MAYBE

Initial complexity problem:
1:	T:
		(1, 1)    f0(a, b, c, d, e) -> f9(f, f, f, 0, e)
		(?, 1)    f9(a, b, c, d, e) -> f9(a, b, c, d + 1, f) [ c >= d + 1 ]
		(?, 1)    f24(a, b, c, d, e) -> f24(a, b, c, d, e) [ 0 >= f + 1 ]
		(?, 1)    f24(a, b, c, d, e) -> f24(a, b, c, d, e)
		(?, 1)    f37(a, b, c, d, e) -> f37(a, b, c, d, e) [ f >= g + 1 ]
		(?, 1)    f37(a, b, c, d, e) -> f37(a, b, c, d, e)
		(?, 1)    f37(a, b, c, d, e) -> f48(a, b, c, d, e)
		(?, 1)    f24(a, b, c, d, e) -> f37(a, b, c, d, e)
		(?, 1)    f9(a, b, c, d, e) -> f24(a, b, c, d, e) [ d >= c ]
	start location:	f0
	leaf cost:	0

Slicing away variables that do not contribute to conditions from problem 1 leaves variables [c, d].
We thus obtain the following problem:
2:	T:
		(?, 1)    f9(c, d) -> f24(c, d) [ d >= c ]
		(?, 1)    f24(c, d) -> f37(c, d)
		(?, 1)    f37(c, d) -> f48(c, d)
		(?, 1)    f37(c, d) -> f37(c, d)
		(?, 1)    f37(c, d) -> f37(c, d) [ f >= g + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d)
		(?, 1)    f24(c, d) -> f24(c, d) [ 0 >= f + 1 ]
		(?, 1)    f9(c, d) -> f9(c, d + 1) [ c >= d + 1 ]
		(1, 1)    f0(c, d) -> f9(f, 0)
	start location:	f0
	leaf cost:	0

Repeatedly removing leaves of the complexity graph in problem 2 produces the following problem:
3:	T:
		(?, 1)    f9(c, d) -> f24(c, d) [ d >= c ]
		(?, 1)    f24(c, d) -> f37(c, d)
		(?, 1)    f37(c, d) -> f37(c, d)
		(?, 1)    f37(c, d) -> f37(c, d) [ f >= g + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d)
		(?, 1)    f24(c, d) -> f24(c, d) [ 0 >= f + 1 ]
		(?, 1)    f9(c, d) -> f9(c, d + 1) [ c >= d + 1 ]
		(1, 1)    f0(c, d) -> f9(f, 0)
	start location:	f0
	leaf cost:	1

A polynomial rank function with
	Pol(f9) = 2
	Pol(f24) = 1
	Pol(f37) = -1
	Pol(f0) = 2
orients all transitions weakly and the transitions
	f9(c, d) -> f24(c, d) [ d >= c ]
	f24(c, d) -> f37(c, d)
strictly and produces the following problem:
4:	T:
		(2, 1)    f9(c, d) -> f24(c, d) [ d >= c ]
		(2, 1)    f24(c, d) -> f37(c, d)
		(?, 1)    f37(c, d) -> f37(c, d)
		(?, 1)    f37(c, d) -> f37(c, d) [ f >= g + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d)
		(?, 1)    f24(c, d) -> f24(c, d) [ 0 >= f + 1 ]
		(?, 1)    f9(c, d) -> f9(c, d + 1) [ c >= d + 1 ]
		(1, 1)    f0(c, d) -> f9(f, 0)
	start location:	f0
	leaf cost:	1

Applied AI with 'oct' on problem 4 to obtain the following invariants:
  For symbol f24: X_2 >= 0 /\ -X_1 + X_2 >= 0
  For symbol f37: X_2 >= 0 /\ -X_1 + X_2 >= 0
  For symbol f9: X_2 >= 0


