MAYBE

Initial complexity problem:
1:	T:
		(1, 1)    f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
		(?, 1)    f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ c >= d + 1 ]
		(?, 1)    f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ e >= f + 1 ]
		(?, 1)    f25(a, b, c, d, e, f, g) -> f34(a, b, c, d, e, f, g) [ f >= e ]
		(?, 1)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 0, h) [ d >= c ]
	start location:	f0
	leaf cost:	0

Repeatedly removing leaves of the complexity graph in problem 1 produces the following problem:
2:	T:
		(1, 1)    f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
		(?, 1)    f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ c >= d + 1 ]
		(?, 1)    f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ e >= f + 1 ]
		(?, 1)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 0, h) [ d >= c ]
	start location:	f0
	leaf cost:	1

A polynomial rank function with
	Pol(f0) = 1
	Pol(f12) = 1
	Pol(f25) = -1
orients all transitions weakly and the transition
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 0, h) [ d >= c ]
strictly and produces the following problem:
3:	T:
		(1, 1)    f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
		(?, 1)    f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ c >= d + 1 ]
		(?, 1)    f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ e >= f + 1 ]
		(1, 1)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 0, h) [ d >= c ]
	start location:	f0
	leaf cost:	1

Applied AI with 'oct' on problem 3 to obtain the following invariants:
  For symbol f12: X_4 >= 0
  For symbol f25: X_6 >= 0 /\ X_4 + X_6 >= 0 /\ X_1 - X_5 >= 0 /\ -X_1 + X_5 >= 0 /\ X_4 >= 0 /\ -X_3 + X_4 >= 0


This yielded the following problem:
4:	T:
		(1, 1)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 0, h) [ d >= 0 /\ d >= c ]
		(?, 1)    f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)    f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)    f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 0, h) [ d >= 0 /\ d >= c ] with all transitions in problem 4, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 1, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 ]
We thus obtain the following problem:
5:	T:
		(1, 2)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 1, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 ]
		(?, 1)    f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)    f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)    f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 1, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 ] with all transitions in problem 5, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 2, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 ]
We thus obtain the following problem:
6:	T:
		(1, 3)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 2, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 ]
		(?, 1)    f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)    f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)    f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 2, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 ] with all transitions in problem 6, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 3, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 ]
We thus obtain the following problem:
7:	T:
		(1, 4)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 3, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 ]
		(?, 1)    f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)    f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)    f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 3, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 ] with all transitions in problem 7, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 4, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 ]
We thus obtain the following problem:
8:	T:
		(1, 5)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 4, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 ]
		(?, 1)    f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)    f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)    f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 4, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 ] with all transitions in problem 8, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 5, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 ]
We thus obtain the following problem:
9:	T:
		(1, 6)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 5, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 ]
		(?, 1)    f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)    f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)    f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 5, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 ] with all transitions in problem 9, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 6, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 ]
We thus obtain the following problem:
10:	T:
		(1, 7)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 6, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 ]
		(?, 1)    f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)    f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)    f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 6, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 ] with all transitions in problem 10, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 7, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 ]
We thus obtain the following problem:
11:	T:
		(1, 8)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 7, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 ]
		(?, 1)    f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)    f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)    f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 7, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 ] with all transitions in problem 11, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 8, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 ]
We thus obtain the following problem:
12:	T:
		(1, 9)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 8, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 ]
		(?, 1)    f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)    f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)    f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 8, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 ] with all transitions in problem 12, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 9, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 ]
We thus obtain the following problem:
13:	T:
		(1, 10)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 9, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 ]
		(?, 1)     f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)     f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)     f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 9, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 ] with all transitions in problem 13, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 10, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 ]
We thus obtain the following problem:
14:	T:
		(1, 11)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 10, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 ]
		(?, 1)     f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)     f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)     f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 10, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 ] with all transitions in problem 14, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 11, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 /\ 10 >= 0 /\ d + 10 >= 0 /\ a >= 11 ]
We thus obtain the following problem:
15:	T:
		(1, 12)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 11, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 /\ 10 >= 0 /\ d + 10 >= 0 /\ a >= 11 ]
		(?, 1)     f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)     f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)     f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 11, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 /\ 10 >= 0 /\ d + 10 >= 0 /\ a >= 11 ] with all transitions in problem 15, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 12, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 /\ 10 >= 0 /\ d + 10 >= 0 /\ a >= 11 /\ 11 >= 0 /\ d + 11 >= 0 /\ a >= 12 ]
We thus obtain the following problem:
16:	T:
		(1, 13)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 12, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 /\ 10 >= 0 /\ d + 10 >= 0 /\ a >= 11 /\ 11 >= 0 /\ d + 11 >= 0 /\ a >= 12 ]
		(?, 1)     f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)     f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)     f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 12, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 /\ 10 >= 0 /\ d + 10 >= 0 /\ a >= 11 /\ 11 >= 0 /\ d + 11 >= 0 /\ a >= 12 ] with all transitions in problem 16, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 13, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 /\ 10 >= 0 /\ d + 10 >= 0 /\ a >= 11 /\ 11 >= 0 /\ d + 11 >= 0 /\ a >= 12 /\ 12 >= 0 /\ d + 12 >= 0 /\ a >= 13 ]
We thus obtain the following problem:
17:	T:
		(1, 14)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 13, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 /\ 10 >= 0 /\ d + 10 >= 0 /\ a >= 11 /\ 11 >= 0 /\ d + 11 >= 0 /\ a >= 12 /\ 12 >= 0 /\ d + 12 >= 0 /\ a >= 13 ]
		(?, 1)     f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)     f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)     f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 13, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 /\ 10 >= 0 /\ d + 10 >= 0 /\ a >= 11 /\ 11 >= 0 /\ d + 11 >= 0 /\ a >= 12 /\ 12 >= 0 /\ d + 12 >= 0 /\ a >= 13 ] with all transitions in problem 17, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 14, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 /\ 10 >= 0 /\ d + 10 >= 0 /\ a >= 11 /\ 11 >= 0 /\ d + 11 >= 0 /\ a >= 12 /\ 12 >= 0 /\ d + 12 >= 0 /\ a >= 13 /\ 13 >= 0 /\ d + 13 >= 0 /\ a >= 14 ]
We thus obtain the following problem:
18:	T:
		(1, 15)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 14, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 /\ 10 >= 0 /\ d + 10 >= 0 /\ a >= 11 /\ 11 >= 0 /\ d + 11 >= 0 /\ a >= 12 /\ 12 >= 0 /\ d + 12 >= 0 /\ a >= 13 /\ 13 >= 0 /\ d + 13 >= 0 /\ a >= 14 ]
		(?, 1)     f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)     f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)     f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

