MAYBE

Initial complexity problem:
1:	T:
		(1, 1)    f1(a, b) -> f2(a, b) [ 0 >= a + b + 1 /\ a >= 1 ]
		(?, 1)    f2(a, b) -> f2(a - b, b) [ a >= 0 ]
		(?, 1)    f2(a, b) -> f3(a, b) [ 0 >= a + 1 ]
	start location:	f1
	leaf cost:	0

Repeatedly removing leaves of the complexity graph in problem 1 produces the following problem:
2:	T:
		(1, 1)    f1(a, b) -> f2(a, b) [ 0 >= a + b + 1 /\ a >= 1 ]
		(?, 1)    f2(a, b) -> f2(a - b, b) [ a >= 0 ]
	start location:	f1
	leaf cost:	1

Applied AI with 'oct' on problem 2 to obtain the following invariants:
  For symbol f2: -X_2 - 2 >= 0 /\ X_1 - X_2 - 3 >= 0 /\ X_1 - 1 >= 0


This yielded the following problem:
3:	T:
		(?, 1)    f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
		(1, 1)    f1(a, b) -> f2(a, b) [ 0 >= a + b + 1 /\ a >= 1 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a, b) [ 0 >= a + b + 1 /\ a >= 1 ] with all transitions in problem 3, the following new transition is obtained:
	f1(a, b) -> f2(a - b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
We thus obtain the following problem:
4:	T:
		(1, 2)    f1(a, b) -> f2(a - b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
		(?, 1)    f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a - b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ] with all transitions in problem 4, the following new transition is obtained:
	f1(a, b) -> f2(a - 2*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 ]
We thus obtain the following problem:
5:	T:
		(1, 3)    f1(a, b) -> f2(a - 2*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 ]
		(?, 1)    f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a - 2*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 ] with all transitions in problem 5, the following new transition is obtained:
	f1(a, b) -> f2(a - 3*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 ]
We thus obtain the following problem:
6:	T:
		(1, 4)    f1(a, b) -> f2(a - 3*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 ]
		(?, 1)    f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a - 3*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 ] with all transitions in problem 6, the following new transition is obtained:
	f1(a, b) -> f2(a - 4*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 ]
We thus obtain the following problem:
7:	T:
		(1, 5)    f1(a, b) -> f2(a - 4*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 ]
		(?, 1)    f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a - 4*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 ] with all transitions in problem 7, the following new transition is obtained:
	f1(a, b) -> f2(a - 5*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 ]
We thus obtain the following problem:
8:	T:
		(1, 6)    f1(a, b) -> f2(a - 5*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 ]
		(?, 1)    f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a - 5*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 ] with all transitions in problem 8, the following new transition is obtained:
	f1(a, b) -> f2(a - 6*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 ]
We thus obtain the following problem:
9:	T:
		(1, 7)    f1(a, b) -> f2(a - 6*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 ]
		(?, 1)    f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a - 6*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 ] with all transitions in problem 9, the following new transition is obtained:
	f1(a, b) -> f2(a - 7*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 ]
We thus obtain the following problem:
10:	T:
		(1, 8)    f1(a, b) -> f2(a - 7*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 ]
		(?, 1)    f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a - 7*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 ] with all transitions in problem 10, the following new transition is obtained:
	f1(a, b) -> f2(a - 8*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 ]
We thus obtain the following problem:
11:	T:
		(1, 9)    f1(a, b) -> f2(a - 8*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 ]