This yielded the following problem:
5:	T:
		(1, 1)    f0(c, d) -> f9(f, 0)
		(?, 1)    f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 0) with all transitions in problem 5, the following new transitions are obtained:
	f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
	f0(c, d) -> f9(f, 1) [ 0 >= 0 /\ f >= 1 ]
We thus obtain the following problem:
6:	T:
		(1, 2)    f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(1, 2)    f0(c, d) -> f9(f, 1) [ 0 >= 0 /\ f >= 1 ]
		(?, 1)    f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 1) [ 0 >= 0 /\ f >= 1 ] with all transitions in problem 6, the following new transitions are obtained:
	f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
	f0(c, d) -> f9(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 ]
We thus obtain the following problem:
7:	T:
		(1, 3)    f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
		(1, 3)    f0(c, d) -> f9(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 ]
		(1, 2)    f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(?, 1)    f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 ] with all transitions in problem 7, the following new transitions are obtained:
	f0(c, d) -> f24(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ 2 >= f ]
	f0(c, d) -> f9(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 ]
We thus obtain the following problem:
8:	T:
		(1, 4)    f0(c, d) -> f24(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ 2 >= f ]
		(1, 4)    f0(c, d) -> f9(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 ]
		(1, 3)    f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
		(1, 2)    f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(?, 1)    f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 ] with all transitions in problem 8, the following new transitions are obtained:
	f0(c, d) -> f24(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ 3 >= f ]
	f0(c, d) -> f9(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 ]
We thus obtain the following problem:
9:	T:
		(1, 5)    f0(c, d) -> f24(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ 3 >= f ]
		(1, 5)    f0(c, d) -> f9(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 ]
		(1, 4)    f0(c, d) -> f24(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ 2 >= f ]
		(1, 3)    f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
		(1, 2)    f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(?, 1)    f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 ] with all transitions in problem 9, the following new transitions are obtained:
	f0(c, d) -> f24(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ 4 >= f ]
	f0(c, d) -> f9(f, 5) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 ]
We thus obtain the following problem:
10:	T:
		(1, 6)    f0(c, d) -> f24(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ 4 >= f ]
		(1, 6)    f0(c, d) -> f9(f, 5) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 ]
		(1, 5)    f0(c, d) -> f24(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ 3 >= f ]
		(1, 4)    f0(c, d) -> f24(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ 2 >= f ]
		(1, 3)    f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
		(1, 2)    f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(?, 1)    f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 5) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 ] with all transitions in problem 10, the following new transitions are obtained:
	f0(c, d) -> f24(f, 5) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ 5 >= f ]
	f0(c, d) -> f9(f, 6) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 ]
We thus obtain the following problem:
11:	T:
		(1, 7)    f0(c, d) -> f24(f, 5) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ 5 >= f ]
		(1, 7)    f0(c, d) -> f9(f, 6) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 ]
		(1, 6)    f0(c, d) -> f24(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ 4 >= f ]
		(1, 5)    f0(c, d) -> f24(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ 3 >= f ]
		(1, 4)    f0(c, d) -> f24(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ 2 >= f ]
		(1, 3)    f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
		(1, 2)    f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(?, 1)    f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 6) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 ] with all transitions in problem 11, the following new transitions are obtained:
	f0(c, d) -> f24(f, 6) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ 6 >= f ]
	f0(c, d) -> f9(f, 7) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 ]
We thus obtain the following problem:
12:	T:
		(1, 8)    f0(c, d) -> f24(f, 6) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ 6 >= f ]
		(1, 8)    f0(c, d) -> f9(f, 7) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 ]
		(1, 7)    f0(c, d) -> f24(f, 5) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ 5 >= f ]
		(1, 6)    f0(c, d) -> f24(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ 4 >= f ]
		(1, 5)    f0(c, d) -> f24(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ 3 >= f ]
		(1, 4)    f0(c, d) -> f24(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ 2 >= f ]
		(1, 3)    f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
		(1, 2)    f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(?, 1)    f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 7) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 ] with all transitions in problem 12, the following new transitions are obtained:
	f0(c, d) -> f24(f, 7) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ 7 >= f ]
	f0(c, d) -> f9(f, 8) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 ]
We thus obtain the following problem:
13:	T:
		(1, 9)    f0(c, d) -> f24(f, 7) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ 7 >= f ]
		(1, 9)    f0(c, d) -> f9(f, 8) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 ]
		(1, 8)    f0(c, d) -> f24(f, 6) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ 6 >= f ]
		(1, 7)    f0(c, d) -> f24(f, 5) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ 5 >= f ]
