Trying to load file: main.koat

Initial Control flow graph problem:
  Start location: f2
      0: f2 -> f300 : [], cost: 1
      1: f300 -> f300 : C'=free, [ free>=1 && B>=1+A ], cost: 1
      2: f300 -> f300 : C'=free_1, [ 0>=1+free_1 && B>=1+A ], cost: 1
      3: f300 -> f300 : B'=-1+B, C'=0, [ B>=1+A ], cost: 1
      4: f300 -> f1 : D'=free_2, [ A>=B ], cost: 1


Simplified the transitions:
  Start location: f2
      0: f2 -> f300 : [], cost: 1
      1: f300 -> f300 : C'=free, [ free>=1 && B>=1+A ], cost: 1
      2: f300 -> f300 : C'=free_1, [ 0>=1+free_1 && B>=1+A ], cost: 1
      3: f300 -> f300 : B'=-1+B, C'=0, [ B>=1+A ], cost: 1

Eliminating 3 self-loops for location f300
  Self-Loop 1 has unbounded runtime, resulting in the new transition 5.
  Self-Loop 2 has unbounded runtime, resulting in the new transition 6.
  Self-Loop 3 has the metering function: B-A, resulting in the new transition 7.
  Removing the self-loops: 1 2 3.

Removed all Self-loops using metering functions (where possible):
  Start location: f2
      0: f2 -> f300 : [], cost: 1
      5: f300 -> [3] : [ free>=1 && B>=1+A ], cost: INF
      6: f300 -> [3] : [ 0>=1+free_1 && B>=1+A ], cost: INF
      7: f300 -> [3] : B'=A, C'=0, [ B>=1+A ], cost: B-A


Applied chaining over branches and pruning:
  Start location: f2
      8: f2 -> [3] : [ free>=1 && B>=1+A ], cost: INF
      9: f2 -> [3] : [ 0>=1+free_1 && B>=1+A ], cost: INF
     10: f2 -> [3] : B'=A, C'=0, [ B>=1+A ], cost: 1+B-A


Final control flow graph problem, now checking costs for infinitely many models:
  Start location: f2
      8: f2 -> [3] : [ free>=1 && B>=1+A ], cost: INF
      9: f2 -> [3] : [ 0>=1+free_1 && B>=1+A ], cost: INF
     10: f2 -> [3] : B'=A, C'=0, [ B>=1+A ], cost: 1+B-A


Computing complexity for remaining 3 transitions.

Found new complexity INF, because: INF sat.


The final runtime is determined by this resulting transition:
  Final Guard: free>=1 && B>=1+A
  Final Cost:  INF

Obtained the following complexity w.r.t. the length of the input n:
  Complexity class: INF
  Complexity value: INF

WORST_CASE(INF,?)