MAYBE

Initial complexity problem:
1:	T:
		(1, 1)    f0(a, b, c) -> f15(2, b, c)
		(?, 1)    f15(a, b, c) -> f18(a, a, c) [ 10 >= a ]
		(?, 1)    f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
		(?, 1)    f18(a, b, c) -> f15(a + 1, b, c)
		(?, 1)    f15(a, b, c) -> f28(a, b, c) [ a >= 11 ]
	start location:	f0
	leaf cost:	0

Repeatedly removing leaves of the complexity graph in problem 1 produces the following problem:
2:	T:
		(1, 1)    f0(a, b, c) -> f15(2, b, c)
		(?, 1)    f15(a, b, c) -> f18(a, a, c) [ 10 >= a ]
		(?, 1)    f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
		(?, 1)    f18(a, b, c) -> f15(a + 1, b, c)
	start location:	f0
	leaf cost:	1

A polynomial rank function with
	Pol(f0) = 17
	Pol(f15) = -2*V_1 + 21
	Pol(f18) = -2*V_1 + 20
orients all transitions weakly and the transition
	f15(a, b, c) -> f18(a, a, c) [ 10 >= a ]
strictly and produces the following problem:
3:	T:
		(1, 1)     f0(a, b, c) -> f15(2, b, c)
		(17, 1)    f15(a, b, c) -> f18(a, a, c) [ 10 >= a ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
		(?, 1)     f18(a, b, c) -> f15(a + 1, b, c)
	start location:	f0
	leaf cost:	1

A polynomial rank function with
	Pol(f18) = 1
	Pol(f15) = 0
and size complexities
	S("f18(a, b, c) -> f15(a + 1, b, c)", 0-0) = ?
	S("f18(a, b, c) -> f15(a + 1, b, c)", 0-1) = ?
	S("f18(a, b, c) -> f15(a + 1, b, c)", 0-2) = ?
	S("f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]", 0-0) = ?
	S("f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]", 0-1) = ?
	S("f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]", 0-2) = ?
	S("f15(a, b, c) -> f18(a, a, c) [ 10 >= a ]", 0-0) = ?
	S("f15(a, b, c) -> f18(a, a, c) [ 10 >= a ]", 0-1) = ?
	S("f15(a, b, c) -> f18(a, a, c) [ 10 >= a ]", 0-2) = ?
	S("f0(a, b, c) -> f15(2, b, c)", 0-0) = 2
	S("f0(a, b, c) -> f15(2, b, c)", 0-1) = b
	S("f0(a, b, c) -> f15(2, b, c)", 0-2) = c
orients the transitions
	f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	f18(a, b, c) -> f15(a + 1, b, c)
weakly and the transition
	f18(a, b, c) -> f15(a + 1, b, c)
strictly and produces the following problem:
4:	T:
		(1, 1)     f0(a, b, c) -> f15(2, b, c)
		(17, 1)    f15(a, b, c) -> f18(a, a, c) [ 10 >= a ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
		(17, 1)    f18(a, b, c) -> f15(a + 1, b, c)
	start location:	f0
	leaf cost:	1

By chaining the transition f0(a, b, c) -> f15(2, b, c) with all transitions in problem 4, the following new transition is obtained:
	f0(a, b, c) -> f18(2, 2, c) [ 10 >= 2 ]
We thus obtain the following problem:
5:	T:
		(1, 2)     f0(a, b, c) -> f18(2, 2, c) [ 10 >= 2 ]
		(17, 1)    f15(a, b, c) -> f18(a, a, c) [ 10 >= a ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
		(17, 1)    f18(a, b, c) -> f15(a + 1, b, c)
	start location:	f0
	leaf cost:	1

By chaining the transition f18(a, b, c) -> f15(a + 1, b, c) with all transitions in problem 5, the following new transition is obtained:
	f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
We thus obtain the following problem:
6:	T:
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(1, 2)     f0(a, b, c) -> f18(2, 2, c) [ 10 >= 2 ]
		(17, 1)    f15(a, b, c) -> f18(a, a, c) [ 10 >= a ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	start location:	f0
	leaf cost:	1

