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Initial Control flow graph problem:
  Start location: f
      0: f -> g : A'=1, B'=1, [], cost: 1
      1: g -> g : A'=B+A, B'=B+A, C'=-1+C, [ C>0 ], cost: 1
      2: g -> h : [ C<=0 ], cost: 1
      3: h -> h : B'=-1+B, [ B>0 ], cost: 1

Eliminating 1 self-loops for location g
  Self-Loop 1 has the metering function: C, resulting in the new transition 4.
  Removing the self-loops: 1.
Eliminating 1 self-loops for location h
  Self-Loop 3 has the metering function: B, resulting in the new transition 5.
  Removing the self-loops: 3.

Removed all Self-loops using metering functions (where possible):
  Start location: f
      0: f -> g : A'=1, B'=1, [], cost: 1
      4: g -> [3] : A'=2^C*A, B'=2^C*A, C'=0, [ C>0 && A==B ], cost: C
      5: h -> [4] : B'=0, [ B>0 ], cost: B
      2: [3] -> h : [ C<=0 ], cost: 1


Applied simple chaining:
  Start location: f
      0: f -> [4] : A'=2^C, B'=0, C'=0, [ C>0 && 1==1 && 0<=0 && 2^C>0 ], cost: 2+C+2^C


Final control flow graph problem, now checking costs for infinitely many models:
  Start location: f
      0: f -> [4] : A'=2^C, B'=0, C'=0, [ C>0 && 1==1 && 0<=0 && 2^C>0 ], cost: 2+C+2^C


Computing complexity for remaining 1 transitions.

  Found configuration with infinitely models for cost: 2+C+2^C
  and guard: C>0 && 1==1 && 0<=0 && 2^C>0:
  C: Pos

Found new complexity EXP, because: Found infinity configuration.


The final runtime is determined by this resulting transition:
  Final Guard: C>0 && 1==1 && 0<=0 && 2^C>0
  Final Cost:  2+C+2^C

Obtained the following complexity w.r.t. the length of the input n:
  Complexity class: EXP
  Complexity value: EXP

WORST_CASE(EXP,?)