We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict Trs: { f(s(x), y, y) -> f(y, x, s(x)) }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

We add the following weak dependency pairs:

Strict DPs: { f^#(s(x), y, y) -> c_1(f^#(y, x, s(x))) }

and mark the set of starting terms.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict DPs: { f^#(s(x), y, y) -> c_1(f^#(y, x, s(x))) }
Strict Trs: { f(s(x), y, y) -> f(y, x, s(x)) }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

No rule is usable, rules are removed from the input problem.

We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).

Strict DPs: { f^#(s(x), y, y) -> c_1(f^#(y, x, s(x))) }
Obligation:
  runtime complexity
Answer:
  YES(O(1),O(n^1))

The weightgap principle applies (using the following constant
growth matrix-interpretation)

The following argument positions are usable:
  none

TcT has computed the following constructor-restricted matrix
interpretation.

            [s](x1) = [0]
                      [0]
                         
  [f^#](x1, x2, x3) = [1]
                      [0]
                         
          [c_1](x1) = [0]
                      [0]

The order satisfies the following ordering constraints:

  [f^#(s(x), y, y)] = [1]                   
                      [0]                   
                    > [0]                   
                      [0]                   
                    = [c_1(f^#(y, x, s(x)))]
                                            

Further, it can be verified that all rules not oriented are covered by the weightgap condition.

We are left with following problem, upon which TcT provides the
certificate YES(?,O(n^1)).

Weak DPs: { f^#(s(x), y, y) -> c_1(f^#(y, x, s(x))) }
Obligation:
  runtime complexity
Answer:
  YES(?,O(n^1))

The following weak DPs constitute a sub-graph of the DG that is
closed under successors. The DPs are removed.

{ f^#(s(x), y, y) -> c_1(f^#(y, x, s(x))) }

We are left with following problem, upon which TcT provides the
certificate YES(?,O(n^1)).

Rules: Empty
Obligation:
  runtime complexity
Answer:
  YES(?,O(n^1))

We employ 'linear path analysis' using the following approximated
dependency graph:
empty


Hurray, we answered YES(O(1),O(n^1))