Testing for reachability in the complexity graph removes the following transition from problem 6:
	f15(a, b, c) -> f18(a, a, c) [ 10 >= a ]
We thus obtain the following problem:
7:	T:
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
		(1, 2)     f0(a, b, c) -> f18(2, 2, c) [ 10 >= 2 ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(a, b, c) -> f18(2, 2, c) [ 10 >= 2 ] with all transitions in problem 7, the following new transitions are obtained:
	f0(a, b, c) -> f18(3, 3, c) [ 10 >= 2 /\ 10 >= 3 ]
	f0(a, b, c) -> f18(2, 1, f) [ 10 >= 2 /\ d >= e + 1 ]
We thus obtain the following problem:
8:	T:
		(1, 4)     f0(a, b, c) -> f18(3, 3, c) [ 10 >= 2 /\ 10 >= 3 ]
		(1, 3)     f0(a, b, c) -> f18(2, 1, f) [ 10 >= 2 /\ d >= e + 1 ]
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(a, b, c) -> f18(3, 3, c) [ 10 >= 2 /\ 10 >= 3 ] with all transitions in problem 8, the following new transitions are obtained:
	f0(a, b, c) -> f18(4, 4, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 ]
	f0(a, b, c) -> f18(3, 2, f) [ 10 >= 2 /\ 10 >= 3 /\ d >= e + 1 ]
We thus obtain the following problem:
9:	T:
		(1, 6)     f0(a, b, c) -> f18(4, 4, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 ]
		(1, 5)     f0(a, b, c) -> f18(3, 2, f) [ 10 >= 2 /\ 10 >= 3 /\ d >= e + 1 ]
		(1, 3)     f0(a, b, c) -> f18(2, 1, f) [ 10 >= 2 /\ d >= e + 1 ]
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(a, b, c) -> f18(4, 4, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 ] with all transitions in problem 9, the following new transitions are obtained:
	f0(a, b, c) -> f18(5, 5, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 ]
	f0(a, b, c) -> f18(4, 3, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ d >= e + 1 ]
We thus obtain the following problem:
10:	T:
		(1, 8)     f0(a, b, c) -> f18(5, 5, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 ]
		(1, 7)     f0(a, b, c) -> f18(4, 3, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ d >= e + 1 ]
		(1, 5)     f0(a, b, c) -> f18(3, 2, f) [ 10 >= 2 /\ 10 >= 3 /\ d >= e + 1 ]
		(1, 3)     f0(a, b, c) -> f18(2, 1, f) [ 10 >= 2 /\ d >= e + 1 ]
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(a, b, c) -> f18(5, 5, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 ] with all transitions in problem 10, the following new transitions are obtained:
	f0(a, b, c) -> f18(6, 6, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 ]
	f0(a, b, c) -> f18(5, 4, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ d >= e + 1 ]
We thus obtain the following problem:
11:	T:
		(1, 10)    f0(a, b, c) -> f18(6, 6, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 ]
		(1, 9)     f0(a, b, c) -> f18(5, 4, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ d >= e + 1 ]
		(1, 7)     f0(a, b, c) -> f18(4, 3, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ d >= e + 1 ]
		(1, 5)     f0(a, b, c) -> f18(3, 2, f) [ 10 >= 2 /\ 10 >= 3 /\ d >= e + 1 ]
		(1, 3)     f0(a, b, c) -> f18(2, 1, f) [ 10 >= 2 /\ d >= e + 1 ]
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(a, b, c) -> f18(6, 6, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 ] with all transitions in problem 11, the following new transitions are obtained:
	f0(a, b, c) -> f18(7, 7, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 ]
	f0(a, b, c) -> f18(6, 5, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ d >= e + 1 ]
We thus obtain the following problem:
12:	T:
		(1, 12)    f0(a, b, c) -> f18(7, 7, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 ]
		(1, 11)    f0(a, b, c) -> f18(6, 5, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ d >= e + 1 ]