		(1, 6)    f0(c, d) -> f24(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ 4 >= f ]
		(1, 5)    f0(c, d) -> f24(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ 3 >= f ]
		(1, 4)    f0(c, d) -> f24(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ 2 >= f ]
		(1, 3)    f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
		(1, 2)    f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(?, 1)    f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)    f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)    f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)    f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 8) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 ] with all transitions in problem 13, the following new transitions are obtained:
	f0(c, d) -> f24(f, 8) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ 8 >= f ]
	f0(c, d) -> f9(f, 9) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 ]
We thus obtain the following problem:
14:	T:
		(1, 10)    f0(c, d) -> f24(f, 8) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ 8 >= f ]
		(1, 10)    f0(c, d) -> f9(f, 9) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 ]
		(1, 9)     f0(c, d) -> f24(f, 7) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ 7 >= f ]
		(1, 8)     f0(c, d) -> f24(f, 6) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ 6 >= f ]
		(1, 7)     f0(c, d) -> f24(f, 5) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ 5 >= f ]
		(1, 6)     f0(c, d) -> f24(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ 4 >= f ]
		(1, 5)     f0(c, d) -> f24(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ 3 >= f ]
		(1, 4)     f0(c, d) -> f24(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ 2 >= f ]
		(1, 3)     f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
		(1, 2)     f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(?, 1)     f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)     f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)     f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)     f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)     f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)     f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)     f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 9) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 ] with all transitions in problem 14, the following new transitions are obtained:
	f0(c, d) -> f24(f, 9) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ 9 >= f ]
	f0(c, d) -> f9(f, 10) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 ]
We thus obtain the following problem:
15:	T:
		(1, 11)    f0(c, d) -> f24(f, 9) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ 9 >= f ]
		(1, 11)    f0(c, d) -> f9(f, 10) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 ]
		(1, 10)    f0(c, d) -> f24(f, 8) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ 8 >= f ]
		(1, 9)     f0(c, d) -> f24(f, 7) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ 7 >= f ]
		(1, 8)     f0(c, d) -> f24(f, 6) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ 6 >= f ]
		(1, 7)     f0(c, d) -> f24(f, 5) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ 5 >= f ]
		(1, 6)     f0(c, d) -> f24(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ 4 >= f ]
		(1, 5)     f0(c, d) -> f24(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ 3 >= f ]
		(1, 4)     f0(c, d) -> f24(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ 2 >= f ]
		(1, 3)     f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
		(1, 2)     f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(?, 1)     f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)     f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)     f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)     f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)     f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)     f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)     f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 10) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 ] with all transitions in problem 15, the following new transitions are obtained:
	f0(c, d) -> f24(f, 10) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ 10 >= f ]
	f0(c, d) -> f9(f, 11) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 ]
We thus obtain the following problem:
16:	T:
		(1, 12)    f0(c, d) -> f24(f, 10) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ 10 >= f ]
		(1, 12)    f0(c, d) -> f9(f, 11) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 ]
		(1, 11)    f0(c, d) -> f24(f, 9) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ 9 >= f ]
		(1, 10)    f0(c, d) -> f24(f, 8) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ 8 >= f ]
		(1, 9)     f0(c, d) -> f24(f, 7) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ 7 >= f ]
		(1, 8)     f0(c, d) -> f24(f, 6) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ 6 >= f ]
		(1, 7)     f0(c, d) -> f24(f, 5) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ 5 >= f ]
		(1, 6)     f0(c, d) -> f24(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ 4 >= f ]
		(1, 5)     f0(c, d) -> f24(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ 3 >= f ]
		(1, 4)     f0(c, d) -> f24(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ 2 >= f ]
		(1, 3)     f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
		(1, 2)     f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(?, 1)     f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)     f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)     f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)     f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)     f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)     f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)     f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 11) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 ] with all transitions in problem 16, the following new transitions are obtained:
