We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).
Strict Trs:
{ f(0(), y) -> 0()
, f(s(x), y) -> f(f(x, y), y) }
Obligation:
runtime complexity
Answer:
YES(O(1),O(n^1))
We add the following weak dependency pairs:
Strict DPs:
{ f^#(0(), y) -> c_1()
, f^#(s(x), y) -> c_2(f^#(f(x, y), y)) }
and mark the set of starting terms.
We are left with following problem, upon which TcT provides the
certificate YES(O(1),O(n^1)).
Strict DPs:
{ f^#(0(), y) -> c_1()
, f^#(s(x), y) -> c_2(f^#(f(x, y), y)) }
Strict Trs:
{ f(0(), y) -> 0()
, f(s(x), y) -> f(f(x, y), y) }
Obligation:
runtime complexity
Answer:
YES(O(1),O(n^1))
The weightgap principle applies (using the following constant
growth matrix-interpretation)
The following argument positions are usable:
Uargs(f) = {1}, Uargs(f^#) = {1}, Uargs(c_2) = {1}
TcT has computed the following constructor-restricted matrix
interpretation.
[f](x1, x2) = [1 1] x1 + [0]
[0 0] [1]
[0] = [0]
[1]
[s](x1) = [1 0] x1 + [2]
[0 1] [2]
[f^#](x1, x2) = [1 1] x1 + [0]
[0 0] [0]
[c_1] = [0]
[0]
[c_2](x1) = [1 0] x1 + [0]
[0 1] [0]
The order satisfies the following ordering constraints:
[f(0(), y)] = [1]
[1]
> [0]
[1]
= [0()]
[f(s(x), y)] = [1 1] x + [4]
[0 0] [1]
> [1 1] x + [1]
[0 0] [1]
= [f(f(x, y), y)]
[f^#(0(), y)] = [1]
[0]
> [0]
[0]
= [c_1()]
[f^#(s(x), y)] = [1 1] x + [4]
[0 0] [0]
> [1 1] x + [1]
[0 0] [0]
= [c_2(f^#(f(x, y), y))]
Further, it can be verified that all rules not oriented are covered by the weightgap condition.
We are left with following problem, upon which TcT provides the
certificate YES(?,O(n^1)).
Weak DPs:
{ f^#(0(), y) -> c_1()
, f^#(s(x), y) -> c_2(f^#(f(x, y), y)) }
Weak Trs:
{ f(0(), y) -> 0()
, f(s(x), y) -> f(f(x, y), y) }
Obligation:
runtime complexity
Answer:
YES(?,O(n^1))
The following weak DPs constitute a sub-graph of the DG that is
closed under successors. The DPs are removed.
{ f^#(0(), y) -> c_1()
, f^#(s(x), y) -> c_2(f^#(f(x, y), y)) }
We are left with following problem, upon which TcT provides the
certificate YES(?,O(n^1)).
Weak Trs:
{ f(0(), y) -> 0()
, f(s(x), y) -> f(f(x, y), y) }
Obligation:
runtime complexity
Answer:
YES(?,O(n^1))
We employ 'linear path analysis' using the following approximated
dependency graph:
empty
Hurray, we answered YES(O(1),O(n^1))