		(1, 9)     f0(a, b, c) -> f18(5, 4, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ d >= e + 1 ]
		(1, 7)     f0(a, b, c) -> f18(4, 3, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ d >= e + 1 ]
		(1, 5)     f0(a, b, c) -> f18(3, 2, f) [ 10 >= 2 /\ 10 >= 3 /\ d >= e + 1 ]
		(1, 3)     f0(a, b, c) -> f18(2, 1, f) [ 10 >= 2 /\ d >= e + 1 ]
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(a, b, c) -> f18(7, 7, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 ] with all transitions in problem 12, the following new transitions are obtained:
	f0(a, b, c) -> f18(8, 8, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 ]
	f0(a, b, c) -> f18(7, 6, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ d >= e + 1 ]
We thus obtain the following problem:
13:	T:
		(1, 14)    f0(a, b, c) -> f18(8, 8, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 ]
		(1, 13)    f0(a, b, c) -> f18(7, 6, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ d >= e + 1 ]
		(1, 11)    f0(a, b, c) -> f18(6, 5, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ d >= e + 1 ]
		(1, 9)     f0(a, b, c) -> f18(5, 4, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ d >= e + 1 ]
		(1, 7)     f0(a, b, c) -> f18(4, 3, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ d >= e + 1 ]
		(1, 5)     f0(a, b, c) -> f18(3, 2, f) [ 10 >= 2 /\ 10 >= 3 /\ d >= e + 1 ]
		(1, 3)     f0(a, b, c) -> f18(2, 1, f) [ 10 >= 2 /\ d >= e + 1 ]
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(a, b, c) -> f18(8, 8, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 ] with all transitions in problem 13, the following new transitions are obtained:
	f0(a, b, c) -> f18(9, 9, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 ]
	f0(a, b, c) -> f18(8, 7, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ d >= e + 1 ]
We thus obtain the following problem:
14:	T:
		(1, 16)    f0(a, b, c) -> f18(9, 9, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 ]
		(1, 15)    f0(a, b, c) -> f18(8, 7, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ d >= e + 1 ]
		(1, 13)    f0(a, b, c) -> f18(7, 6, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ d >= e + 1 ]
		(1, 11)    f0(a, b, c) -> f18(6, 5, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ d >= e + 1 ]
		(1, 9)     f0(a, b, c) -> f18(5, 4, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ d >= e + 1 ]
		(1, 7)     f0(a, b, c) -> f18(4, 3, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ d >= e + 1 ]
		(1, 5)     f0(a, b, c) -> f18(3, 2, f) [ 10 >= 2 /\ 10 >= 3 /\ d >= e + 1 ]
		(1, 3)     f0(a, b, c) -> f18(2, 1, f) [ 10 >= 2 /\ d >= e + 1 ]
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(a, b, c) -> f18(9, 9, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 ] with all transitions in problem 14, the following new transitions are obtained:
	f0(a, b, c) -> f18(10, 10, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 ]
	f0(a, b, c) -> f18(9, 8, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ d >= e + 1 ]
We thus obtain the following problem:
15:	T:
		(1, 18)    f0(a, b, c) -> f18(10, 10, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 ]
		(1, 17)    f0(a, b, c) -> f18(9, 8, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ d >= e + 1 ]
		(1, 15)    f0(a, b, c) -> f18(8, 7, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ d >= e + 1 ]
		(1, 13)    f0(a, b, c) -> f18(7, 6, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ d >= e + 1 ]
		(1, 11)    f0(a, b, c) -> f18(6, 5, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ d >= e + 1 ]
		(1, 9)     f0(a, b, c) -> f18(5, 4, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ d >= e + 1 ]
