(0) Obligation:

Runtime Complexity TRS:
The TRS R consists of the following rules:

cond1(true, x, y) → cond2(gr(x, y), x, y)
cond2(true, x, y) → cond1(gr0(x), y, y)
cond2(false, x, y) → cond1(gr0(x), p(x), y)
gr(0, x) → false
gr(s(x), 0) → true
gr(s(x), s(y)) → gr(x, y)
gr0(0) → false
gr0(s(x)) → true
p(0) → 0
p(s(x)) → x

Rewrite Strategy: FULL

(1) RenamingProof (EQUIVALENT transformation)

Renamed function symbols to avoid clashes with predefined symbol.

(2) Obligation:

Runtime Complexity Relative TRS:
The TRS R consists of the following rules:

cond1(true, x, y) → cond2(gr(x, y), x, y)
cond2(true, x, y) → cond1(gr0(x), y, y)
cond2(false, x, y) → cond1(gr0(x), p(x), y)
gr(0', x) → false
gr(s(x), 0') → true
gr(s(x), s(y)) → gr(x, y)
gr0(0') → false
gr0(s(x)) → true
p(0') → 0'
p(s(x)) → x

S is empty.
Rewrite Strategy: FULL

(3) TypeInferenceProof (BOTH BOUNDS(ID, ID) transformation)

Infered types.

(4) Obligation:

TRS:
Rules:
cond1(true, x, y) → cond2(gr(x, y), x, y)
cond2(true, x, y) → cond1(gr0(x), y, y)
cond2(false, x, y) → cond1(gr0(x), p(x), y)
gr(0', x) → false
gr(s(x), 0') → true
gr(s(x), s(y)) → gr(x, y)
gr0(0') → false
gr0(s(x)) → true
p(0') → 0'
p(s(x)) → x

Types:
cond1 :: true:false → 0':s → 0':s → cond1:cond2
true :: true:false
cond2 :: true:false → 0':s → 0':s → cond1:cond2
gr :: 0':s → 0':s → true:false
gr0 :: 0':s → true:false
false :: true:false
p :: 0':s → 0':s
0' :: 0':s
s :: 0':s → 0':s
hole_cond1:cond21_3 :: cond1:cond2
hole_true:false2_3 :: true:false
hole_0':s3_3 :: 0':s
gen_0':s4_3 :: Nat → 0':s

(5) OrderProof (LOWER BOUND(ID) transformation)

Heuristically decided to analyse the following defined symbols:
cond1, cond2, gr

They will be analysed ascendingly in the following order:
cond1 = cond2
gr < cond1

(6) Obligation:

TRS:
Rules:
cond1(true, x, y) → cond2(gr(x, y), x, y)
cond2(true, x, y) → cond1(gr0(x), y, y)
cond2(false, x, y) → cond1(gr0(x), p(x), y)
gr(0', x) → false
gr(s(x), 0') → true
gr(s(x), s(y)) → gr(x, y)
gr0(0') → false
gr0(s(x)) → true
p(0') → 0'
p(s(x)) → x

Types:
cond1 :: true:false → 0':s → 0':s → cond1:cond2
true :: true:false
cond2 :: true:false → 0':s → 0':s → cond1:cond2
gr :: 0':s → 0':s → true:false
gr0 :: 0':s → true:false
false :: true:false
p :: 0':s → 0':s
0' :: 0':s
s :: 0':s → 0':s
hole_cond1:cond21_3 :: cond1:cond2
hole_true:false2_3 :: true:false
hole_0':s3_3 :: 0':s
gen_0':s4_3 :: Nat → 0':s

Generator Equations:
gen_0':s4_3(0) ⇔ 0'
gen_0':s4_3(+(x, 1)) ⇔ s(gen_0':s4_3(x))

The following defined symbols remain to be analysed:
gr, cond1, cond2

They will be analysed ascendingly in the following order:
cond1 = cond2
gr < cond1

(7) RewriteLemmaProof (LOWER BOUND(ID) transformation)

Proved the following rewrite lemma:
gr(gen_0':s4_3(n6_3), gen_0':s4_3(n6_3)) → false, rt ∈ Ω(1 + n63)

Induction Base:
gr(gen_0':s4_3(0), gen_0':s4_3(0)) →RΩ(1)
false

Induction Step:
gr(gen_0':s4_3(+(n6_3, 1)), gen_0':s4_3(+(n6_3, 1))) →RΩ(1)
gr(gen_0':s4_3(n6_3), gen_0':s4_3(n6_3)) →IH
false

We have rt ∈ Ω(n1) and sz ∈ O(n). Thus, we have ircR ∈ Ω(n).

(8) Complex Obligation (BEST)

(9) Obligation:

TRS:
Rules:
cond1(true, x, y) → cond2(gr(x, y), x, y)
cond2(true, x, y) → cond1(gr0(x), y, y)
cond2(false, x, y) → cond1(gr0(x), p(x), y)
gr(0', x) → false
gr(s(x), 0') → true
gr(s(x), s(y)) → gr(x, y)
gr0(0') → false
gr0(s(x)) → true
p(0') → 0'
p(s(x)) → x

Types:
cond1 :: true:false → 0':s → 0':s → cond1:cond2
true :: true:false
cond2 :: true:false → 0':s → 0':s → cond1:cond2
gr :: 0':s → 0':s → true:false
gr0 :: 0':s → true:false
false :: true:false
p :: 0':s → 0':s
0' :: 0':s
s :: 0':s → 0':s
hole_cond1:cond21_3 :: cond1:cond2
hole_true:false2_3 :: true:false
hole_0':s3_3 :: 0':s
gen_0':s4_3 :: Nat → 0':s

Lemmas:
gr(gen_0':s4_3(n6_3), gen_0':s4_3(n6_3)) → false, rt ∈ Ω(1 + n63)

Generator Equations:
gen_0':s4_3(0) ⇔ 0'
gen_0':s4_3(+(x, 1)) ⇔ s(gen_0':s4_3(x))

The following defined symbols remain to be analysed:
cond2, cond1

They will be analysed ascendingly in the following order:
cond1 = cond2

(10) NoRewriteLemmaProof (LOWER BOUND(ID) transformation)

Could not prove a rewrite lemma for the defined symbol cond2.

