MAYBE

Initial complexity problem:
1:	T:
		(1, 1)    f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
		(1, 1)    f0(a) -> f2(a + 500) [ a >= 1 ]
		(?, 1)    f2(a) -> f2(a + 700) [ a + 199 >= 0 ]
	start location:	f0
	leaf cost:	0

Applied AI with 'oct' on problem 1 to obtain the following invariants:
  For symbol f2: X_1 - 101 >= 0


This yielded the following problem:
2:	T:
		(?, 1)    f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)    f0(a) -> f2(a + 500) [ a >= 1 ]
		(1, 1)    f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 500) [ a >= 1 ] with all transitions in problem 2, the following new transition is obtained:
	f0(a) -> f2(a + 1200) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 ]
We thus obtain the following problem:
3:	T:
		(1, 2)    f0(a) -> f2(a + 1200) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 ]
		(?, 1)    f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)    f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 1200) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 ] with all transitions in problem 3, the following new transition is obtained:
	f0(a) -> f2(a + 1900) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 ]
We thus obtain the following problem:
4:	T:
		(1, 3)    f0(a) -> f2(a + 1900) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 ]
		(?, 1)    f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)    f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 1900) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 ] with all transitions in problem 4, the following new transition is obtained:
	f0(a) -> f2(a + 2600) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 ]
We thus obtain the following problem:
5:	T:
		(1, 4)    f0(a) -> f2(a + 2600) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 ]
		(?, 1)    f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)    f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 2600) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 ] with all transitions in problem 5, the following new transition is obtained:
	f0(a) -> f2(a + 3300) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 ]
We thus obtain the following problem:
6:	T:
		(1, 5)    f0(a) -> f2(a + 3300) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 ]
		(?, 1)    f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)    f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 3300) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 ] with all transitions in problem 6, the following new transition is obtained:
	f0(a) -> f2(a + 4000) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 ]
We thus obtain the following problem:
7:	T:
		(1, 6)    f0(a) -> f2(a + 4000) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 ]
		(?, 1)    f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)    f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 4000) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 ] with all transitions in problem 7, the following new transition is obtained:
	f0(a) -> f2(a + 4700) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 ]
We thus obtain the following problem:
8:	T:
		(1, 7)    f0(a) -> f2(a + 4700) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 ]
		(?, 1)    f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)    f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 4700) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 ] with all transitions in problem 8, the following new transition is obtained:
	f0(a) -> f2(a + 5400) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 ]
We thus obtain the following problem:
9:	T:
		(1, 8)    f0(a) -> f2(a + 5400) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 ]
		(?, 1)    f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)    f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 5400) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 ] with all transitions in problem 9, the following new transition is obtained:
	f0(a) -> f2(a + 6100) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 ]
We thus obtain the following problem:
10:	T:
		(1, 9)    f0(a) -> f2(a + 6100) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 ]
		(?, 1)    f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)    f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 6100) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 ] with all transitions in problem 10, the following new transition is obtained:
	f0(a) -> f2(a + 6800) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 ]
We thus obtain the following problem:
11:	T:
		(1, 10)    f0(a) -> f2(a + 6800) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 ]
		(?, 1)     f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)     f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 6800) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 ] with all transitions in problem 11, the following new transition is obtained:
	f0(a) -> f2(a + 7500) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 ]
We thus obtain the following problem:
12:	T:
		(1, 11)    f0(a) -> f2(a + 7500) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 ]
		(?, 1)     f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)     f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 7500) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 ] with all transitions in problem 12, the following new transition is obtained:
	f0(a) -> f2(a + 8200) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 /\ a + 7399 >= 0 /\ a + 7699 >= 0 ]
We thus obtain the following problem:
13:	T:
		(1, 12)    f0(a) -> f2(a + 8200) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 /\ a + 7399 >= 0 /\ a + 7699 >= 0 ]
		(?, 1)     f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)     f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 8200) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 /\ a + 7399 >= 0 /\ a + 7699 >= 0 ] with all transitions in problem 13, the following new transition is obtained:
	f0(a) -> f2(a + 8900) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 /\ a + 7399 >= 0 /\ a + 7699 >= 0 /\ a + 8099 >= 0 /\ a + 8399 >= 0 ]
We thus obtain the following problem:
14:	T:
		(1, 13)    f0(a) -> f2(a + 8900) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 /\ a + 7399 >= 0 /\ a + 7699 >= 0 /\ a + 8099 >= 0 /\ a + 8399 >= 0 ]
		(?, 1)     f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)     f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 8900) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 /\ a + 7399 >= 0 /\ a + 7699 >= 0 /\ a + 8099 >= 0 /\ a + 8399 >= 0 ] with all transitions in problem 14, the following new transition is obtained:
	f0(a) -> f2(a + 9600) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 /\ a + 7399 >= 0 /\ a + 7699 >= 0 /\ a + 8099 >= 0 /\ a + 8399 >= 0 /\ a + 8799 >= 0 /\ a + 9099 >= 0 ]
We thus obtain the following problem:
15:	T:
		(1, 14)    f0(a) -> f2(a + 9600) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 /\ a + 7399 >= 0 /\ a + 7699 >= 0 /\ a + 8099 >= 0 /\ a + 8399 >= 0 /\ a + 8799 >= 0 /\ a + 9099 >= 0 ]
		(?, 1)     f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)     f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 9600) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 /\ a + 7399 >= 0 /\ a + 7699 >= 0 /\ a + 8099 >= 0 /\ a + 8399 >= 0 /\ a + 8799 >= 0 /\ a + 9099 >= 0 ] with all transitions in problem 15, the following new transition is obtained:
	f0(a) -> f2(a + 10300) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 /\ a + 7399 >= 0 /\ a + 7699 >= 0 /\ a + 8099 >= 0 /\ a + 8399 >= 0 /\ a + 8799 >= 0 /\ a + 9099 >= 0 /\ a + 9499 >= 0 /\ a + 9799 >= 0 ]
We thus obtain the following problem:
16:	T:
		(1, 15)    f0(a) -> f2(a + 10300) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 /\ a + 7399 >= 0 /\ a + 7699 >= 0 /\ a + 8099 >= 0 /\ a + 8399 >= 0 /\ a + 8799 >= 0 /\ a + 9099 >= 0 /\ a + 9499 >= 0 /\ a + 9799 >= 0 ]
		(?, 1)     f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)     f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

