*** 1 Progress [(O(1),O(1))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: f(f(x)) -> f(c(f(x))) f(f(x)) -> f(d(f(x))) g(c(x)) -> x g(c(0())) -> g(d(1())) g(c(1())) -> g(d(0())) g(d(x)) -> x Weak DP Rules: Weak TRS Rules: Signature: {f/1,g/1} / {0/0,1/0,c/1,d/1} Obligation: Full basic terms: {f,g}/{0,1,c,d} Applied Processor: DependencyPairs {dpKind_ = DT} Proof: We add the following weak dependency pairs: Strict DPs f#(f(x)) -> c_1(f#(c(f(x)))) f#(f(x)) -> c_2(f#(d(f(x)))) g#(c(x)) -> c_3(x) g#(c(0())) -> c_4(g#(d(1()))) g#(c(1())) -> c_5(g#(d(0()))) g#(d(x)) -> c_6(x) Weak DPs and mark the set of starting terms. *** 1.1 Progress [(O(1),O(1))] *** Considered Problem: Strict DP Rules: f#(f(x)) -> c_1(f#(c(f(x)))) f#(f(x)) -> c_2(f#(d(f(x)))) g#(c(x)) -> c_3(x) g#(c(0())) -> c_4(g#(d(1()))) g#(c(1())) -> c_5(g#(d(0()))) g#(d(x)) -> c_6(x) Strict TRS Rules: f(f(x)) -> f(c(f(x))) f(f(x)) -> f(d(f(x))) g(c(x)) -> x g(c(0())) -> g(d(1())) g(c(1())) -> g(d(0())) g(d(x)) -> x Weak DP Rules: Weak TRS Rules: Signature: {f/1,g/1,f#/1,g#/1} / {0/0,1/0,c/1,d/1,c_1/1,c_2/1,c_3/1,c_4/1,c_5/1,c_6/1} Obligation: Full basic terms: {f#,g#}/{0,1,c,d} Applied Processor: UsableRules Proof: We replace rewrite rules by usable rules: g#(c(x)) -> c_3(x) g#(c(0())) -> c_4(g#(d(1()))) g#(c(1())) -> c_5(g#(d(0()))) g#(d(x)) -> c_6(x) *** 1.1.1 Progress [(O(1),O(1))] *** Considered Problem: Strict DP Rules: g#(c(x)) -> c_3(x) g#(c(0())) -> c_4(g#(d(1()))) g#(c(1())) -> c_5(g#(d(0()))) g#(d(x)) -> c_6(x) Strict TRS Rules: Weak DP Rules: Weak TRS Rules: Signature: {f/1,g/1,f#/1,g#/1} / {0/0,1/0,c/1,d/1,c_1/1,c_2/1,c_3/1,c_4/1,c_5/1,c_6/1} Obligation: Full basic terms: {f#,g#}/{0,1,c,d} Applied Processor: NaturalMI {miDimension = 1, miDegree = 0, miKind = Algebraic, uargs = UArgs, urules = URules, selector = Just any strict-rules, greedy = NoGreedy} Proof: We apply a matrix interpretation of kind constructor based matrix interpretation (containing no more than 0 non-zero interpretation-entries in the diagonal of the component-wise maxima): The following argument positions are considered usable: uargs(c_4) = {1}, uargs(c_5) = {1} Following symbols are considered usable: {} TcT has computed the following interpretation: p(0) = [0] p(1) = [0] p(c) = [3] p(d) = [0] p(f) = [1] x1 + [2] p(g) = [8] x1 + [1] p(f#) = [2] p(g#) = [8] x1 + [1] p(c_1) = [2] x1 + [0] p(c_2) = [1] x1 + [1] p(c_3) = [8] p(c_4) = [2] x1 + [15] p(c_5) = [4] x1 + [15] p(c_6) = [0] Following rules are strictly oriented: g#(c(x)) = [25] > [8] = c_3(x) g#(c(0())) = [25] > [17] = c_4(g#(d(1()))) g#(c(1())) = [25] > [19] = c_5(g#(d(0()))) g#(d(x)) = [1] > [0] = c_6(x) Following rules are (at-least) weakly oriented: *** 1.1.1.1 Progress [(O(1),O(1))] *** Considered Problem: Strict DP Rules: Strict TRS Rules: Weak DP Rules: g#(c(x)) -> c_3(x) g#(c(0())) -> c_4(g#(d(1()))) g#(c(1())) -> c_5(g#(d(0()))) g#(d(x)) -> c_6(x) Weak TRS Rules: Signature: {f/1,g/1,f#/1,g#/1} / {0/0,1/0,c/1,d/1,c_1/1,c_2/1,c_3/1,c_4/1,c_5/1,c_6/1} Obligation: Full basic terms: {f#,g#}/{0,1,c,d} Applied Processor: EmptyProcessor Proof: The problem is already closed. The intended complexity is O(1).