YES(?, 21*b + 6)

Initial complexity problem:
1:	T:
		(1, 1)    evalSequentialSinglestart(a, b) -> evalSequentialSingleentryin(a, b)
		(?, 1)    evalSequentialSingleentryin(a, b) -> evalSequentialSinglebb1in(0, b)
		(?, 1)    evalSequentialSinglebb1in(a, b) -> evalSequentialSinglebb5in(a, b) [ a >= b ]
		(?, 1)    evalSequentialSinglebb1in(a, b) -> evalSequentialSinglebb2in(a, b) [ b >= a + 1 ]
		(?, 1)    evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebbin(a, b) [ 0 >= c + 1 ]
		(?, 1)    evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebbin(a, b) [ c >= 1 ]
		(?, 1)    evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebb5in(a, b)
		(?, 1)    evalSequentialSinglebbin(a, b) -> evalSequentialSinglebb1in(a + 1, b)
		(?, 1)    evalSequentialSinglebb5in(a, b) -> evalSequentialSinglebb4in(a, b) [ b >= a + 1 ]
		(?, 1)    evalSequentialSinglebb5in(a, b) -> evalSequentialSinglereturnin(a, b) [ a >= b ]
		(?, 1)    evalSequentialSinglebb4in(a, b) -> evalSequentialSinglebb5in(a + 1, b)
		(?, 1)    evalSequentialSinglereturnin(a, b) -> evalSequentialSinglestop(a, b)
	start location:	evalSequentialSinglestart
	leaf cost:	0

Repeatedly removing leaves of the complexity graph in problem 1 produces the following problem:
2:	T:
		(1, 1)    evalSequentialSinglestart(a, b) -> evalSequentialSingleentryin(a, b)
		(?, 1)    evalSequentialSingleentryin(a, b) -> evalSequentialSinglebb1in(0, b)
		(?, 1)    evalSequentialSinglebb1in(a, b) -> evalSequentialSinglebb2in(a, b) [ b >= a + 1 ]
		(?, 1)    evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebbin(a, b) [ 0 >= c + 1 ]
		(?, 1)    evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebbin(a, b) [ c >= 1 ]
		(?, 1)    evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebb5in(a, b)
		(?, 1)    evalSequentialSinglebbin(a, b) -> evalSequentialSinglebb1in(a + 1, b)
		(?, 1)    evalSequentialSinglebb5in(a, b) -> evalSequentialSinglebb4in(a, b) [ b >= a + 1 ]
		(?, 1)    evalSequentialSinglebb4in(a, b) -> evalSequentialSinglebb5in(a + 1, b)
	start location:	evalSequentialSinglestart
	leaf cost:	3

Repeatedly propagating knowledge in problem 2 produces the following problem:
3:	T:
		(1, 1)    evalSequentialSinglestart(a, b) -> evalSequentialSingleentryin(a, b)
		(1, 1)    evalSequentialSingleentryin(a, b) -> evalSequentialSinglebb1in(0, b)
		(?, 1)    evalSequentialSinglebb1in(a, b) -> evalSequentialSinglebb2in(a, b) [ b >= a + 1 ]
		(?, 1)    evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebbin(a, b) [ 0 >= c + 1 ]
		(?, 1)    evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebbin(a, b) [ c >= 1 ]
		(?, 1)    evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebb5in(a, b)
		(?, 1)    evalSequentialSinglebbin(a, b) -> evalSequentialSinglebb1in(a + 1, b)
		(?, 1)    evalSequentialSinglebb5in(a, b) -> evalSequentialSinglebb4in(a, b) [ b >= a + 1 ]
		(?, 1)    evalSequentialSinglebb4in(a, b) -> evalSequentialSinglebb5in(a + 1, b)
	start location:	evalSequentialSinglestart
	leaf cost:	3