By chaining the transition f0(a) -> f2(a + 10300) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 /\ a + 7399 >= 0 /\ a + 7699 >= 0 /\ a + 8099 >= 0 /\ a + 8399 >= 0 /\ a + 8799 >= 0 /\ a + 9099 >= 0 /\ a + 9499 >= 0 /\ a + 9799 >= 0 ] with all transitions in problem 16, the following new transition is obtained:
	f0(a) -> f2(a + 11000) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 /\ a + 7399 >= 0 /\ a + 7699 >= 0 /\ a + 8099 >= 0 /\ a + 8399 >= 0 /\ a + 8799 >= 0 /\ a + 9099 >= 0 /\ a + 9499 >= 0 /\ a + 9799 >= 0 /\ a + 10199 >= 0 /\ a + 10499 >= 0 ]
We thus obtain the following problem:
17:	T:
		(1, 16)    f0(a) -> f2(a + 11000) [ a >= 1 /\ a + 399 >= 0 /\ a + 699 >= 0 /\ a + 1099 >= 0 /\ a + 1399 >= 0 /\ a + 1799 >= 0 /\ a + 2099 >= 0 /\ a + 2499 >= 0 /\ a + 2799 >= 0 /\ a + 3199 >= 0 /\ a + 3499 >= 0 /\ a + 3899 >= 0 /\ a + 4199 >= 0 /\ a + 4599 >= 0 /\ a + 4899 >= 0 /\ a + 5299 >= 0 /\ a + 5599 >= 0 /\ a + 5999 >= 0 /\ a + 6299 >= 0 /\ a + 6699 >= 0 /\ a + 6999 >= 0 /\ a + 7399 >= 0 /\ a + 7699 >= 0 /\ a + 8099 >= 0 /\ a + 8399 >= 0 /\ a + 8799 >= 0 /\ a + 9099 >= 0 /\ a + 9499 >= 0 /\ a + 9799 >= 0 /\ a + 10199 >= 0 /\ a + 10499 >= 0 ]
		(?, 1)     f2(a) -> f2(a + 700) [ a - 101 >= 0 /\ a + 199 >= 0 ]
		(1, 1)     f0(a) -> f2(a + 200) [ a + 99 >= 0 ]
	start location:	f0
	leaf cost:	0

Complexity upper bound ?

Time: 1.480 sec (SMT: 1.391 sec)