	f0(c, d) -> f24(f, 11) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ 11 >= f ]
	f0(c, d) -> f9(f, 12) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 ]
We thus obtain the following problem:
17:	T:
		(1, 13)    f0(c, d) -> f24(f, 11) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ 11 >= f ]
		(1, 13)    f0(c, d) -> f9(f, 12) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 ]
		(1, 12)    f0(c, d) -> f24(f, 10) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ 10 >= f ]
		(1, 11)    f0(c, d) -> f24(f, 9) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ 9 >= f ]
		(1, 10)    f0(c, d) -> f24(f, 8) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ 8 >= f ]
		(1, 9)     f0(c, d) -> f24(f, 7) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ 7 >= f ]
		(1, 8)     f0(c, d) -> f24(f, 6) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ 6 >= f ]
		(1, 7)     f0(c, d) -> f24(f, 5) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ 5 >= f ]
		(1, 6)     f0(c, d) -> f24(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ 4 >= f ]
		(1, 5)     f0(c, d) -> f24(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ 3 >= f ]
		(1, 4)     f0(c, d) -> f24(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ 2 >= f ]
		(1, 3)     f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
		(1, 2)     f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(?, 1)     f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)     f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)     f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)     f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)     f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)     f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)     f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 12) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 ] with all transitions in problem 17, the following new transitions are obtained:
	f0(c, d) -> f24(f, 12) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ 12 >= f ]
	f0(c, d) -> f9(f, 13) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ f >= 13 ]
We thus obtain the following problem:
18:	T:
		(1, 14)    f0(c, d) -> f24(f, 12) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ 12 >= f ]
		(1, 14)    f0(c, d) -> f9(f, 13) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ f >= 13 ]
		(1, 13)    f0(c, d) -> f24(f, 11) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ 11 >= f ]
		(1, 12)    f0(c, d) -> f24(f, 10) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ 10 >= f ]
		(1, 11)    f0(c, d) -> f24(f, 9) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ 9 >= f ]
		(1, 10)    f0(c, d) -> f24(f, 8) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ 8 >= f ]
		(1, 9)     f0(c, d) -> f24(f, 7) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ 7 >= f ]
		(1, 8)     f0(c, d) -> f24(f, 6) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ 6 >= f ]
		(1, 7)     f0(c, d) -> f24(f, 5) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ 5 >= f ]
		(1, 6)     f0(c, d) -> f24(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ 4 >= f ]
		(1, 5)     f0(c, d) -> f24(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ 3 >= f ]
		(1, 4)     f0(c, d) -> f24(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ 2 >= f ]
		(1, 3)     f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
		(1, 2)     f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(?, 1)     f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)     f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)     f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)     f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)     f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)     f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)     f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 13) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ f >= 13 ] with all transitions in problem 18, the following new transitions are obtained:
	f0(c, d) -> f24(f, 13) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ f >= 13 /\ 13 >= 0 /\ 13 >= f ]
	f0(c, d) -> f9(f, 14) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ f >= 13 /\ 13 >= 0 /\ f >= 14 ]
We thus obtain the following problem:
19:	T:
		(1, 15)    f0(c, d) -> f24(f, 13) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ f >= 13 /\ 13 >= 0 /\ 13 >= f ]
		(1, 15)    f0(c, d) -> f9(f, 14) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ f >= 13 /\ 13 >= 0 /\ f >= 14 ]
		(1, 14)    f0(c, d) -> f24(f, 12) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ 12 >= f ]
		(1, 13)    f0(c, d) -> f24(f, 11) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ 11 >= f ]
		(1, 12)    f0(c, d) -> f24(f, 10) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ 10 >= f ]
		(1, 11)    f0(c, d) -> f24(f, 9) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ 9 >= f ]
		(1, 10)    f0(c, d) -> f24(f, 8) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ 8 >= f ]
		(1, 9)     f0(c, d) -> f24(f, 7) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ 7 >= f ]
		(1, 8)     f0(c, d) -> f24(f, 6) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ 6 >= f ]
		(1, 7)     f0(c, d) -> f24(f, 5) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ 5 >= f ]
		(1, 6)     f0(c, d) -> f24(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ 4 >= f ]
		(1, 5)     f0(c, d) -> f24(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ 3 >= f ]
		(1, 4)     f0(c, d) -> f24(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ 2 >= f ]
		(1, 3)     f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
		(1, 2)     f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(?, 1)     f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)     f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)     f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)     f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)     f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)     f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)     f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