		(?, 1)    f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a - 8*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 ] with all transitions in problem 11, the following new transition is obtained:
	f1(a, b) -> f2(a - 9*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 ]
We thus obtain the following problem:
12:	T:
		(1, 10)    f1(a, b) -> f2(a - 9*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 ]
		(?, 1)     f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a - 9*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 ] with all transitions in problem 12, the following new transition is obtained:
	f1(a, b) -> f2(a - 10*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 ]
We thus obtain the following problem:
13:	T:
		(1, 11)    f1(a, b) -> f2(a - 10*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 ]
		(?, 1)     f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a - 10*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 ] with all transitions in problem 13, the following new transition is obtained:
	f1(a, b) -> f2(a - 11*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 /\ a - 11*b - 3 >= 0 /\ a - 10*b - 1 >= 0 /\ a - 10*b >= 0 ]
We thus obtain the following problem:
14:	T:
		(1, 12)    f1(a, b) -> f2(a - 11*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 /\ a - 11*b - 3 >= 0 /\ a - 10*b - 1 >= 0 /\ a - 10*b >= 0 ]
		(?, 1)     f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a - 11*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 /\ a - 11*b - 3 >= 0 /\ a - 10*b - 1 >= 0 /\ a - 10*b >= 0 ] with all transitions in problem 14, the following new transition is obtained:
	f1(a, b) -> f2(a - 12*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 /\ a - 11*b - 3 >= 0 /\ a - 10*b - 1 >= 0 /\ a - 10*b >= 0 /\ a - 12*b - 3 >= 0 /\ a - 11*b - 1 >= 0 /\ a - 11*b >= 0 ]
We thus obtain the following problem:
15:	T:
		(1, 13)    f1(a, b) -> f2(a - 12*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 /\ a - 11*b - 3 >= 0 /\ a - 10*b - 1 >= 0 /\ a - 10*b >= 0 /\ a - 12*b - 3 >= 0 /\ a - 11*b - 1 >= 0 /\ a - 11*b >= 0 ]
		(?, 1)     f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a - 12*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 /\ a - 11*b - 3 >= 0 /\ a - 10*b - 1 >= 0 /\ a - 10*b >= 0 /\ a - 12*b - 3 >= 0 /\ a - 11*b - 1 >= 0 /\ a - 11*b >= 0 ] with all transitions in problem 15, the following new transition is obtained:
	f1(a, b) -> f2(a - 13*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 /\ a - 11*b - 3 >= 0 /\ a - 10*b - 1 >= 0 /\ a - 10*b >= 0 /\ a - 12*b - 3 >= 0 /\ a - 11*b - 1 >= 0 /\ a - 11*b >= 0 /\ a - 13*b - 3 >= 0 /\ a - 12*b - 1 >= 0 /\ a - 12*b >= 0 ]
We thus obtain the following problem:
16:	T:
		(1, 14)    f1(a, b) -> f2(a - 13*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 /\ a - 11*b - 3 >= 0 /\ a - 10*b - 1 >= 0 /\ a - 10*b >= 0 /\ a - 12*b - 3 >= 0 /\ a - 11*b - 1 >= 0 /\ a - 11*b >= 0 /\ a - 13*b - 3 >= 0 /\ a - 12*b - 1 >= 0 /\ a - 12*b >= 0 ]
		(?, 1)     f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a - 13*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 /\ a - 11*b - 3 >= 0 /\ a - 10*b - 1 >= 0 /\ a - 10*b >= 0 /\ a - 12*b - 3 >= 0 /\ a - 11*b - 1 >= 0 /\ a - 11*b >= 0 /\ a - 13*b - 3 >= 0 /\ a - 12*b - 1 >= 0 /\ a - 12*b >= 0 ] with all transitions in problem 16, the following new transition is obtained:
	f1(a, b) -> f2(a - 14*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 /\ a - 11*b - 3 >= 0 /\ a - 10*b - 1 >= 0 /\ a - 10*b >= 0 /\ a - 12*b - 3 >= 0 /\ a - 11*b - 1 >= 0 /\ a - 11*b >= 0 /\ a - 13*b - 3 >= 0 /\ a - 12*b - 1 >= 0 /\ a - 12*b >= 0 /\ a - 14*b - 3 >= 0 /\ a - 13*b - 1 >= 0 /\ a - 13*b >= 0 ]
We thus obtain the following problem:
17:	T:
		(1, 15)    f1(a, b) -> f2(a - 14*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 /\ a - 11*b - 3 >= 0 /\ a - 10*b - 1 >= 0 /\ a - 10*b >= 0 /\ a - 12*b - 3 >= 0 /\ a - 11*b - 1 >= 0 /\ a - 11*b >= 0 /\ a - 13*b - 3 >= 0 /\ a - 12*b - 1 >= 0 /\ a - 12*b >= 0 /\ a - 14*b - 3 >= 0 /\ a - 13*b - 1 >= 0 /\ a - 13*b >= 0 ]
		(?, 1)     f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