		(1, 7)     f0(a, b, c) -> f18(4, 3, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ d >= e + 1 ]
		(1, 5)     f0(a, b, c) -> f18(3, 2, f) [ 10 >= 2 /\ 10 >= 3 /\ d >= e + 1 ]
		(1, 3)     f0(a, b, c) -> f18(2, 1, f) [ 10 >= 2 /\ d >= e + 1 ]
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(a, b, c) -> f18(10, 10, c) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 ] with all transitions in problem 15, the following new transition is obtained:
	f0(a, b, c) -> f18(10, 9, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 /\ d >= e + 1 ]
We thus obtain the following problem:
16:	T:
		(1, 19)    f0(a, b, c) -> f18(10, 9, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 /\ d >= e + 1 ]
		(1, 17)    f0(a, b, c) -> f18(9, 8, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ d >= e + 1 ]
		(1, 15)    f0(a, b, c) -> f18(8, 7, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ d >= e + 1 ]
		(1, 13)    f0(a, b, c) -> f18(7, 6, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ d >= e + 1 ]
		(1, 11)    f0(a, b, c) -> f18(6, 5, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ d >= e + 1 ]
		(1, 9)     f0(a, b, c) -> f18(5, 4, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ d >= e + 1 ]
		(1, 7)     f0(a, b, c) -> f18(4, 3, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ d >= e + 1 ]
		(1, 5)     f0(a, b, c) -> f18(3, 2, f) [ 10 >= 2 /\ 10 >= 3 /\ d >= e + 1 ]
		(1, 3)     f0(a, b, c) -> f18(2, 1, f) [ 10 >= 2 /\ d >= e + 1 ]
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(a, b, c) -> f18(10, 9, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 /\ d >= e + 1 ] with all transitions in problem 16, the following new transition is obtained:
	f0(a, b, c) -> f18(10, 8, f') [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 /\ d >= e + 1 /\ d' >= e' + 1 ]
We thus obtain the following problem:
17:	T:
		(1, 20)    f0(a, b, c) -> f18(10, 8, f') [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 /\ d >= e + 1 /\ d' >= e' + 1 ]
		(1, 17)    f0(a, b, c) -> f18(9, 8, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ d >= e + 1 ]
		(1, 15)    f0(a, b, c) -> f18(8, 7, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ d >= e + 1 ]
		(1, 13)    f0(a, b, c) -> f18(7, 6, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ d >= e + 1 ]
		(1, 11)    f0(a, b, c) -> f18(6, 5, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ d >= e + 1 ]
		(1, 9)     f0(a, b, c) -> f18(5, 4, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ d >= e + 1 ]
		(1, 7)     f0(a, b, c) -> f18(4, 3, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ d >= e + 1 ]
		(1, 5)     f0(a, b, c) -> f18(3, 2, f) [ 10 >= 2 /\ 10 >= 3 /\ d >= e + 1 ]
		(1, 3)     f0(a, b, c) -> f18(2, 1, f) [ 10 >= 2 /\ d >= e + 1 ]
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(a, b, c) -> f18(10, 8, f') [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 /\ d >= e + 1 /\ d' >= e' + 1 ] with all transitions in problem 17, the following new transition is obtained:
	f0(a, b, c) -> f18(10, 7, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 /\ d >= e + 1 /\ d' >= e' + 1 /\ d'' >= e'' + 1 ]
We thus obtain the following problem:
18:	T:
		(1, 21)    f0(a, b, c) -> f18(10, 7, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 /\ d >= e + 1 /\ d' >= e' + 1 /\ d'' >= e'' + 1 ]
		(1, 17)    f0(a, b, c) -> f18(9, 8, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ d >= e + 1 ]
		(1, 15)    f0(a, b, c) -> f18(8, 7, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ d >= e + 1 ]
