considered usable: {} TcT has computed the following interpretation: p(0) = 0 p(1) = 0 p(2) = 1 p(f) = 2 + 3*x1 + x1*x2 + x2 p(g) = 1 + x1 + x2 p(i) = 0 Following rules are strictly oriented: f(f(x,y),z) = 8 + 9*x + 3*x*y + x*y*z + 3*x*z + 3*y + y*z + 3*z > 4 + 5*x + 3*x*y + x*y*z + x*z + 3*y + y*z + z = f(x,f(y,z)) Following rules are (at-least) weakly oriented: f(x,0()) = 2 + 3*x >= x = x f(0(),y) = 2 + y >= y = y f(1(),g(x,y)) = 3 + x + y >= x = x f(2(),g(x,y)) = 7 + 2*x + 2*y >= y = y f(g(x,y),z) = 5 + 3*x + x*z + 3*y + y*z + 2*z >= 5 + 3*x + x*z + 3*y + y*z + 2*z = g(f(x,z),f(y,z)) f(i(x),y) = 2 + y >= 0 = i(x) *** 1.1.1.1 Progress [(O(1),O(1))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: Weak DP Rules: Weak TRS Rules: f(x,0()) -> x f(0(),y) -> y f(1(),g(x,y)) -> x f(2(),g(x,y)) -> y f(f(x,y),z) -> f(x,f(y,z)) f(g(x,y),z) -> g(f(x,z),f(y,z)) f(i(x),y) -> i(x) Signature: {f/2} / {0/0,1/0,2/0,g/2,i/1} Obligation: Full basic terms: {f}/{0,1,2,g,i} Applied Processor: EmptyProcessor Proof: The problem is already closed. The intended complexity is O(1).