A polynomial rank function with
	Pol(evalSequentialSinglestart) = 1
	Pol(evalSequentialSingleentryin) = 1
	Pol(evalSequentialSinglebb1in) = 1
	Pol(evalSequentialSinglebb2in) = 1
	Pol(evalSequentialSinglebbin) = 1
	Pol(evalSequentialSinglebb5in) = -1
	Pol(evalSequentialSinglebb4in) = -1
orients all transitions weakly and the transition
	evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebb5in(a, b)
strictly and produces the following problem:
4:	T:
		(1, 1)    evalSequentialSinglestart(a, b) -> evalSequentialSingleentryin(a, b)
		(1, 1)    evalSequentialSingleentryin(a, b) -> evalSequentialSinglebb1in(0, b)
		(?, 1)    evalSequentialSinglebb1in(a, b) -> evalSequentialSinglebb2in(a, b) [ b >= a + 1 ]
		(?, 1)    evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebbin(a, b) [ 0 >= c + 1 ]
		(?, 1)    evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebbin(a, b) [ c >= 1 ]
		(1, 1)    evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebb5in(a, b)
		(?, 1)    evalSequentialSinglebbin(a, b) -> evalSequentialSinglebb1in(a + 1, b)
		(?, 1)    evalSequentialSinglebb5in(a, b) -> evalSequentialSinglebb4in(a, b) [ b >= a + 1 ]
		(?, 1)    evalSequentialSinglebb4in(a, b) -> evalSequentialSinglebb5in(a + 1, b)
	start location:	evalSequentialSinglestart
	leaf cost:	3

A polynomial rank function with
	Pol(evalSequentialSinglestart) = 3*V_2
	Pol(evalSequentialSingleentryin) = 3*V_2
	Pol(evalSequentialSinglebb1in) = -3*V_1 + 3*V_2
	Pol(evalSequentialSinglebb2in) = -3*V_1 + 3*V_2 - 1
	Pol(evalSequentialSinglebbin) = -3*V_1 + 3*V_2 - 2
	Pol(evalSequentialSinglebb5in) = -3*V_1 + 3*V_2 - 1
	Pol(evalSequentialSinglebb4in) = -3*V_1 + 3*V_2 - 2
orients all transitions weakly and the transitions
	evalSequentialSinglebb5in(a, b) -> evalSequentialSinglebb4in(a, b) [ b >= a + 1 ]
	evalSequentialSinglebb1in(a, b) -> evalSequentialSinglebb2in(a, b) [ b >= a + 1 ]
strictly and produces the following problem:
5:	T:
		(1, 1)      evalSequentialSinglestart(a, b) -> evalSequentialSingleentryin(a, b)
		(1, 1)      evalSequentialSingleentryin(a, b) -> evalSequentialSinglebb1in(0, b)
		(3*b, 1)    evalSequentialSinglebb1in(a, b) -> evalSequentialSinglebb2in(a, b) [ b >= a + 1 ]
		(?, 1)      evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebbin(a, b) [ 0 >= c + 1 ]
		(?, 1)      evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebbin(a, b) [ c >= 1 ]
		(1, 1)      evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebb5in(a, b)
		(?, 1)      evalSequentialSinglebbin(a, b) -> evalSequentialSinglebb1in(a + 1, b)
		(3*b, 1)    evalSequentialSinglebb5in(a, b) -> evalSequentialSinglebb4in(a, b) [ b >= a + 1 ]
		(?, 1)      evalSequentialSinglebb4in(a, b) -> evalSequentialSinglebb5in(a + 1, b)
	start location:	evalSequentialSinglestart
	leaf cost:	3

Repeatedly propagating knowledge in problem 5 produces the following problem:
6:	T:
		(1, 1)      evalSequentialSinglestart(a, b) -> evalSequentialSingleentryin(a, b)
		(1, 1)      evalSequentialSingleentryin(a, b) -> evalSequentialSinglebb1in(0, b)
		(3*b, 1)    evalSequentialSinglebb1in(a, b) -> evalSequentialSinglebb2in(a, b) [ b >= a + 1 ]
		(3*b, 1)    evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebbin(a, b) [ 0 >= c + 1 ]
		(3*b, 1)    evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebbin(a, b) [ c >= 1 ]
		(1, 1)      evalSequentialSinglebb2in(a, b) -> evalSequentialSinglebb5in(a, b)
		(6*b, 1)    evalSequentialSinglebbin(a, b) -> evalSequentialSinglebb1in(a + 1, b)
		(3*b, 1)    evalSequentialSinglebb5in(a, b) -> evalSequentialSinglebb4in(a, b) [ b >= a + 1 ]
		(3*b, 1)    evalSequentialSinglebb4in(a, b) -> evalSequentialSinglebb5in(a + 1, b)
	start location:	evalSequentialSinglestart
	leaf cost:	3

Complexity upper bound 21*b + 6

Time: 0.199 sec (SMT: 0.189 sec)