*** 1 Progress [(O(1),O(1))]  ***
    Considered Problem:
      Strict DP Rules:
        
      Strict TRS Rules:
        f(s(X),Y) -> h(s(f(h(Y),X)))
      Weak DP Rules:
        
      Weak TRS Rules:
        
      Signature:
        {f/2} / {h/1,s/1}
      Obligation:
        Full
        basic terms: {f}/{h,s}
    Applied Processor:
      ToInnermost
    Proof:
      switch to innermost, as the system is overlay and right linear and does not contain weak rules
*** 1.1 Progress [(O(1),O(1))]  ***
    Considered Problem:
      Strict DP Rules:
        
      Strict TRS Rules:
        f(s(X),Y) -> h(s(f(h(Y),X)))
      Weak DP Rules:
        
      Weak TRS Rules:
        
      Signature:
        {f/2} / {h/1,s/1}
      Obligation:
        Innermost
        basic terms: {f}/{h,s}
    Applied Processor:
      DependencyPairs {dpKind_ = DT}
    Proof:
      We add the following dependency tuples:
      
      Strict DPs
        f#(s(X),Y) -> c_1(f#(h(Y),X))
      Weak DPs
        
      
      and mark the set of starting terms.
*** 1.1.1 Progress [(O(1),O(1))]  ***
    Considered Problem:
      Strict DP Rules:
        f#(s(X),Y) -> c_1(f#(h(Y),X))
      Strict TRS Rules:
        
      Weak DP Rules:
        
      Weak TRS Rules:
        f(s(X),Y) -> h(s(f(h(Y),X)))
      Signature:
        {f/2,f#/2} / {h/1,s/1,c_1/1}
      Obligation:
        Innermost
        basic terms: {f#}/{h,s}
    Applied Processor:
      UsableRules
    Proof:
      We replace rewrite rules by usable rules:
        f#(s(X),Y) -> c_1(f#(h(Y),X))
*** 1.1.1.1 Progress [(O(1),O(1))]  ***
    Considered Problem:
      Strict DP Rules:
        f#(s(X),Y) -> c_1(f#(h(Y),X))
      Strict TRS Rules:
        
      Weak DP Rules:
        
      Weak TRS Rules:
        
      Signature:
        {f/2,f#/2} / {h/1,s/1,c_1/1}
      Obligation:
        Innermost
        basic terms: {f#}/{h,s}
    Applied Processor:
      Trivial
    Proof:
      Consider the dependency graph
        1:S:f#(s(X),Y) -> c_1(f#(h(Y),X))
           
        
      The dependency graph contains no loops, we remove all dependency pairs.
*** 1.1.1.1.1 Progress [(O(1),O(1))]  ***
    Considered Problem:
      Strict DP Rules:
        
      Strict TRS Rules:
        
      Weak DP Rules:
        
      Weak TRS Rules:
        
      Signature:
        {f/2,f#/2} / {h/1,s/1,c_1/1}
      Obligation:
        Innermost
        basic terms: {f#}/{h,s}
    Applied Processor:
      EmptyProcessor
    Proof:
      The problem is already closed. The intended complexity is O(1).