Termination w.r.t. Q of the following Term Rewriting System could be proven:
Q restricted rewrite system:
The TRS R consists of the following rules:
f(X, g(X)) → f(1, g(X))
g(1) → g(0)
The set Q consists of the following terms:
g(1)
f(x0, g(x0))
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
f(X, g(X)) → f(1, g(X))
g(1) → g(0)
The set Q consists of the following terms:
g(1)
f(x0, g(x0))
Using Dependency Pairs [1,15] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:
F(X, g(X)) → F(1, g(X))
G(1) → G(0)
The TRS R consists of the following rules:
f(X, g(X)) → f(1, g(X))
g(1) → g(0)
The set Q consists of the following terms:
g(1)
f(x0, g(x0))
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ DependencyGraphProof
Q DP problem:
The TRS P consists of the following rules:
F(X, g(X)) → F(1, g(X))
G(1) → G(0)
The TRS R consists of the following rules:
f(X, g(X)) → f(1, g(X))
g(1) → g(0)
The set Q consists of the following terms:
g(1)
f(x0, g(x0))
We have to consider all minimal (P,Q,R)-chains.
The approximation of the Dependency Graph [15,17,22] contains 0 SCCs with 2 less nodes.