Trying to load file: main.koat

Initial Control flow graph problem:
  Start location: start
      0: eval -> eval : B'=1+B, E'=1+E, [ A>=1+B && C>=1+D ], cost: 1
      1: eval -> eval : D'=1+D, E'=1+E, [ A>=1+B && C>=1+D ], cost: 1
      2: eval -> eval : D'=1+D, E'=1+E, [ B>=A && C>=1+D ], cost: 1
      3: eval -> eval : B'=1+B, E'=1+E, [ A>=1+B && D>=C ], cost: 1
      4: start -> eval : [], cost: 1

Eliminating 4 self-loops for location eval
  Self-Loop 0 has the metering function: -B+A, resulting in the new transition 5.
  Self-Loop 1 has the metering function: C-D, resulting in the new transition 6.
  Self-Loop 2 has the metering function: C-D, resulting in the new transition 7.
  Self-Loop 3 has the metering function: -B+A, resulting in the new transition 8.
  Found this metering function when nesting loops: -1-B+A,
  Found this metering function when nesting loops: -1+C-D,
  Removing the self-loops: 0 1 2 3.

Removed all Self-loops using metering functions (where possible):
  Start location: start
      5: eval -> [2] : B'=A, E'=E-B+A, [ A>=1+B && C>=1+D ], cost: -B+A
      6: eval -> [2] : D'=C, E'=E+C-D, [ A>=1+B && C>=1+D ], cost: C-D
      7: eval -> [2] : D'=C, E'=E+C-D, [ B>=A && C>=1+D ], cost: C-D
      8: eval -> [2] : B'=A, E'=E-B+A, [ A>=1+B && D>=C ], cost: -B+A
      4: start -> eval : [], cost: 1


Applied chaining over branches and pruning:
  Start location: start
      9: start -> [2] : B'=A, E'=E-B+A, [ A>=1+B && C>=1+D ], cost: 1-B+A
     10: start -> [2] : D'=C, E'=E+C-D, [ A>=1+B && C>=1+D ], cost: 1+C-D
     11: start -> [2] : D'=C, E'=E+C-D, [ B>=A && C>=1+D ], cost: 1+C-D
     12: start -> [2] : B'=A, E'=E-B+A, [ A>=1+B && D>=C ], cost: 1-B+A


Final control flow graph problem, now checking costs for infinitely many models:
  Start location: start
      9: start -> [2] : B'=A, E'=E-B+A, [ A>=1+B && C>=1+D ], cost: 1-B+A
     10: start -> [2] : D'=C, E'=E+C-D, [ A>=1+B && C>=1+D ], cost: 1+C-D
     11: start -> [2] : D'=C, E'=E+C-D, [ B>=A && C>=1+D ], cost: 1+C-D
     12: start -> [2] : B'=A, E'=E-B+A, [ A>=1+B && D>=C ], cost: 1-B+A


Computing complexity for remaining 4 transitions.

  Found configuration with infinitely models for cost: 1-B+A
  and guard: A>=1+B && C>=1+D:
  B: Pos, C: Pos, D: Pos, A: Pos, where: C > D A > B

Found new complexity n^1, because: Found infinity configuration.


The final runtime is determined by this resulting transition:
  Final Guard: A>=1+B && C>=1+D
  Final Cost:  1-B+A

Obtained the following complexity w.r.t. the length of the input n:
  Complexity class: n^1
  Complexity value: 1

WORST_CASE(Omega(n^1),?)