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Initial Control flow graph problem:
  Start location: f1
      0: f1 -> f2 : [ A>=1 && B>=1 ], cost: 1
      1: f2 -> f2 : A'=-1+A, [ A>=2 && B>=1 ], cost: 1
      2: f2 -> f2 : B'=-1+B, [ A>=1 && B>=2 ], cost: 1

Eliminating 2 self-loops for location f2
  Self-Loop 1 has the metering function: -1+A, resulting in the new transition 3.
  Self-Loop 2 has the metering function: -1+B, resulting in the new transition 4.
  Removing the self-loops: 1 2.

Removed all Self-loops using metering functions (where possible):
  Start location: f1
      0: f1 -> f2 : [ A>=1 && B>=1 ], cost: 1
      3: f2 -> [2] : A'=1, [ A>=2 && B>=1 ], cost: -1+A
      4: f2 -> [2] : B'=1, [ A>=1 && B>=2 ], cost: -1+B


Applied chaining over branches and pruning:
  Start location: f1
      5: f1 -> [2] : A'=1, [ A>=1 && B>=1 && A>=2 && B>=1 ], cost: A
      6: f1 -> [2] : B'=1, [ A>=1 && B>=1 && A>=1 && B>=2 ], cost: B


Final control flow graph problem, now checking costs for infinitely many models:
  Start location: f1
      5: f1 -> [2] : A'=1, [ A>=1 && B>=1 && A>=2 && B>=1 ], cost: A
      6: f1 -> [2] : B'=1, [ A>=1 && B>=1 && A>=1 && B>=2 ], cost: B


Computing complexity for remaining 2 transitions.

  Found configuration with infinitely models for cost: A
  and guard: A>=1 && B>=1 && A>=2 && B>=1:
  B: Pos, A: Pos

Found new complexity n^1, because: Found infinity configuration.


The final runtime is determined by this resulting transition:
  Final Guard: A>=1 && B>=1 && A>=2 && B>=1
  Final Cost:  A

Obtained the following complexity w.r.t. the length of the input n:
  Complexity class: n^1
  Complexity value: 1

WORST_CASE(Omega(n^1),?)