MAYBE

Initial complexity problem:
1:	T:
		(1, 1)    f0(a, b, c, d, e, f, g) -> f6(8, 0, 14, -1, e, f, g)
		(?, 1)    f6(a, b, c, d, e, f, g) -> f12(a, b, c, d, i, f, g) [ c >= b /\ a >= h + 1 ]
		(?, 1)    f6(a, b, c, d, e, f, g) -> f12(a, b, c, d, i, f, g) [ c >= b ]
		(?, 1)    f6(a, b, c, d, e, f, g) -> f6(a, b, b - 1, i, h, f, g) [ c >= b ]
		(?, 1)    f12(a, b, c, d, e, f, g) -> f6(a, b, e - 1, d, e, f, g)
		(?, 1)    f12(a, b, c, d, e, f, g) -> f6(a, e + 1, c, d, e, f, g)
		(?, 1)    f6(a, b, c, d, e, f, g) -> f20(a, b, c, d, e, d, d) [ b >= c + 1 ]
	start location:	f0
	leaf cost:	0

Slicing away variables that do not contribute to conditions from problem 1 leaves variables [a, b, c, e].
We thus obtain the following problem:
2:	T:
		(?, 1)    f6(a, b, c, e) -> f20(a, b, c, e) [ b >= c + 1 ]
		(?, 1)    f12(a, b, c, e) -> f6(a, e + 1, c, e)
		(?, 1)    f12(a, b, c, e) -> f6(a, b, e - 1, e)
		(?, 1)    f6(a, b, c, e) -> f6(a, b, b - 1, h) [ c >= b ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ c >= b ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ c >= b /\ a >= h + 1 ]
		(1, 1)    f0(a, b, c, e) -> f6(8, 0, 14, e)
	start location:	f0
	leaf cost:	0

Repeatedly removing leaves of the complexity graph in problem 2 produces the following problem:
3:	T:
		(?, 1)    f12(a, b, c, e) -> f6(a, e + 1, c, e)
		(?, 1)    f12(a, b, c, e) -> f6(a, b, e - 1, e)
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ c >= b ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ c >= b /\ a >= h + 1 ]
		(1, 1)    f0(a, b, c, e) -> f6(8, 0, 14, e)
	start location:	f0
	leaf cost:	2

Applied AI with 'oct' on problem 3 to obtain the following invariants:
  For symbol f12: -X_2 + X_3 >= 0 /\ -X_1 + 8 >= 0 /\ X_1 - 8 >= 0
  For symbol f6: -X_1 + 8 >= 0 /\ X_1 - 8 >= 0


This yielded the following problem:
4:	T:
		(1, 1)    f0(a, b, c, e) -> f6(8, 0, 14, e)
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)    f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)    f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f6(8, 0, 14, e) with all transitions in problem 4, the following new transitions are obtained:
	f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 ]
	f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
We thus obtain the following problem:
5:	T:
		(1, 2)    f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)    f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)    f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)    f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 ] with all transitions in problem 5, the following new transitions are obtained:
	f0(a, b, c, e) -> f6(8, i + 1, 14, i) [ 0 >= 0 /\ 14 >= 0 ]
	f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
We thus obtain the following problem:
6:	T:
		(1, 3)    f0(a, b, c, e) -> f6(8, i + 1, 14, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 3)    f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)    f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)    f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)    f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f6(8, i + 1, 14, i) [ 0 >= 0 /\ 14 >= 0 ] with all transitions in problem 6, the following new transitions are obtained:
	f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 ]
	f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ 8 >= h + 1 ]
We thus obtain the following problem:
7:	T:
		(1, 4)    f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 ]
		(1, 4)    f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ 8 >= h + 1 ]
		(1, 3)    f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)    f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)    f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)    f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 ] with all transitions in problem 7, the following new transitions are obtained:
	f0(a, b, c, e) -> f6(8, i' + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
	f0(a, b, c, e) -> f6(8, i + 1, i' - 1, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
We thus obtain the following problem:
8:	T:
		(1, 5)    f0(a, b, c, e) -> f6(8, i' + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
		(1, 5)    f0(a, b, c, e) -> f6(8, i + 1, i' - 1, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
		(1, 4)    f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ 8 >= h + 1 ]
		(1, 3)    f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)    f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)    f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)    f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f6(8, i' + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ] with all transitions in problem 8, the following new transitions are obtained:
