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Initial Control flow graph problem:
  Start location: start
      0: eval1 -> eval2 : [ A>=1 && B==A ], cost: 1
      2: eval2 -> eval1 : [ 0>=A ], cost: 1
      1: eval2 -> eval2 : A'=-1+A, B'=-1+B, [ A>=1 ], cost: 1
      3: start -> eval1 : [], cost: 1

Eliminating 1 self-loops for location eval2
  Self-Loop 1 has the metering function: A, resulting in the new transition 4.
  Removing the self-loops: 1.

Removed all Self-loops using metering functions (where possible):
  Start location: start
      0: eval1 -> eval2 : [ A>=1 && B==A ], cost: 1
      4: eval2 -> [3] : A'=0, B'=B-A, [ A>=1 ], cost: A
      3: start -> eval1 : [], cost: 1
      2: [3] -> eval1 : [ 0>=A ], cost: 1


Applied simple chaining:
  Start location: start
      0: eval1 -> eval1 : A'=0, B'=B-A, [ A>=1 && B==A && A>=1 && 0>=0 ], cost: 2+A
      3: start -> eval1 : [], cost: 1

Eliminating 1 self-loops for location eval1
  Removing the self-loops: 0.
Adding an epsilon transition (to model nonexecution of the loops): 6.

Removed all Self-loops using metering functions (where possible):
  Start location: start
      5: eval1 -> [4] : A'=0, B'=B-A, [ A>=1 && B==A ], cost: 2+A
      6: eval1 -> [4] : [], cost: 0
      3: start -> eval1 : [], cost: 1


Applied chaining over branches and pruning:
  Start location: start
      7: start -> [4] : A'=0, B'=B-A, [ A>=1 && B==A ], cost: 3+A


Final control flow graph problem, now checking costs for infinitely many models:
  Start location: start
      7: start -> [4] : A'=0, B'=B-A, [ A>=1 && B==A ], cost: 3+A


Computing complexity for remaining 1 transitions.

  Found configuration with infinitely models for cost: 3+A
  and guard: A>=1 && B==A:
  B: Both, A: Pos

Found new complexity n^1, because: Found infinity configuration.


The final runtime is determined by this resulting transition:
  Final Guard: A>=1 && B==A
  Final Cost:  3+A

Obtained the following complexity w.r.t. the length of the input n:
  Complexity class: n^1
  Complexity value: 1

WORST_CASE(Omega(n^1),?)