		(1, 13)    f0(a, b, c) -> f18(7, 6, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ d >= e + 1 ]
		(1, 11)    f0(a, b, c) -> f18(6, 5, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ d >= e + 1 ]
		(1, 9)     f0(a, b, c) -> f18(5, 4, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ d >= e + 1 ]
		(1, 7)     f0(a, b, c) -> f18(4, 3, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ d >= e + 1 ]
		(1, 5)     f0(a, b, c) -> f18(3, 2, f) [ 10 >= 2 /\ 10 >= 3 /\ d >= e + 1 ]
		(1, 3)     f0(a, b, c) -> f18(2, 1, f) [ 10 >= 2 /\ d >= e + 1 ]
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(a, b, c) -> f18(10, 7, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 /\ d >= e + 1 /\ d' >= e' + 1 /\ d'' >= e'' + 1 ] with all transitions in problem 18, the following new transition is obtained:
	f0(a, b, c) -> f18(10, 6, f') [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 /\ d >= e + 1 /\ d' >= e' + 1 /\ d'' >= e'' + 1 /\ d''' >= e''' + 1 ]
We thus obtain the following problem:
19:	T:
		(1, 22)    f0(a, b, c) -> f18(10, 6, f') [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 /\ d >= e + 1 /\ d' >= e' + 1 /\ d'' >= e'' + 1 /\ d''' >= e''' + 1 ]
		(1, 17)    f0(a, b, c) -> f18(9, 8, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ d >= e + 1 ]
		(1, 15)    f0(a, b, c) -> f18(8, 7, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ d >= e + 1 ]
		(1, 13)    f0(a, b, c) -> f18(7, 6, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ d >= e + 1 ]
		(1, 11)    f0(a, b, c) -> f18(6, 5, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ d >= e + 1 ]
		(1, 9)     f0(a, b, c) -> f18(5, 4, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ d >= e + 1 ]
		(1, 7)     f0(a, b, c) -> f18(4, 3, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ d >= e + 1 ]
		(1, 5)     f0(a, b, c) -> f18(3, 2, f) [ 10 >= 2 /\ 10 >= 3 /\ d >= e + 1 ]
		(1, 3)     f0(a, b, c) -> f18(2, 1, f) [ 10 >= 2 /\ d >= e + 1 ]
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(a, b, c) -> f18(10, 6, f') [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 /\ d >= e + 1 /\ d' >= e' + 1 /\ d'' >= e'' + 1 /\ d''' >= e''' + 1 ] with all transitions in problem 19, the following new transition is obtained:
	f0(a, b, c) -> f18(10, 5, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 /\ d >= e + 1 /\ d' >= e' + 1 /\ d'' >= e'' + 1 /\ d''' >= e''' + 1 /\ d'''' >= e'''' + 1 ]
We thus obtain the following problem:
20:	T:
		(1, 23)    f0(a, b, c) -> f18(10, 5, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ 10 >= 10 /\ d >= e + 1 /\ d' >= e' + 1 /\ d'' >= e'' + 1 /\ d''' >= e''' + 1 /\ d'''' >= e'''' + 1 ]
		(1, 17)    f0(a, b, c) -> f18(9, 8, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ 10 >= 9 /\ d >= e + 1 ]
		(1, 15)    f0(a, b, c) -> f18(8, 7, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ d >= e + 1 ]
		(1, 13)    f0(a, b, c) -> f18(7, 6, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ 10 >= 7 /\ d >= e + 1 ]
		(1, 11)    f0(a, b, c) -> f18(6, 5, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ 10 >= 6 /\ d >= e + 1 ]
		(1, 9)     f0(a, b, c) -> f18(5, 4, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ 10 >= 5 /\ d >= e + 1 ]
		(1, 7)     f0(a, b, c) -> f18(4, 3, f) [ 10 >= 2 /\ 10 >= 3 /\ 10 >= 4 /\ d >= e + 1 ]
		(1, 5)     f0(a, b, c) -> f18(3, 2, f) [ 10 >= 2 /\ 10 >= 3 /\ d >= e + 1 ]
		(1, 3)     f0(a, b, c) -> f18(2, 1, f) [ 10 >= 2 /\ d >= e + 1 ]
		(17, 2)    f18(a, b, c) -> f18(a + 1, a + 1, c) [ 10 >= a + 1 ]
		(?, 1)     f18(a, b, c) -> f18(a, b - 1, f) [ d >= e + 1 ]
	start location:	f0
	leaf cost:	1

Complexity upper bound ?

Time: 4.195 sec (SMT: 3.849 sec)