MAYBE

Initial complexity problem:
1:	T:
		(1, 1)    f0(a) -> f1(a)
		(?, 1)    f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(a) with all transitions in problem 1, the following new transition is obtained:
	f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
We thus obtain the following problem:
2:	T:
		(1, 2)    f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
		(?, 1)    f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ] with all transitions in problem 2, the following new transition is obtained:
	f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
We thus obtain the following problem:
3:	T:
		(1, 3)    f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
		(?, 1)    f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ] with all transitions in problem 3, the following new transition is obtained:
	f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
We thus obtain the following problem:
4:	T:
		(1, 4)    f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
		(?, 1)    f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ] with all transitions in problem 4, the following new transition is obtained:
	f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
We thus obtain the following problem:
5:	T:
		(1, 5)    f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
		(?, 1)    f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ] with all transitions in problem 5, the following new transition is obtained:
	f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
We thus obtain the following problem:
6:	T:
		(1, 6)    f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
		(?, 1)    f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ] with all transitions in problem 6, the following new transition is obtained:
	f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
We thus obtain the following problem:
7:	T:
		(1, 7)    f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
		(?, 1)    f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ] with all transitions in problem 7, the following new transition is obtained:
	f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
We thus obtain the following problem:
8:	T:
		(1, 8)    f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
		(?, 1)    f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ] with all transitions in problem 8, the following new transition is obtained:
	f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
We thus obtain the following problem:
9:	T:
		(1, 9)    f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
		(?, 1)    f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ] with all transitions in problem 9, the following new transition is obtained:
	f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
We thus obtain the following problem:
10:	T:
		(1, 10)    f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
		(?, 1)     f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ] with all transitions in problem 10, the following new transition is obtained:
	f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
We thus obtain the following problem:
11:	T:
		(1, 11)    f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
		(?, 1)     f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ] with all transitions in problem 11, the following new transition is obtained:
	f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
We thus obtain the following problem:
12:	T:
		(1, 12)    f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
		(?, 1)     f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ] with all transitions in problem 12, the following new transition is obtained:
	f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
We thus obtain the following problem:
13:	T:
		(1, 13)    f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
		(?, 1)     f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ] with all transitions in problem 13, the following new transition is obtained:
	f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
We thus obtain the following problem:
14:	T:
		(1, 14)    f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
		(?, 1)     f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ] with all transitions in problem 14, the following new transition is obtained:
	f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
We thus obtain the following problem:
15:	T:
		(1, 15)    f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
		(?, 1)     f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f1(a) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ] with all transitions in problem 15, the following new transition is obtained:
	f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
We thus obtain the following problem:
16:	T:
		(1, 16)    f0(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 /\ 1 >= -a + 1 /\ -a + 1 >= 0 ]
		(?, 1)     f1(a) -> f1(-a + 1) [ 1 >= a /\ a >= 0 ]
	start location:	f0
	leaf cost:	0

Complexity upper bound ?

Time: 1.015 sec (SMT: 0.958 sec)