	f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 ]
	f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ 8 >= h + 1 ]
We thus obtain the following problem:
9:	T:
		(1, 6)    f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 ]
		(1, 6)    f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ 8 >= h + 1 ]
		(1, 5)    f0(a, b, c, e) -> f6(8, i + 1, i' - 1, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
		(1, 4)    f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ 8 >= h + 1 ]
		(1, 3)    f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)    f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)    f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)    f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 ] with all transitions in problem 9, the following new transitions are obtained:
	f0(a, b, c, e) -> f6(8, i'' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 ]
	f0(a, b, c, e) -> f6(8, i' + 1, i'' - 1, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 ]
We thus obtain the following problem:
10:	T:
		(1, 7)    f0(a, b, c, e) -> f6(8, i'' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 ]
		(1, 7)    f0(a, b, c, e) -> f6(8, i' + 1, i'' - 1, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 ]
		(1, 6)    f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ 8 >= h + 1 ]
		(1, 5)    f0(a, b, c, e) -> f6(8, i + 1, i' - 1, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
		(1, 4)    f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ 8 >= h + 1 ]
		(1, 3)    f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)    f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)    f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)    f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f6(8, i'' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 ] with all transitions in problem 10, the following new transitions are obtained:
	f0(a, b, c, e) -> f12(8, i'' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 ]
	f0(a, b, c, e) -> f12(8, i'' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ 8 >= h + 1 ]
We thus obtain the following problem:
11:	T:
		(1, 8)    f0(a, b, c, e) -> f12(8, i'' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 ]
		(1, 8)    f0(a, b, c, e) -> f12(8, i'' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ 8 >= h + 1 ]
		(1, 7)    f0(a, b, c, e) -> f6(8, i' + 1, i'' - 1, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 ]
		(1, 6)    f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ 8 >= h + 1 ]
		(1, 5)    f0(a, b, c, e) -> f6(8, i + 1, i' - 1, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
		(1, 4)    f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ 8 >= h + 1 ]
		(1, 3)    f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)    f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)    f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)    f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f12(8, i'' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 ] with all transitions in problem 11, the following new transitions are obtained:
	f0(a, b, c, e) -> f6(8, i''' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 ]
	f0(a, b, c, e) -> f6(8, i'' + 1, i''' - 1, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 ]
We thus obtain the following problem:
12:	T:
		(1, 9)    f0(a, b, c, e) -> f6(8, i''' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 ]
		(1, 9)    f0(a, b, c, e) -> f6(8, i'' + 1, i''' - 1, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 ]
		(1, 8)    f0(a, b, c, e) -> f12(8, i'' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ 8 >= h + 1 ]
		(1, 7)    f0(a, b, c, e) -> f6(8, i' + 1, i'' - 1, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 ]
		(1, 6)    f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ 8 >= h + 1 ]
		(1, 5)    f0(a, b, c, e) -> f6(8, i + 1, i' - 1, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
		(1, 4)    f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ 8 >= h + 1 ]
		(1, 3)    f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)    f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)    f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)    f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)    f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f6(8, i''' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 ] with all transitions in problem 12, the following new transitions are obtained:
	f0(a, b, c, e) -> f12(8, i''' + 1, 14, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 ]
	f0(a, b, c, e) -> f12(8, i''' + 1, 14, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ 8 >= h + 1 ]
