*** 1 Progress [(O(1),O(n^2))] ***
Considered Problem:
Strict DP Rules:
Strict TRS Rules:
f(x,0()) -> x
f(0(),y) -> y
f(1(),g(x,y)) -> x
f(2(),g(x,y)) -> y
f(f(x,y),z) -> f(x,f(y,z))
f(g(x,y),z) -> g(f(x,z),f(y,z))
f(i(x),y) -> i(x)
Weak DP Rules:
Weak TRS Rules:
Signature:
{f/2} / {0/0,1/0,2/0,g/2,i/1}
Obligation:
Full
basic terms: {f}/{0,1,2,g,i}
Applied Processor:
NaturalPI {shape = Mixed 2, restrict = Restrict, uargs = UArgs, urules = URules, selector = Just any strict-rules, greedy = NoGreedy}
Proof:
We apply a polynomial interpretation of kind constructor-based(mixed(2)):
The following argument positions are considered usable:
uargs(f) = {2},
uargs(g) = {1,2}
Following symbols are considered usable:
{}
TcT has computed the following interpretation:
p(0) = 0
p(1) = 0
p(2) = 0
p(f) = 1 + 2*x1 + 2*x1*x2 + 2*x2
p(g) = 1 + x1 + x2
p(i) = 1
Following rules are strictly oriented:
f(x,0()) = 1 + 2*x
> x
= x
f(0(),y) = 1 + 2*y
> y
= y
f(1(),g(x,y)) = 3 + 2*x + 2*y
> x
= x
f(2(),g(x,y)) = 3 + 2*x + 2*y
> y
= y
f(i(x),y) = 3 + 4*y
> 1
= i(x)
Following rules are (at-least) weakly oriented:
f(f(x,y),z) = 3 + 4*x + 4*x*y + 4*x*y*z + 4*x*z + 4*y + 4*y*z + 4*z
>= 3 + 4*x + 4*x*y + 4*x*y*z + 4*x*z + 4*y + 4*y*z + 4*z
= f(x,f(y,z))
f(g(x,y),z) = 3 + 2*x + 2*x*z + 2*y + 2*y*z + 4*z
>= 3 + 2*x + 2*x*z + 2*y + 2*y*z + 4*z
= g(f(x,z),f(y,z))
*** 1.1 Progress [(O(1),O(n^2))] ***
Considered Problem:
Strict DP Rules:
Strict TRS Rules:
f(f(x,y),z) -> f(x,f(y,z))
f(g(x,y),z) -> g(f(x,z),f(y,z))
Weak DP Rules:
Weak TRS Rules:
f(x,0()) -> x
f(0(),y) -> y
f(1(),g(x,y)) -> x
f(2(),g(x,y)) -> y
f(i(x),y) -> i(x)
Signature:
{f/2} / {0/0,1/0,2/0,g/2,i/1}
Obligation:
Full
basic terms: {f}/{0,1,2,g,i}
Applied Processor:
NaturalPI {shape = Mixed 2, restrict = Restrict, uargs = UArgs, urules = URules, selector = Just any strict-rules, greedy = NoGreedy}
Proof:
We apply a polynomial interpretation of kind constructor-based(mixed(2)):
The following argument positions are considered usable:
uargs(f) = {2},
uargs(g) = {1,2}
Following symbols are considered usable:
{}
TcT has computed the following interpretation:
p(0) = 0
p(1) = 1
p(2) = 0
p(f) = x1 + 2*x1*x2 + x1^2 + x2
p(g) = 1 + x1 + x2
p(i) = x1
Following rules are strictly oriented:
f(g(x,y),z) = 2 + 3*x + 2*x*y + 2*x*z + x^2 + 3*y + 2*y*z + y^2 + 3*z
> 1 + x + 2*x*z + x^2 + y + 2*y*z + y^2 + 2*z
= g(f(x,z),f(y,z))
Following rules are (at-least) weakly oriented:
f(x,0()) = x + x^2
>= x
= x
f(0(),y) = y
>= y
= y
f(1(),g(x,y)) = 5 + 3*x + 3*y
>= x
= x
f(2(),g(x,y)) = 1 + x + y
>= y
= y
f(f(x,y),z) = x + 4*x*y + 4*x*y*z + 4*x*y^2 + 2*x*z + 2*x^2 + 6*x^2*y + 4*x^2*y^2 + 2*x^2*z + 2*x^3 + 4*x^3*y + x^4 + y + 2*y*z + y^2 + z
>= x + 2*x*y + 4*x*y*z + 2*x*y^2 + 2*x*z + x^2 + y + 2*y*z + y^2 + z
= f(x,f(y,z))
f(i(x),y) = x + 2*x*y + x^2 + y
>= x
= i(x)
*** 1.1.1 Progress [(O(1),O(n^2))] ***
Considered Problem:
Strict DP Rules:
Strict TRS Rules:
f(f(x,y),z) -> f(x,f(y,z))
Weak DP Rules:
Weak TRS Rules:
f(x,0()) -> x
f(0(),y) -> y
f(1(),g(x,y)) -> x
f(2(),g(x,y)) -> y
f(g(x,y),z) -> g(f(x,z),f(y,z))
f(i(x),y) -> i(x)
Signature:
{f/2} / {0/0,1/0,2/0,g/2,i/1}
Obligation:
Full
basic terms: {f}/{0,1,2,g,i}
Applied Processor:
NaturalPI {shape = Mixed 2, restrict = Restrict, uargs = UArgs, urules = URules, selector = Just any strict-rules, greedy = NoGreedy}
Proof:
We apply a polynomial interpretation of kind constructor-based(mixed(2)):
The following argument positions are considered usable:
uargs(f) = {2},
uargs(g) = {1,2}
Following symbols are considered usable:
{}
TcT has computed the following interpretation:
p(0) = 0
p(1) = 0
p(2) = 1
p(f) = 2 + 3*x1 + x1*x2 + x2
p(g) = 1 + x1 + x2
p(i) = 0
Following rules are strictly oriented:
f(f(x,y),z) = 8 + 9*x + 3*x*y + x*y*z + 3*x*z + 3*y + y*z + 3*z
> 4 + 5*x + 3*x*y + x*y*z + x*z + 3*y + y*z + z
= f(x,f(y,z))
Following rules are (at-least) weakly oriented:
f(x,0()) = 2 + 3*x
>= x
= x
f(0(),y) = 2 + y
>= y
= y
f(1(),g(x,y)) = 3 + x + y
>= x
= x
f(2(),g(x,y)) = 7 + 2*x + 2*y
>= y
= y
f(g(x,y),z) = 5 + 3*x + x*z + 3*y + y*z + 2*z
>= 5 + 3*x + x*z + 3*y + y*z + 2*z
= g(f(x,z),f(y,z))
f(i(x),y) = 2 + y
>= 0
= i(x)
*** 1.1.1.1 Progress [(O(1),O(1))] ***
Considered Problem:
Strict DP Rules:
Strict TRS Rules:
Weak DP Rules:
Weak TRS Rules:
f(x,0()) -> x
f(0(),y) -> y
f(1(),g(x,y)) -> x
f(2(),g(x,y)) -> y
f(f(x,y),z) -> f(x,f(y,z))
f(g(x,y),z) -> g(f(x,z),f(y,z))
f(i(x),y) -> i(x)
Signature:
{f/2} / {0/0,1/0,2/0,g/2,i/1}
Obligation:
Full
basic terms: {f}/{0,1,2,g,i}
Applied Processor:
EmptyProcessor
Proof:
The problem is already closed. The intended complexity is O(1).