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Initial Control flow graph problem:
  Start location: f0
      0: f0 -> f1 : [], cost: 1
      1: f1 -> f1 : A'=-1+A, [ A>=202 ], cost: 1

Eliminating 1 self-loops for location f1
  Self-Loop 1 has the metering function: -201+A, resulting in the new transition 2.
  Removing the self-loops: 1.

Removed all Self-loops using metering functions (where possible):
  Start location: f0
      0: f0 -> f1 : [], cost: 1
      2: f1 -> [2] : A'=201, [ A>=202 ], cost: -201+A


Applied simple chaining:
  Start location: f0
      0: f0 -> [2] : A'=201, [ A>=202 ], cost: -200+A


Final control flow graph problem, now checking costs for infinitely many models:
  Start location: f0
      0: f0 -> [2] : A'=201, [ A>=202 ], cost: -200+A


Computing complexity for remaining 1 transitions.

  Found configuration with infinitely models for cost: -200+A
  and guard: A>=202:
  A: Pos

Found new complexity n^1, because: Found infinity configuration.


The final runtime is determined by this resulting transition:
  Final Guard: A>=202
  Final Cost:  -200+A

Obtained the following complexity w.r.t. the length of the input n:
  Complexity class: n^1
  Complexity value: 1

WORST_CASE(Omega(n^1),?)