Trying to load file: main.koat

Initial Control flow graph problem:
  Start location: f0
      0: f9 -> f15 : B'=0, C'=free, [ 0>=A && free>=1 ], cost: 1
      5: f9 -> f23 : [ A>=1 ], cost: 1
      4: f15 -> f9 : A'=free_1, D'=0, [ 0>=C ], cost: 1
      1: f15 -> f15 : [ C>=1 ], cost: 1
      2: f23 -> f23 : [], cost: 1
      3: f25 -> f28 : [], cost: 1
      6: f0 -> f9 : A'=free_2, B'=0, D'=0, [], cost: 1


Simplified the transitions:
  Start location: f0
      0: f9 -> f15 : B'=0, C'=free, [ 0>=A && free>=1 ], cost: 1
      5: f9 -> f23 : [ A>=1 ], cost: 1
      4: f15 -> f9 : A'=free_1, D'=0, [ 0>=C ], cost: 1
      1: f15 -> f15 : [ C>=1 ], cost: 1
      2: f23 -> f23 : [], cost: 1
      6: f0 -> f9 : A'=free_2, B'=0, D'=0, [], cost: 1

Eliminating 1 self-loops for location f15
  Self-Loop 1 has unbounded runtime, resulting in the new transition 7.
  Removing the self-loops: 1.
Eliminating 1 self-loops for location f23
  Self-Loop 2 has unbounded runtime, resulting in the new transition 8.
  Removing the self-loops: 2.

Removed all Self-loops using metering functions (where possible):
  Start location: f0
      0: f9 -> f15 : B'=0, C'=free, [ 0>=A && free>=1 ], cost: 1
      5: f9 -> f23 : [ A>=1 ], cost: 1
      7: f15 -> [6] : [ C>=1 ], cost: INF
      8: f23 -> [7] : [], cost: INF
      6: f0 -> f9 : A'=free_2, B'=0, D'=0, [], cost: 1
      4: [6] -> f9 : A'=free_1, D'=0, [ 0>=C ], cost: 1


Applied simple chaining:
  Start location: f0
      0: f9 -> [6] : B'=0, C'=free, [ 0>=A && free>=1 && free>=1 ], cost: INF
      5: f9 -> [7] : [ A>=1 ], cost: INF
      6: f0 -> f9 : A'=free_2, B'=0, D'=0, [], cost: 1
      4: [6] -> f9 : A'=free_1, D'=0, [ 0>=C ], cost: 1


Applied chaining over branches and pruning:
  Start location: f0
      5: f9 -> [7] : [ A>=1 ], cost: INF
      9: f9 -> [8] : B'=0, C'=free, [ 0>=A && free>=1 && free>=1 ], cost: INF
      6: f0 -> f9 : A'=free_2, B'=0, D'=0, [], cost: 1


Applied chaining over branches and pruning:
  Start location: f0
     10: f0 -> [7] : A'=free_2, B'=0, D'=0, [ free_2>=1 ], cost: INF
     11: f0 -> [8] : A'=free_2, B'=0, C'=free, D'=0, [ 0>=free_2 && free>=1 && free>=1 ], cost: INF


Final control flow graph problem, now checking costs for infinitely many models:
  Start location: f0
     10: f0 -> [7] : A'=free_2, B'=0, D'=0, [ free_2>=1 ], cost: INF
     11: f0 -> [8] : A'=free_2, B'=0, C'=free, D'=0, [ 0>=free_2 && free>=1 && free>=1 ], cost: INF


Computing complexity for remaining 2 transitions.

Found new complexity INF, because: INF sat.


The final runtime is determined by this resulting transition:
  Final Guard: free_2>=1
  Final Cost:  INF

Obtained the following complexity w.r.t. the length of the input n:
  Complexity class: INF
  Complexity value: INF

WORST_CASE(INF,?)