YES(?, 5)

Initial complexity problem:
1:	T:
		(?, 1)    f11(a, b, c, d, e, f, g, h, i, j, k) -> f54(a, b, b + a, d, e, f, g, h, i, j, k) [ a >= b ]
		(?, 1)    f11(a, b, c, d, e, f, g, h, i, j, k) -> f54(a, b, b - a, d, e, f, g, h, i, j, k) [ b >= a + 1 ]
		(?, 1)    f38(a, b, c, d, e, f, g, h, i, j, k) -> f11(l, b, c, d, e, d, d, h, i, j, k) [ d >= e + 1 ]
		(?, 1)    f38(a, b, c, d, e, f, g, h, i, j, k) -> f11(l, b, c, d, e, d, d, m, i, j, k) [ e >= d ]
		(1, 1)    f0(a, b, c, d, e, f, g, h, i, j, k) -> f38(1, 2, c, 1, 10, f, g, h, 10, 2, l)
	start location:	f0
	leaf cost:	0

Slicing away variables that do not contribute to conditions from problem 1 leaves variables [a, b, d, e].
We thus obtain the following problem:
2:	T:
		(1, 1)    f0(a, b, d, e) -> f38(1, 2, 1, 10)
		(?, 1)    f38(a, b, d, e) -> f11(l, b, d, e) [ e >= d ]
		(?, 1)    f38(a, b, d, e) -> f11(l, b, d, e) [ d >= e + 1 ]
		(?, 1)    f11(a, b, d, e) -> f54(a, b, d, e) [ b >= a + 1 ]
		(?, 1)    f11(a, b, d, e) -> f54(a, b, d, e) [ a >= b ]
	start location:	f0
	leaf cost:	0

Repeatedly removing leaves of the complexity graph in problem 2 produces the following problem:
3:	T:
		(none)
	start location:	f0
	leaf cost:	5

Complexity upper bound 5

Time: 0.032 sec (SMT: 0.030 sec)