MAYBE

Initial complexity problem:
1:	T:
		(1, 1)    f3(a, b) -> f2(a, b)
		(?, 1)    f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
		(?, 1)    f2(a, b) -> f300(a - 1, c) [ a >= 2 ]
	start location:	f3
	leaf cost:	0

Repeatedly removing leaves of the complexity graph in problem 1 produces the following problem:
2:	T:
		(1, 1)    f3(a, b) -> f2(a, b)
		(?, 1)    f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a, b) with all transitions in problem 2, the following new transition is obtained:
	f3(a, b) -> f2(a - 1, b) [ 1 >= a ]
We thus obtain the following problem:
3:	T:
		(1, 2)    f3(a, b) -> f2(a - 1, b) [ 1 >= a ]
		(?, 1)    f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a - 1, b) [ 1 >= a ] with all transitions in problem 3, the following new transition is obtained:
	f3(a, b) -> f2(a - 2, b) [ 1 >= a /\ 1 >= a - 1 ]
We thus obtain the following problem:
4:	T:
		(1, 3)    f3(a, b) -> f2(a - 2, b) [ 1 >= a /\ 1 >= a - 1 ]
		(?, 1)    f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a - 2, b) [ 1 >= a /\ 1 >= a - 1 ] with all transitions in problem 4, the following new transition is obtained:
	f3(a, b) -> f2(a - 3, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 ]
We thus obtain the following problem:
5:	T:
		(1, 4)    f3(a, b) -> f2(a - 3, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 ]
		(?, 1)    f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a - 3, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 ] with all transitions in problem 5, the following new transition is obtained:
	f3(a, b) -> f2(a - 4, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 ]
We thus obtain the following problem:
6:	T:
		(1, 5)    f3(a, b) -> f2(a - 4, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 ]
		(?, 1)    f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a - 4, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 ] with all transitions in problem 6, the following new transition is obtained:
	f3(a, b) -> f2(a - 5, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 ]
We thus obtain the following problem:
7:	T:
		(1, 6)    f3(a, b) -> f2(a - 5, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 ]
		(?, 1)    f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a - 5, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 ] with all transitions in problem 7, the following new transition is obtained:
	f3(a, b) -> f2(a - 6, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 ]
We thus obtain the following problem:
8:	T:
		(1, 7)    f3(a, b) -> f2(a - 6, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 ]
		(?, 1)    f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a - 6, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 ] with all transitions in problem 8, the following new transition is obtained:
	f3(a, b) -> f2(a - 7, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 ]
We thus obtain the following problem:
9:	T:
		(1, 8)    f3(a, b) -> f2(a - 7, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 ]
		(?, 1)    f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a - 7, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 ] with all transitions in problem 9, the following new transition is obtained:
	f3(a, b) -> f2(a - 8, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 ]
We thus obtain the following problem:
10:	T:
		(1, 9)    f3(a, b) -> f2(a - 8, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 ]
		(?, 1)    f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a - 8, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 ] with all transitions in problem 10, the following new transition is obtained:
	f3(a, b) -> f2(a - 9, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 ]
We thus obtain the following problem:
11:	T:
		(1, 10)    f3(a, b) -> f2(a - 9, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 ]
		(?, 1)     f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a - 9, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 ] with all transitions in problem 11, the following new transition is obtained:
	f3(a, b) -> f2(a - 10, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 ]
We thus obtain the following problem:
12:	T:
		(1, 11)    f3(a, b) -> f2(a - 10, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 ]
		(?, 1)     f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a - 10, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 ] with all transitions in problem 12, the following new transition is obtained:
	f3(a, b) -> f2(a - 11, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 /\ 1 >= a - 10 ]
We thus obtain the following problem:
13:	T:
		(1, 12)    f3(a, b) -> f2(a - 11, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 /\ 1 >= a - 10 ]
		(?, 1)     f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a - 11, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 /\ 1 >= a - 10 ] with all transitions in problem 13, the following new transition is obtained:
	f3(a, b) -> f2(a - 12, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 /\ 1 >= a - 10 /\ 1 >= a - 11 ]
We thus obtain the following problem:
14:	T:
		(1, 13)    f3(a, b) -> f2(a - 12, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 /\ 1 >= a - 10 /\ 1 >= a - 11 ]
		(?, 1)     f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a - 12, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 /\ 1 >= a - 10 /\ 1 >= a - 11 ] with all transitions in problem 14, the following new transition is obtained:
	f3(a, b) -> f2(a - 13, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 /\ 1 >= a - 10 /\ 1 >= a - 11 /\ 1 >= a - 12 ]
We thus obtain the following problem:
15:	T:
		(1, 14)    f3(a, b) -> f2(a - 13, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 /\ 1 >= a - 10 /\ 1 >= a - 11 /\ 1 >= a - 12 ]
		(?, 1)     f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a - 13, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 /\ 1 >= a - 10 /\ 1 >= a - 11 /\ 1 >= a - 12 ] with all transitions in problem 15, the following new transition is obtained:
	f3(a, b) -> f2(a - 14, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 /\ 1 >= a - 10 /\ 1 >= a - 11 /\ 1 >= a - 12 /\ 1 >= a - 13 ]
We thus obtain the following problem:
16:	T:
		(1, 15)    f3(a, b) -> f2(a - 14, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 /\ 1 >= a - 10 /\ 1 >= a - 11 /\ 1 >= a - 12 /\ 1 >= a - 13 ]
		(?, 1)     f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

By chaining the transition f3(a, b) -> f2(a - 14, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 /\ 1 >= a - 10 /\ 1 >= a - 11 /\ 1 >= a - 12 /\ 1 >= a - 13 ] with all transitions in problem 16, the following new transition is obtained:
	f3(a, b) -> f2(a - 15, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 /\ 1 >= a - 10 /\ 1 >= a - 11 /\ 1 >= a - 12 /\ 1 >= a - 13 /\ 1 >= a - 14 ]
We thus obtain the following problem:
17:	T:
		(1, 16)    f3(a, b) -> f2(a - 15, b) [ 1 >= a /\ 1 >= a - 1 /\ 1 >= a - 2 /\ 1 >= a - 3 /\ 1 >= a - 4 /\ 1 >= a - 5 /\ 1 >= a - 6 /\ 1 >= a - 7 /\ 1 >= a - 8 /\ 1 >= a - 9 /\ 1 >= a - 10 /\ 1 >= a - 11 /\ 1 >= a - 12 /\ 1 >= a - 13 /\ 1 >= a - 14 ]
		(?, 1)     f2(a, b) -> f2(a - 1, b) [ 1 >= a ]
	start location:	f3
	leaf cost:	1

Complexity upper bound ?

Time: 0.876 sec (SMT: 0.820 sec)