*** 1 Progress [(O(1),O(n^1))]  ***
    Considered Problem:
      Strict DP Rules:
        
      Strict TRS Rules:
        f(0()) -> s(0())
        f(s(0())) -> s(0())
        f(s(s(x))) -> f(f(s(x)))
      Weak DP Rules:
        
      Weak TRS Rules:
        
      Signature:
        {f/1} / {0/0,s/1}
      Obligation:
        Full
        basic terms: {f}/{0,s}
    Applied Processor:
      ToInnermost
    Proof:
      switch to innermost, as the system is overlay and right linear and does not contain weak rules
*** 1.1 Progress [(O(1),O(n^1))]  ***
    Considered Problem:
      Strict DP Rules:
        
      Strict TRS Rules:
        f(0()) -> s(0())
        f(s(0())) -> s(0())
        f(s(s(x))) -> f(f(s(x)))
      Weak DP Rules:
        
      Weak TRS Rules:
        
      Signature:
        {f/1} / {0/0,s/1}
      Obligation:
        Innermost
        basic terms: {f}/{0,s}
    Applied Processor:
      Bounds {initialAutomaton = perSymbol, enrichment = match}
    Proof:
      The problem is match-bounded by 2.
      The enriched problem is compatible with follwoing automaton.
        0_0() -> 1
        0_1() -> 4
        0_2() -> 7
        f_0(1) -> 2
        f_0(3) -> 2
        f_1(5) -> 2
        f_1(5) -> 5
        f_1(6) -> 5
        s_0(1) -> 3
        s_0(3) -> 3
        s_1(1) -> 6
        s_1(3) -> 6
        s_1(4) -> 2
        s_1(4) -> 5
        s_2(7) -> 2
        s_2(7) -> 5
*** 1.1.1 Progress [(O(1),O(1))]  ***
    Considered Problem:
      Strict DP Rules:
        
      Strict TRS Rules:
        
      Weak DP Rules:
        
      Weak TRS Rules:
        f(0()) -> s(0())
        f(s(0())) -> s(0())
        f(s(s(x))) -> f(f(s(x)))
      Signature:
        {f/1} / {0/0,s/1}
      Obligation:
        Innermost
        basic terms: {f}/{0,s}
    Applied Processor:
      EmptyProcessor
    Proof:
      The problem is already closed. The intended complexity is O(1).