MAYBE

Initial complexity problem:
1:	T:
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ 0 >= a + 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ a >= 1 ]
		(?, 1)    f6(a, b, c) -> f17(0, b, c) [ a = 0 ]
		(?, 1)    f17(a, b, c) -> f24(a, b, c) [ 0 >= c ]
		(?, 1)    f17(a, b, c) -> f24(a, b, c) [ c >= 2 ]
		(?, 1)    f17(a, b, c) -> f24(a, b, 0) [ c = 1 ]
		(?, 1)    f9(a, b, c) -> f17(a, 0, 1) [ b = 0 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ 0 >= b + 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ b >= 1 ]
		(1, 1)    f0(a, b, c) -> f6(d, b, 0)
	start location:	f0
	leaf cost:	0

Repeatedly removing leaves of the complexity graph in problem 1 produces the following problem:
2:	T:
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ 0 >= a + 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ a >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ 0 >= b + 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ b >= 1 ]
		(1, 1)    f0(a, b, c) -> f6(d, b, 0)
	start location:	f0
	leaf cost:	5

Applied AI with 'oct' on problem 2 to obtain the following invariants:
  For symbol f6: -X_3 >= 0 /\ X_3 >= 0
  For symbol f9: -X_3 >= 0 /\ X_3 >= 0


This yielded the following problem:
3:	T:
		(1, 1)    f0(a, b, c) -> f6(d, b, 0)
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f6(d, b, 0) with all transitions in problem 3, the following new transitions are obtained:
	f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ 0 >= d + 1 ]
	f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
We thus obtain the following problem:
4:	T:
		(1, 2)    f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ 0 >= d + 1 ]
		(1, 2)    f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ 0 >= d + 1 ] with all transitions in problem 4, the following new transitions are obtained:
	f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 ]
	f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
We thus obtain the following problem:
5:	T:
		(1, 3)    f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 ]
		(1, 3)    f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
		(1, 2)    f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 ] with all transitions in problem 5, the following new transitions are obtained:
	f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 ]
	f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ d'' >= 1 ]
We thus obtain the following problem:
6:	T:
		(1, 4)    f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 ]
		(1, 4)    f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ d'' >= 1 ]
		(1, 3)    f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
		(1, 2)    f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 ] with all transitions in problem 6, the following new transitions are obtained:
	f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 ]
	f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ d''' >= 1 ]
We thus obtain the following problem:
7:	T:
		(1, 5)    f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 ]
		(1, 5)    f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ d''' >= 1 ]
		(1, 4)    f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ d'' >= 1 ]
		(1, 3)    f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
		(1, 2)    f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 ] with all transitions in problem 7, the following new transitions are obtained:
	f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 ]
	f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ d'''' >= 1 ]
We thus obtain the following problem:
8:	T:
		(1, 6)    f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 ]
		(1, 6)    f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ d'''' >= 1 ]
		(1, 5)    f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ d''' >= 1 ]
		(1, 4)    f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ d'' >= 1 ]
		(1, 3)    f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
		(1, 2)    f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 ] with all transitions in problem 8, the following new transitions are obtained:
	f0(a, b, c) -> f6(d'''''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 ]
	f0(a, b, c) -> f6(d'''''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ d''''' >= 1 ]
We thus obtain the following problem:
9:	T:
		(1, 7)    f0(a, b, c) -> f6(d'''''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 ]
		(1, 7)    f0(a, b, c) -> f6(d'''''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ d''''' >= 1 ]
		(1, 6)    f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ d'''' >= 1 ]
		(1, 5)    f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ d''' >= 1 ]
		(1, 4)    f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ d'' >= 1 ]
		(1, 3)    f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
		(1, 2)    f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f6(d'''''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 ] with all transitions in problem 9, the following new transitions are obtained:
	f0(a, b, c) -> f9(d'''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 ]
	f0(a, b, c) -> f9(d'''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ d'''''' >= 1 ]
We thus obtain the following problem:
10:	T:
		(1, 8)    f0(a, b, c) -> f9(d'''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 ]
		(1, 8)    f0(a, b, c) -> f9(d'''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ d'''''' >= 1 ]
		(1, 7)    f0(a, b, c) -> f6(d'''''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ d''''' >= 1 ]
		(1, 6)    f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ d'''' >= 1 ]
		(1, 5)    f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ d''' >= 1 ]
		(1, 4)    f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ d'' >= 1 ]
		(1, 3)    f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
		(1, 2)    f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f9(d'''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 ] with all transitions in problem 10, the following new transitions are obtained:
	f0(a, b, c) -> f6(d'''''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 ]
	f0(a, b, c) -> f6(d'''''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ d''''''' >= 1 ]
We thus obtain the following problem:
11:	T:
		(1, 9)    f0(a, b, c) -> f6(d'''''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 ]
		(1, 9)    f0(a, b, c) -> f6(d'''''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ d''''''' >= 1 ]
		(1, 8)    f0(a, b, c) -> f9(d'''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ d'''''' >= 1 ]
		(1, 7)    f0(a, b, c) -> f6(d'''''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ d''''' >= 1 ]
		(1, 6)    f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ d'''' >= 1 ]
		(1, 5)    f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ d''' >= 1 ]
		(1, 4)    f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ d'' >= 1 ]
		(1, 3)    f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
		(1, 2)    f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)    f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)    f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f6(d'''''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 ] with all transitions in problem 11, the following new transitions are obtained:
	f0(a, b, c) -> f9(d'''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 ]
	f0(a, b, c) -> f9(d'''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ d'''''''' >= 1 ]
We thus obtain the following problem:
12:	T:
		(1, 10)    f0(a, b, c) -> f9(d'''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 ]
		(1, 10)    f0(a, b, c) -> f9(d'''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ d'''''''' >= 1 ]
		(1, 9)     f0(a, b, c) -> f6(d'''''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ d''''''' >= 1 ]
		(1, 8)     f0(a, b, c) -> f9(d'''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ d'''''' >= 1 ]
		(1, 7)     f0(a, b, c) -> f6(d'''''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ d''''' >= 1 ]
		(1, 6)     f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ d'''' >= 1 ]
		(1, 5)     f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ d''' >= 1 ]
		(1, 4)     f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ d'' >= 1 ]
		(1, 3)     f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
		(1, 2)     f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)     f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)     f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)     f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)     f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f9(d'''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 ] with all transitions in problem 12, the following new transitions are obtained:
	f0(a, b, c) -> f6(d'''''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 ]
	f0(a, b, c) -> f6(d'''''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ d''''''''' >= 1 ]
We thus obtain the following problem:
13:	T:
		(1, 11)    f0(a, b, c) -> f6(d'''''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 ]
		(1, 11)    f0(a, b, c) -> f6(d'''''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ d''''''''' >= 1 ]
		(1, 10)    f0(a, b, c) -> f9(d'''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ d'''''''' >= 1 ]
		(1, 9)     f0(a, b, c) -> f6(d'''''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ d''''''' >= 1 ]
		(1, 8)     f0(a, b, c) -> f9(d'''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ d'''''' >= 1 ]
		(1, 7)     f0(a, b, c) -> f6(d'''''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ d''''' >= 1 ]
		(1, 6)     f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ d'''' >= 1 ]
		(1, 5)     f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ d''' >= 1 ]
		(1, 4)     f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ d'' >= 1 ]
		(1, 3)     f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
		(1, 2)     f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)     f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)     f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)     f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)     f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f6(d'''''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 ] with all transitions in problem 13, the following new transitions are obtained:
	f0(a, b, c) -> f9(d'''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 ]
	f0(a, b, c) -> f9(d'''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ d'''''''''' >= 1 ]
We thus obtain the following problem:
14:	T:
		(1, 12)    f0(a, b, c) -> f9(d'''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 ]
		(1, 12)    f0(a, b, c) -> f9(d'''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ d'''''''''' >= 1 ]
		(1, 11)    f0(a, b, c) -> f6(d'''''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ d''''''''' >= 1 ]
		(1, 10)    f0(a, b, c) -> f9(d'''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ d'''''''' >= 1 ]
		(1, 9)     f0(a, b, c) -> f6(d'''''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ d''''''' >= 1 ]
		(1, 8)     f0(a, b, c) -> f9(d'''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ d'''''' >= 1 ]
		(1, 7)     f0(a, b, c) -> f6(d'''''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ d''''' >= 1 ]
		(1, 6)     f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ d'''' >= 1 ]
		(1, 5)     f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ d''' >= 1 ]
		(1, 4)     f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ d'' >= 1 ]
		(1, 3)     f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
		(1, 2)     f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)     f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)     f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)     f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)     f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f9(d'''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 ] with all transitions in problem 14, the following new transitions are obtained:
	f0(a, b, c) -> f6(d'''''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 ]
	f0(a, b, c) -> f6(d'''''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ d''''''''''' >= 1 ]
We thus obtain the following problem:
15:	T:
		(1, 13)    f0(a, b, c) -> f6(d'''''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 ]
		(1, 13)    f0(a, b, c) -> f6(d'''''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ d''''''''''' >= 1 ]
		(1, 12)    f0(a, b, c) -> f9(d'''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ d'''''''''' >= 1 ]
		(1, 11)    f0(a, b, c) -> f6(d'''''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ d''''''''' >= 1 ]
		(1, 10)    f0(a, b, c) -> f9(d'''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ d'''''''' >= 1 ]
		(1, 9)     f0(a, b, c) -> f6(d'''''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ d''''''' >= 1 ]
		(1, 8)     f0(a, b, c) -> f9(d'''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ d'''''' >= 1 ]
		(1, 7)     f0(a, b, c) -> f6(d'''''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ d''''' >= 1 ]
		(1, 6)     f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ d'''' >= 1 ]
		(1, 5)     f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ d''' >= 1 ]
		(1, 4)     f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ d'' >= 1 ]
		(1, 3)     f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
		(1, 2)     f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)     f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)     f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)     f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)     f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f6(d'''''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 ] with all transitions in problem 15, the following new transitions are obtained:
	f0(a, b, c) -> f9(d'''''''''''', d''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ 0 >= d'''''''''''' + 1 ]
	f0(a, b, c) -> f9(d'''''''''''', d''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ d'''''''''''' >= 1 ]
We thus obtain the following problem:
16:	T:
		(1, 14)    f0(a, b, c) -> f9(d'''''''''''', d''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ 0 >= d'''''''''''' + 1 ]
		(1, 14)    f0(a, b, c) -> f9(d'''''''''''', d''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ d'''''''''''' >= 1 ]
		(1, 13)    f0(a, b, c) -> f6(d'''''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ d''''''''''' >= 1 ]
		(1, 12)    f0(a, b, c) -> f9(d'''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ d'''''''''' >= 1 ]
		(1, 11)    f0(a, b, c) -> f6(d'''''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ d''''''''' >= 1 ]
		(1, 10)    f0(a, b, c) -> f9(d'''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ d'''''''' >= 1 ]
		(1, 9)     f0(a, b, c) -> f6(d'''''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ d''''''' >= 1 ]
		(1, 8)     f0(a, b, c) -> f9(d'''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ d'''''' >= 1 ]
		(1, 7)     f0(a, b, c) -> f6(d'''''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ d''''' >= 1 ]
		(1, 6)     f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ d'''' >= 1 ]
		(1, 5)     f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ d''' >= 1 ]
		(1, 4)     f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ d'' >= 1 ]
		(1, 3)     f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
		(1, 2)     f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)     f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)     f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)     f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)     f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f9(d'''''''''''', d''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ 0 >= d'''''''''''' + 1 ] with all transitions in problem 16, the following new transitions are obtained:
	f0(a, b, c) -> f6(d'''''''''''''', d''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ 0 >= d'''''''''''' + 1 /\ 0 >= d''''''''''''' + 1 ]
	f0(a, b, c) -> f6(d'''''''''''''', d''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ 0 >= d'''''''''''' + 1 /\ d''''''''''''' >= 1 ]
We thus obtain the following problem:
17:	T:
		(1, 15)    f0(a, b, c) -> f6(d'''''''''''''', d''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ 0 >= d'''''''''''' + 1 /\ 0 >= d''''''''''''' + 1 ]
		(1, 15)    f0(a, b, c) -> f6(d'''''''''''''', d''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ 0 >= d'''''''''''' + 1 /\ d''''''''''''' >= 1 ]
		(1, 14)    f0(a, b, c) -> f9(d'''''''''''', d''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ d'''''''''''' >= 1 ]
		(1, 13)    f0(a, b, c) -> f6(d'''''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ d''''''''''' >= 1 ]
		(1, 12)    f0(a, b, c) -> f9(d'''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ d'''''''''' >= 1 ]
		(1, 11)    f0(a, b, c) -> f6(d'''''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ d''''''''' >= 1 ]
		(1, 10)    f0(a, b, c) -> f9(d'''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ d'''''''' >= 1 ]
		(1, 9)     f0(a, b, c) -> f6(d'''''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ d''''''' >= 1 ]
		(1, 8)     f0(a, b, c) -> f9(d'''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ d'''''' >= 1 ]
		(1, 7)     f0(a, b, c) -> f6(d'''''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ d''''' >= 1 ]
		(1, 6)     f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ d'''' >= 1 ]
		(1, 5)     f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ d''' >= 1 ]
		(1, 4)     f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ d'' >= 1 ]
		(1, 3)     f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
		(1, 2)     f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)     f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)     f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)     f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)     f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