By chaining the transition f0(c, d) -> f9(f, 14) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ f >= 13 /\ 13 >= 0 /\ f >= 14 ] with all transitions in problem 19, the following new transitions are obtained:
	f0(c, d) -> f24(f, 14) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ f >= 13 /\ 13 >= 0 /\ f >= 14 /\ 14 >= 0 /\ 14 >= f ]
	f0(c, d) -> f9(f, 15) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ f >= 13 /\ 13 >= 0 /\ f >= 14 /\ 14 >= 0 /\ f >= 15 ]
We thus obtain the following problem:
20:	T:
		(1, 16)    f0(c, d) -> f24(f, 14) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ f >= 13 /\ 13 >= 0 /\ f >= 14 /\ 14 >= 0 /\ 14 >= f ]
		(1, 16)    f0(c, d) -> f9(f, 15) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ f >= 13 /\ 13 >= 0 /\ f >= 14 /\ 14 >= 0 /\ f >= 15 ]
		(1, 15)    f0(c, d) -> f24(f, 13) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ f >= 13 /\ 13 >= 0 /\ 13 >= f ]
		(1, 14)    f0(c, d) -> f24(f, 12) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ f >= 12 /\ 12 >= 0 /\ 12 >= f ]
		(1, 13)    f0(c, d) -> f24(f, 11) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ f >= 11 /\ 11 >= 0 /\ 11 >= f ]
		(1, 12)    f0(c, d) -> f24(f, 10) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ f >= 10 /\ 10 >= 0 /\ 10 >= f ]
		(1, 11)    f0(c, d) -> f24(f, 9) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ f >= 9 /\ 9 >= 0 /\ 9 >= f ]
		(1, 10)    f0(c, d) -> f24(f, 8) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ f >= 8 /\ 8 >= 0 /\ 8 >= f ]
		(1, 9)     f0(c, d) -> f24(f, 7) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ f >= 7 /\ 7 >= 0 /\ 7 >= f ]
		(1, 8)     f0(c, d) -> f24(f, 6) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ f >= 6 /\ 6 >= 0 /\ 6 >= f ]
		(1, 7)     f0(c, d) -> f24(f, 5) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ f >= 5 /\ 5 >= 0 /\ 5 >= f ]
		(1, 6)     f0(c, d) -> f24(f, 4) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ f >= 4 /\ 4 >= 0 /\ 4 >= f ]
		(1, 5)     f0(c, d) -> f24(f, 3) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ f >= 3 /\ 3 >= 0 /\ 3 >= f ]
		(1, 4)     f0(c, d) -> f24(f, 2) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ f >= 2 /\ 2 >= 0 /\ 2 >= f ]
		(1, 3)     f0(c, d) -> f24(f, 1) [ 0 >= 0 /\ f >= 1 /\ 1 >= 0 /\ 1 >= f ]
		(1, 2)     f0(c, d) -> f24(f, 0) [ 0 >= 0 /\ 0 >= f ]
		(?, 1)     f9(c, d) -> f9(c, d + 1) [ d >= 0 /\ c >= d + 1 ]
		(?, 1)     f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 /\ 0 >= f + 1 ]
		(?, 1)     f24(c, d) -> f24(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(?, 1)     f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 /\ f >= g + 1 ]
		(?, 1)     f37(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)     f24(c, d) -> f37(c, d) [ d >= 0 /\ -c + d >= 0 ]
		(2, 1)     f9(c, d) -> f24(c, d) [ d >= 0 /\ d >= c ]
	start location:	f0
	leaf cost:	1

Complexity upper bound ?

Time: 2.818 sec (SMT: 2.579 sec)