(11) Obligation:

TRS:
Rules:
cond1(true, x, y) → cond2(gr(x, y), x, y)
cond2(true, x, y) → cond1(gr0(x), y, y)
cond2(false, x, y) → cond1(gr0(x), p(x), y)
gr(0', x) → false
gr(s(x), 0') → true
gr(s(x), s(y)) → gr(x, y)
gr0(0') → false
gr0(s(x)) → true
p(0') → 0'
p(s(x)) → x

Types:
cond1 :: true:false → 0':s → 0':s → cond1:cond2
true :: true:false
cond2 :: true:false → 0':s → 0':s → cond1:cond2
gr :: 0':s → 0':s → true:false
gr0 :: 0':s → true:false
false :: true:false
p :: 0':s → 0':s
0' :: 0':s
s :: 0':s → 0':s
hole_cond1:cond21_3 :: cond1:cond2
hole_true:false2_3 :: true:false
hole_0':s3_3 :: 0':s
gen_0':s4_3 :: Nat → 0':s

Lemmas:
gr(gen_0':s4_3(n6_3), gen_0':s4_3(n6_3)) → false, rt ∈ Ω(1 + n63)

Generator Equations:
gen_0':s4_3(0) ⇔ 0'
gen_0':s4_3(+(x, 1)) ⇔ s(gen_0':s4_3(x))

The following defined symbols remain to be analysed:
cond1

They will be analysed ascendingly in the following order:
cond1 = cond2

(12) NoRewriteLemmaProof (LOWER BOUND(ID) transformation)

Could not prove a rewrite lemma for the defined symbol cond1.

(13) Obligation:

TRS:
Rules:
cond1(true, x, y) → cond2(gr(x, y), x, y)
cond2(true, x, y) → cond1(gr0(x), y, y)
cond2(false, x, y) → cond1(gr0(x), p(x), y)
gr(0', x) → false
gr(s(x), 0') → true
gr(s(x), s(y)) → gr(x, y)
gr0(0') → false
gr0(s(x)) → true
p(0') → 0'
p(s(x)) → x

Types:
cond1 :: true:false → 0':s → 0':s → cond1:cond2
true :: true:false
cond2 :: true:false → 0':s → 0':s → cond1:cond2
gr :: 0':s → 0':s → true:false
gr0 :: 0':s → true:false
false :: true:false
p :: 0':s → 0':s
0' :: 0':s
s :: 0':s → 0':s
hole_cond1:cond21_3 :: cond1:cond2
hole_true:false2_3 :: true:false
hole_0':s3_3 :: 0':s
gen_0':s4_3 :: Nat → 0':s

Lemmas:
gr(gen_0':s4_3(n6_3), gen_0':s4_3(n6_3)) → false, rt ∈ Ω(1 + n63)

Generator Equations:
gen_0':s4_3(0) ⇔ 0'
gen_0':s4_3(+(x, 1)) ⇔ s(gen_0':s4_3(x))

No more defined symbols left to analyse.

(14) LowerBoundsProof (EQUIVALENT transformation)

The lowerbound Ω(n1) was proven with the following lemma:
gr(gen_0':s4_3(n6_3), gen_0':s4_3(n6_3)) → false, rt ∈ Ω(1 + n63)

(15) BOUNDS(n^1, INF)

(16) Obligation:

TRS:
Rules:
cond1(true, x, y) → cond2(gr(x, y), x, y)
cond2(true, x, y) → cond1(gr0(x), y, y)
cond2(false, x, y) → cond1(gr0(x), p(x), y)
gr(0', x) → false
gr(s(x), 0') → true
gr(s(x), s(y)) → gr(x, y)
gr0(0') → false
gr0(s(x)) → true
p(0') → 0'
p(s(x)) → x

Types:
cond1 :: true:false → 0':s → 0':s → cond1:cond2
true :: true:false
cond2 :: true:false → 0':s → 0':s → cond1:cond2
gr :: 0':s → 0':s → true:false
gr0 :: 0':s → true:false
false :: true:false
p :: 0':s → 0':s
0' :: 0':s
s :: 0':s → 0':s
hole_cond1:cond21_3 :: cond1:cond2
hole_true:false2_3 :: true:false
hole_0':s3_3 :: 0':s
gen_0':s4_3 :: Nat → 0':s

Lemmas:
gr(gen_0':s4_3(n6_3), gen_0':s4_3(n6_3)) → false, rt ∈ Ω(1 + n63)

Generator Equations:
gen_0':s4_3(0) ⇔ 0'
gen_0':s4_3(+(x, 1)) ⇔ s(gen_0':s4_3(x))

No more defined symbols left to analyse.

(17) LowerBoundsProof (EQUIVALENT transformation)

The lowerbound Ω(n1) was proven with the following lemma:
gr(gen_0':s4_3(n6_3), gen_0':s4_3(n6_3)) → false, rt ∈ Ω(1 + n63)

(18) BOUNDS(n^1, INF)