By chaining the transition f1(a, b) -> f2(a - 14*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 /\ a - 11*b - 3 >= 0 /\ a - 10*b - 1 >= 0 /\ a - 10*b >= 0 /\ a - 12*b - 3 >= 0 /\ a - 11*b - 1 >= 0 /\ a - 11*b >= 0 /\ a - 13*b - 3 >= 0 /\ a - 12*b - 1 >= 0 /\ a - 12*b >= 0 /\ a - 14*b - 3 >= 0 /\ a - 13*b - 1 >= 0 /\ a - 13*b >= 0 ] with all transitions in problem 17, the following new transition is obtained:
	f1(a, b) -> f2(a - 15*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 /\ a - 11*b - 3 >= 0 /\ a - 10*b - 1 >= 0 /\ a - 10*b >= 0 /\ a - 12*b - 3 >= 0 /\ a - 11*b - 1 >= 0 /\ a - 11*b >= 0 /\ a - 13*b - 3 >= 0 /\ a - 12*b - 1 >= 0 /\ a - 12*b >= 0 /\ a - 14*b - 3 >= 0 /\ a - 13*b - 1 >= 0 /\ a - 13*b >= 0 /\ a - 15*b - 3 >= 0 /\ a - 14*b - 1 >= 0 /\ a - 14*b >= 0 ]
We thus obtain the following problem:
18:	T:
		(1, 16)    f1(a, b) -> f2(a - 15*b, b) [ 0 >= a + b + 1 /\ a >= 1 /\ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 /\ a - 2*b - 3 >= 0 /\ a - b - 1 >= 0 /\ a - b >= 0 /\ a - 3*b - 3 >= 0 /\ a - 2*b - 1 >= 0 /\ a - 2*b >= 0 /\ a - 4*b - 3 >= 0 /\ a - 3*b - 1 >= 0 /\ a - 3*b >= 0 /\ a - 5*b - 3 >= 0 /\ a - 4*b - 1 >= 0 /\ a - 4*b >= 0 /\ a - 6*b - 3 >= 0 /\ a - 5*b - 1 >= 0 /\ a - 5*b >= 0 /\ a - 7*b - 3 >= 0 /\ a - 6*b - 1 >= 0 /\ a - 6*b >= 0 /\ a - 8*b - 3 >= 0 /\ a - 7*b - 1 >= 0 /\ a - 7*b >= 0 /\ a - 9*b - 3 >= 0 /\ a - 8*b - 1 >= 0 /\ a - 8*b >= 0 /\ a - 10*b - 3 >= 0 /\ a - 9*b - 1 >= 0 /\ a - 9*b >= 0 /\ a - 11*b - 3 >= 0 /\ a - 10*b - 1 >= 0 /\ a - 10*b >= 0 /\ a - 12*b - 3 >= 0 /\ a - 11*b - 1 >= 0 /\ a - 11*b >= 0 /\ a - 13*b - 3 >= 0 /\ a - 12*b - 1 >= 0 /\ a - 12*b >= 0 /\ a - 14*b - 3 >= 0 /\ a - 13*b - 1 >= 0 /\ a - 13*b >= 0 /\ a - 15*b - 3 >= 0 /\ a - 14*b - 1 >= 0 /\ a - 14*b >= 0 ]
		(?, 1)     f2(a, b) -> f2(a - b, b) [ -b - 2 >= 0 /\ a - b - 3 >= 0 /\ a - 1 >= 0 /\ a >= 0 ]
	start location:	f1
	leaf cost:	1

Complexity upper bound ?

Time: 2.698 sec (SMT: 2.517 sec)