By chaining the transition f0(a, b, c) -> f6(d'''''''''''''', d''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ 0 >= d'''''''''''' + 1 /\ 0 >= d''''''''''''' + 1 ] with all transitions in problem 17, the following new transitions are obtained:
	f0(a, b, c) -> f9(d'''''''''''''', d''''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ 0 >= d'''''''''''' + 1 /\ 0 >= d''''''''''''' + 1 /\ 0 >= d'''''''''''''' + 1 ]
	f0(a, b, c) -> f9(d'''''''''''''', d''''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ 0 >= d'''''''''''' + 1 /\ 0 >= d''''''''''''' + 1 /\ d'''''''''''''' >= 1 ]
We thus obtain the following problem:
18:	T:
		(1, 16)    f0(a, b, c) -> f9(d'''''''''''''', d''''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ 0 >= d'''''''''''' + 1 /\ 0 >= d''''''''''''' + 1 /\ 0 >= d'''''''''''''' + 1 ]
		(1, 16)    f0(a, b, c) -> f9(d'''''''''''''', d''''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ 0 >= d'''''''''''' + 1 /\ 0 >= d''''''''''''' + 1 /\ d'''''''''''''' >= 1 ]
		(1, 15)    f0(a, b, c) -> f6(d'''''''''''''', d''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ 0 >= d'''''''''''' + 1 /\ d''''''''''''' >= 1 ]
		(1, 14)    f0(a, b, c) -> f9(d'''''''''''', d''''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ 0 >= d''''''''''' + 1 /\ d'''''''''''' >= 1 ]
		(1, 13)    f0(a, b, c) -> f6(d'''''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ 0 >= d'''''''''' + 1 /\ d''''''''''' >= 1 ]
		(1, 12)    f0(a, b, c) -> f9(d'''''''''', d''''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ 0 >= d''''''''' + 1 /\ d'''''''''' >= 1 ]
		(1, 11)    f0(a, b, c) -> f6(d'''''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ 0 >= d'''''''' + 1 /\ d''''''''' >= 1 ]
		(1, 10)    f0(a, b, c) -> f9(d'''''''', d''''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ 0 >= d''''''' + 1 /\ d'''''''' >= 1 ]
		(1, 9)     f0(a, b, c) -> f6(d'''''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ 0 >= d'''''' + 1 /\ d''''''' >= 1 ]
		(1, 8)     f0(a, b, c) -> f9(d'''''', d''''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ 0 >= d''''' + 1 /\ d'''''' >= 1 ]
		(1, 7)     f0(a, b, c) -> f6(d'''''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ 0 >= d'''' + 1 /\ d''''' >= 1 ]
		(1, 6)     f0(a, b, c) -> f9(d'''', d''''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ 0 >= d''' + 1 /\ d'''' >= 1 ]
		(1, 5)     f0(a, b, c) -> f6(d'''', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ 0 >= d'' + 1 /\ d''' >= 1 ]
		(1, 4)     f0(a, b, c) -> f9(d'', d''', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ 0 >= d' + 1 /\ d'' >= 1 ]
		(1, 3)     f0(a, b, c) -> f6(d'', d', 0) [ 0 >= 0 /\ 0 >= d + 1 /\ d' >= 1 ]
		(1, 2)     f0(a, b, c) -> f9(d, d', 0) [ 0 >= 0 /\ d >= 1 ]
		(?, 1)     f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ b >= 1 ]
		(?, 1)     f9(a, b, c) -> f6(d, b, c) [ -c >= 0 /\ c >= 0 /\ 0 >= b + 1 ]
		(?, 1)     f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ a >= 1 ]
		(?, 1)     f6(a, b, c) -> f9(a, d, c) [ -c >= 0 /\ c >= 0 /\ 0 >= a + 1 ]
	start location:	f0
	leaf cost:	5

Complexity upper bound ?

Time: 1.603 sec (SMT: 1.416 sec)