Trying to load file: main.koat

Initial Control flow graph problem:
  Start location: f3
      0: f3 -> f2 : [], cost: 1
      1: f2 -> f2 : A'=-1+free, [ 0>=1+A && 0>=free_1 && B>=1 ], cost: 1
      2: f2 -> f2 : A'=-1+free_2, [ 0>=1+A && 0>=free_3 && 0>=B ], cost: 1
      3: f2 -> f2 : A'=1+free_4, [ free_5>=2 && 0>=1+A ], cost: 1
      4: f2 -> f2 : A'=-1+free_6, [ A>=1 && 0>=2+free_7 && B>=1 ], cost: 1
      5: f2 -> f2 : A'=-1+free_8, [ A>=1 && 0>=2+free_9 && 0>=B ], cost: 1
      6: f2 -> f2 : A'=1+free_10, [ free_11>=0 && A>=1 ], cost: 1
      7: f2 -> f300 : A'=0, C'=free_12, [ 0>=1+A ], cost: 1
      8: f2 -> f300 : A'=0, C'=free_13, [ A>=1 ], cost: 1
      9: f2 -> f300 : C'=free_14, [ A==0 ], cost: 1


Simplified the transitions:
  Start location: f3
      0: f3 -> f2 : [], cost: 1
      1: f2 -> f2 : A'=-1+free, [ 0>=1+A && B>=1 ], cost: 1
      2: f2 -> f2 : A'=-1+free_2, [ 0>=1+A && 0>=B ], cost: 1
      3: f2 -> f2 : A'=1+free_4, [ 0>=1+A ], cost: 1
      4: f2 -> f2 : A'=-1+free_6, [ A>=1 && B>=1 ], cost: 1
      5: f2 -> f2 : A'=-1+free_8, [ A>=1 && 0>=B ], cost: 1
      6: f2 -> f2 : A'=1+free_10, [ A>=1 ], cost: 1

Eliminating 6 self-loops for location f2
  Removing the self-loops: 1 2 3 4 5 6.
Adding an epsilon transition (to model nonexecution of the loops): 16.

Removed all Self-loops using metering functions (where possible):
  Start location: f3
      0: f3 -> f2 : [], cost: 1
     10: f2 -> [3] : A'=-1+free, [ 0>=1+A && B>=1 ], cost: 1
     11: f2 -> [3] : A'=-1+free_2, [ 0>=1+A && 0>=B ], cost: 1
     12: f2 -> [3] : A'=1+free_4, [ 0>=1+A ], cost: 1
     13: f2 -> [3] : A'=-1+free_6, [ A>=1 && B>=1 ], cost: 1
     14: f2 -> [3] : A'=-1+free_8, [ A>=1 && 0>=B ], cost: 1
     15: f2 -> [3] : A'=1+free_10, [ A>=1 ], cost: 1
     16: f2 -> [3] : [], cost: 0


Applied chaining over branches and pruning:
  Start location: f3
    <empty>


Final control flow graph problem, now checking costs for infinitely many models:
  Start location: f3
    <empty>


Computing complexity for remaining 0 transitions.


The final runtime is determined by this resulting transition:
  Final Guard: 
  Final Cost:  1

Obtained the following complexity w.r.t. the length of the input n:
  Complexity class: const
  Complexity value: 0

WORST_CASE(Omega(1),?)