YES(?, 2*a + b + 2) Initial complexity problem: 1: T: (?, 1) eval(a, b) -> eval(a - 1, b) [ a >= 1 ] (?, 1) eval(a, b) -> eval(a - 1, b) [ b >= 1 /\ a >= 1 ] (?, 1) eval(a, b) -> eval(a, b - 1) [ a >= 1 /\ 0 >= a /\ b >= 1 ] (?, 1) eval(a, b) -> eval(a, b - 1) [ b >= 1 /\ 0 >= a ] (?, 1) eval(a, b) -> eval(a, b) [ a >= 1 /\ 0 >= a /\ 0 >= b ] (?, 1) eval(a, b) -> eval(a, b) [ b >= 1 /\ 0 >= a /\ 0 >= b ] (1, 1) start(a, b) -> eval(a, b) start location: start leaf cost: 0 Testing for unsatisfiable constraints removes the following transitions from problem 1: eval(a, b) -> eval(a, b - 1) [ a >= 1 /\ 0 >= a /\ b >= 1 ] eval(a, b) -> eval(a, b) [ a >= 1 /\ 0 >= a /\ 0 >= b ] eval(a, b) -> eval(a, b) [ b >= 1 /\ 0 >= a /\ 0 >= b ] We thus obtain the following problem: 2: T: (?, 1) eval(a, b) -> eval(a - 1, b) [ a >= 1 ] (?, 1) eval(a, b) -> eval(a - 1, b) [ b >= 1 /\ a >= 1 ] (?, 1) eval(a, b) -> eval(a, b - 1) [ b >= 1 /\ 0 >= a ] (1, 1) start(a, b) -> eval(a, b) start location: start leaf cost: 0 A polynomial rank function with Pol(eval) = V_2 + 1 Pol(start) = V_2 + 1 orients all transitions weakly and the transition eval(a, b) -> eval(a, b - 1) [ b >= 1 /\ 0 >= a ] strictly and produces the following problem: 3: T: (?, 1) eval(a, b) -> eval(a - 1, b) [ a >= 1 ] (?, 1) eval(a, b) -> eval(a - 1, b) [ b >= 1 /\ a >= 1 ] (b + 1, 1) eval(a, b) -> eval(a, b - 1) [ b >= 1 /\ 0 >= a ] (1, 1) start(a, b) -> eval(a, b) start location: start leaf cost: 0 A polynomial rank function with Pol(eval) = V_1 Pol(start) = V_1 orients all transitions weakly and the transitions eval(a, b) -> eval(a - 1, b) [ b >= 1 /\ a >= 1 ] eval(a, b) -> eval(a - 1, b) [ a >= 1 ] strictly and produces the following problem: 4: T: (a, 1) eval(a, b) -> eval(a - 1, b) [ a >= 1 ] (a, 1) eval(a, b) -> eval(a - 1, b) [ b >= 1 /\ a >= 1 ] (b + 1, 1) eval(a, b) -> eval(a, b - 1) [ b >= 1 /\ 0 >= a ] (1, 1) start(a, b) -> eval(a, b) start location: start leaf cost: 0 Complexity upper bound 2*a + b + 2 Time: 0.296 sec (SMT: 0.285 sec)