We thus obtain the following problem:
13:	T:
		(1, 10)    f0(a, b, c, e) -> f12(8, i''' + 1, 14, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 ]
		(1, 10)    f0(a, b, c, e) -> f12(8, i''' + 1, 14, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ 8 >= h + 1 ]
		(1, 9)     f0(a, b, c, e) -> f6(8, i'' + 1, i''' - 1, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 ]
		(1, 8)     f0(a, b, c, e) -> f12(8, i'' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ 8 >= h + 1 ]
		(1, 7)     f0(a, b, c, e) -> f6(8, i' + 1, i'' - 1, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 ]
		(1, 6)     f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ 8 >= h + 1 ]
		(1, 5)     f0(a, b, c, e) -> f6(8, i + 1, i' - 1, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
		(1, 4)     f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ 8 >= h + 1 ]
		(1, 3)     f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)     f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)     f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)     f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)     f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)     f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f12(8, i''' + 1, 14, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 ] with all transitions in problem 13, the following new transitions are obtained:
	f0(a, b, c, e) -> f6(8, i'''' + 1, 14, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 ]
	f0(a, b, c, e) -> f6(8, i''' + 1, i'''' - 1, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 ]
We thus obtain the following problem:
14:	T:
		(1, 11)    f0(a, b, c, e) -> f6(8, i'''' + 1, 14, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 ]
		(1, 11)    f0(a, b, c, e) -> f6(8, i''' + 1, i'''' - 1, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 ]
		(1, 10)    f0(a, b, c, e) -> f12(8, i''' + 1, 14, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ 8 >= h + 1 ]
		(1, 9)     f0(a, b, c, e) -> f6(8, i'' + 1, i''' - 1, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 ]
		(1, 8)     f0(a, b, c, e) -> f12(8, i'' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ 8 >= h + 1 ]
		(1, 7)     f0(a, b, c, e) -> f6(8, i' + 1, i'' - 1, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 ]
		(1, 6)     f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ 8 >= h + 1 ]
		(1, 5)     f0(a, b, c, e) -> f6(8, i + 1, i' - 1, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
		(1, 4)     f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ 8 >= h + 1 ]
		(1, 3)     f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)     f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)     f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)     f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)     f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)     f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f6(8, i'''' + 1, 14, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 ] with all transitions in problem 14, the following new transitions are obtained:
	f0(a, b, c, e) -> f12(8, i'''' + 1, 14, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 ]
	f0(a, b, c, e) -> f12(8, i'''' + 1, 14, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ 8 >= h + 1 ]
We thus obtain the following problem:
15:	T:
		(1, 12)    f0(a, b, c, e) -> f12(8, i'''' + 1, 14, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 ]
		(1, 12)    f0(a, b, c, e) -> f12(8, i'''' + 1, 14, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ 8 >= h + 1 ]
		(1, 11)    f0(a, b, c, e) -> f6(8, i''' + 1, i'''' - 1, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 ]
		(1, 10)    f0(a, b, c, e) -> f12(8, i''' + 1, 14, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ 8 >= h + 1 ]
		(1, 9)     f0(a, b, c, e) -> f6(8, i'' + 1, i''' - 1, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 ]
		(1, 8)     f0(a, b, c, e) -> f12(8, i'' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ 8 >= h + 1 ]
		(1, 7)     f0(a, b, c, e) -> f6(8, i' + 1, i'' - 1, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 ]
		(1, 6)     f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ 8 >= h + 1 ]
		(1, 5)     f0(a, b, c, e) -> f6(8, i + 1, i' - 1, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
		(1, 4)     f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ 8 >= h + 1 ]
		(1, 3)     f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)     f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)     f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)     f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)     f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)     f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f12(8, i'''' + 1, 14, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 ] with all transitions in problem 15, the following new transitions are obtained:
	f0(a, b, c, e) -> f6(8, i''''' + 1, 14, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 ]
	f0(a, b, c, e) -> f6(8, i'''' + 1, i''''' - 1, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 ]
We thus obtain the following problem:
16:	T:
		(1, 13)    f0(a, b, c, e) -> f6(8, i''''' + 1, 14, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 ]
		(1, 13)    f0(a, b, c, e) -> f6(8, i'''' + 1, i''''' - 1, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 ]
		(1, 12)    f0(a, b, c, e) -> f12(8, i'''' + 1, 14, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ 8 >= h + 1 ]
		(1, 11)    f0(a, b, c, e) -> f6(8, i''' + 1, i'''' - 1, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 ]
		(1, 10)    f0(a, b, c, e) -> f12(8, i''' + 1, 14, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ 8 >= h + 1 ]
		(1, 9)     f0(a, b, c, e) -> f6(8, i'' + 1, i''' - 1, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 ]
		(1, 8)     f0(a, b, c, e) -> f12(8, i'' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ 8 >= h + 1 ]
		(1, 7)     f0(a, b, c, e) -> f6(8, i' + 1, i'' - 1, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 ]
		(1, 6)     f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ 8 >= h + 1 ]
		(1, 5)     f0(a, b, c, e) -> f6(8, i + 1, i' - 1, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
		(1, 4)     f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ 8 >= h + 1 ]
		(1, 3)     f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)     f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)     f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)     f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)     f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)     f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f6(8, i''''' + 1, 14, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 ] with all transitions in problem 16, the following new transitions are obtained:
	f0(a, b, c, e) -> f12(8, i''''' + 1, 14, i'''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 ]
	f0(a, b, c, e) -> f12(8, i''''' + 1, 14, i'''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 /\ 8 >= h + 1 ]
We thus obtain the following problem:
17:	T:
		(1, 14)    f0(a, b, c, e) -> f12(8, i''''' + 1, 14, i'''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 ]
		(1, 14)    f0(a, b, c, e) -> f12(8, i''''' + 1, 14, i'''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 /\ 8 >= h + 1 ]
		(1, 13)    f0(a, b, c, e) -> f6(8, i'''' + 1, i''''' - 1, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 ]
		(1, 12)    f0(a, b, c, e) -> f12(8, i'''' + 1, 14, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ 8 >= h + 1 ]
		(1, 11)    f0(a, b, c, e) -> f6(8, i''' + 1, i'''' - 1, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 ]
		(1, 10)    f0(a, b, c, e) -> f12(8, i''' + 1, 14, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ 8 >= h + 1 ]
		(1, 9)     f0(a, b, c, e) -> f6(8, i'' + 1, i''' - 1, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 ]
		(1, 8)     f0(a, b, c, e) -> f12(8, i'' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ 8 >= h + 1 ]
		(1, 7)     f0(a, b, c, e) -> f6(8, i' + 1, i'' - 1, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 ]
		(1, 6)     f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ 8 >= h + 1 ]
		(1, 5)     f0(a, b, c, e) -> f6(8, i + 1, i' - 1, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
		(1, 4)     f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ 8 >= h + 1 ]
		(1, 3)     f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)     f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)     f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)     f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)     f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)     f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f12(8, i''''' + 1, 14, i'''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 ] with all transitions in problem 17, the following new transitions are obtained:
	f0(a, b, c, e) -> f6(8, i'''''' + 1, 14, i'''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 /\ -i''''' + 13 >= 0 ]
	f0(a, b, c, e) -> f6(8, i''''' + 1, i'''''' - 1, i'''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 /\ -i''''' + 13 >= 0 ]
We thus obtain the following problem:
18:	T:
		(1, 15)    f0(a, b, c, e) -> f6(8, i'''''' + 1, 14, i'''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 /\ -i''''' + 13 >= 0 ]
		(1, 15)    f0(a, b, c, e) -> f6(8, i''''' + 1, i'''''' - 1, i'''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 /\ -i''''' + 13 >= 0 ]