By chaining the transition f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 14, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 /\ 10 >= 0 /\ d + 10 >= 0 /\ a >= 11 /\ 11 >= 0 /\ d + 11 >= 0 /\ a >= 12 /\ 12 >= 0 /\ d + 12 >= 0 /\ a >= 13 /\ 13 >= 0 /\ d + 13 >= 0 /\ a >= 14 ] with all transitions in problem 18, the following new transition is obtained:
	f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 15, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 /\ 10 >= 0 /\ d + 10 >= 0 /\ a >= 11 /\ 11 >= 0 /\ d + 11 >= 0 /\ a >= 12 /\ 12 >= 0 /\ d + 12 >= 0 /\ a >= 13 /\ 13 >= 0 /\ d + 13 >= 0 /\ a >= 14 /\ 14 >= 0 /\ d + 14 >= 0 /\ a >= 15 ]
We thus obtain the following problem:
19:	T:
		(1, 16)    f12(a, b, c, d, e, f, g) -> f25(a, b, c, d, a, 15, h) [ d >= 0 /\ d >= c /\ 0 >= 0 /\ -c + d >= 0 /\ a >= 1 /\ 1 >= 0 /\ d + 1 >= 0 /\ a >= 2 /\ 2 >= 0 /\ d + 2 >= 0 /\ a >= 3 /\ 3 >= 0 /\ d + 3 >= 0 /\ a >= 4 /\ 4 >= 0 /\ d + 4 >= 0 /\ a >= 5 /\ 5 >= 0 /\ d + 5 >= 0 /\ a >= 6 /\ 6 >= 0 /\ d + 6 >= 0 /\ a >= 7 /\ 7 >= 0 /\ d + 7 >= 0 /\ a >= 8 /\ 8 >= 0 /\ d + 8 >= 0 /\ a >= 9 /\ 9 >= 0 /\ d + 9 >= 0 /\ a >= 10 /\ 10 >= 0 /\ d + 10 >= 0 /\ a >= 11 /\ 11 >= 0 /\ d + 11 >= 0 /\ a >= 12 /\ 12 >= 0 /\ d + 12 >= 0 /\ a >= 13 /\ 13 >= 0 /\ d + 13 >= 0 /\ a >= 14 /\ 14 >= 0 /\ d + 14 >= 0 /\ a >= 15 ]
		(?, 1)     f25(a, b, c, d, e, f, g) -> f25(a, b, c, d, e, f + 1, g) [ f >= 0 /\ d + f >= 0 /\ a - e >= 0 /\ -a + e >= 0 /\ d >= 0 /\ -c + d >= 0 /\ e >= f + 1 ]
		(?, 1)     f12(a, b, c, d, e, f, g) -> f12(a, b, c, d + 1, e, f, g) [ d >= 0 /\ c >= d + 1 ]
		(1, 1)     f0(a, b, c, d, e, f, g) -> f12(h, i, j, 0, e, f, g)
	start location:	f0
	leaf cost:	1

Complexity upper bound ?

Time: 2.328 sec (SMT: 2.130 sec)