		(1, 14)    f0(a, b, c, e) -> f12(8, i''''' + 1, 14, i'''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 /\ 8 >= h + 1 ]
		(1, 13)    f0(a, b, c, e) -> f6(8, i'''' + 1, i''''' - 1, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 ]
		(1, 12)    f0(a, b, c, e) -> f12(8, i'''' + 1, 14, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ 8 >= h + 1 ]
		(1, 11)    f0(a, b, c, e) -> f6(8, i''' + 1, i'''' - 1, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 ]
		(1, 10)    f0(a, b, c, e) -> f12(8, i''' + 1, 14, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ 8 >= h + 1 ]
		(1, 9)     f0(a, b, c, e) -> f6(8, i'' + 1, i''' - 1, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 ]
		(1, 8)     f0(a, b, c, e) -> f12(8, i'' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ 8 >= h + 1 ]
		(1, 7)     f0(a, b, c, e) -> f6(8, i' + 1, i'' - 1, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 ]
		(1, 6)     f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ 8 >= h + 1 ]
		(1, 5)     f0(a, b, c, e) -> f6(8, i + 1, i' - 1, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
		(1, 4)     f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ 8 >= h + 1 ]
		(1, 3)     f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)     f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)     f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)     f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)     f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)     f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

By chaining the transition f0(a, b, c, e) -> f6(8, i'''''' + 1, 14, i'''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 /\ -i''''' + 13 >= 0 ] with all transitions in problem 18, the following new transitions are obtained:
	f0(a, b, c, e) -> f12(8, i'''''' + 1, 14, i''''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 /\ -i''''' + 13 >= 0 /\ 14 >= i'''''' + 1 ]
	f0(a, b, c, e) -> f12(8, i'''''' + 1, 14, i''''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 /\ -i''''' + 13 >= 0 /\ 14 >= i'''''' + 1 /\ 8 >= h + 1 ]
We thus obtain the following problem:
19:	T:
		(1, 16)    f0(a, b, c, e) -> f12(8, i'''''' + 1, 14, i''''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 /\ -i''''' + 13 >= 0 /\ 14 >= i'''''' + 1 ]
		(1, 16)    f0(a, b, c, e) -> f12(8, i'''''' + 1, 14, i''''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 /\ -i''''' + 13 >= 0 /\ 14 >= i'''''' + 1 /\ 8 >= h + 1 ]
		(1, 15)    f0(a, b, c, e) -> f6(8, i''''' + 1, i'''''' - 1, i'''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 /\ -i''''' + 13 >= 0 ]
		(1, 14)    f0(a, b, c, e) -> f12(8, i''''' + 1, 14, i'''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 /\ 14 >= i''''' + 1 /\ 8 >= h + 1 ]
		(1, 13)    f0(a, b, c, e) -> f6(8, i'''' + 1, i''''' - 1, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ -i'''' + 13 >= 0 ]
		(1, 12)    f0(a, b, c, e) -> f12(8, i'''' + 1, 14, i''''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 /\ 14 >= i'''' + 1 /\ 8 >= h + 1 ]
		(1, 11)    f0(a, b, c, e) -> f6(8, i''' + 1, i'''' - 1, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ -i''' + 13 >= 0 ]
		(1, 10)    f0(a, b, c, e) -> f12(8, i''' + 1, 14, i'''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 /\ 14 >= i''' + 1 /\ 8 >= h + 1 ]
		(1, 9)     f0(a, b, c, e) -> f6(8, i'' + 1, i''' - 1, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ -i'' + 13 >= 0 ]
		(1, 8)     f0(a, b, c, e) -> f12(8, i'' + 1, 14, i''') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 /\ 14 >= i'' + 1 /\ 8 >= h + 1 ]
		(1, 7)     f0(a, b, c, e) -> f6(8, i' + 1, i'' - 1, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ -i' + 13 >= 0 ]
		(1, 6)     f0(a, b, c, e) -> f12(8, i' + 1, 14, i'') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 /\ 14 >= i' + 1 /\ 8 >= h + 1 ]
		(1, 5)     f0(a, b, c, e) -> f6(8, i + 1, i' - 1, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ -i + 13 >= 0 ]
		(1, 4)     f0(a, b, c, e) -> f12(8, i + 1, 14, i') [ 0 >= 0 /\ 14 >= 0 /\ 14 >= i + 1 /\ 8 >= h + 1 ]
		(1, 3)     f0(a, b, c, e) -> f6(8, 0, i - 1, i) [ 0 >= 0 /\ 14 >= 0 ]
		(1, 2)     f0(a, b, c, e) -> f12(8, 0, 14, i) [ 0 >= 0 /\ 14 >= 0 /\ 8 >= h + 1 ]
		(?, 1)     f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b /\ a >= h + 1 ]
		(?, 1)     f6(a, b, c, e) -> f12(a, b, c, i) [ -a + 8 >= 0 /\ a - 8 >= 0 /\ c >= b ]
		(?, 1)     f12(a, b, c, e) -> f6(a, b, e - 1, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
		(?, 1)     f12(a, b, c, e) -> f6(a, e + 1, c, e) [ -b + c >= 0 /\ -a + 8 >= 0 /\ a - 8 >= 0 ]
	start location:	f0
	leaf cost:	2

Complexity upper bound ?

Time: 2.021 sec (SMT: 1.800 sec)