(0) Obligation:
Clauses:
f([], RES, RES).
f(.(Head, Tail), X, RES) :- g(Tail, X, .(Head, Tail), RES).
g(A, B, C, RES) :- f(A, .(B, C), RES).
Queries:
f(g,g,a).
(1) PrologToPiTRSProof (SOUND transformation)
We use the technique of [LOPSTR]. With regard to the inferred argument filtering the predicates were used in the following modes:
f_in: (b,b,f)
g_in: (b,b,b,f)
Transforming
Prolog into the following
Term Rewriting System:
Pi-finite rewrite system:
The TRS R consists of the following rules:
f_in_gga([], RES, RES) → f_out_gga([], RES, RES)
f_in_gga(.(Head, Tail), X, RES) → U1_gga(Head, Tail, X, RES, g_in_ggga(Tail, X, .(Head, Tail), RES))
g_in_ggga(A, B, C, RES) → U2_ggga(A, B, C, RES, f_in_gga(A, .(B, C), RES))
U2_ggga(A, B, C, RES, f_out_gga(A, .(B, C), RES)) → g_out_ggga(A, B, C, RES)
U1_gga(Head, Tail, X, RES, g_out_ggga(Tail, X, .(Head, Tail), RES)) → f_out_gga(.(Head, Tail), X, RES)
The argument filtering Pi contains the following mapping:
f_in_gga(
x1,
x2,
x3) =
f_in_gga(
x1,
x2)
[] =
[]
f_out_gga(
x1,
x2,
x3) =
f_out_gga(
x1,
x2,
x3)
.(
x1,
x2) =
.(
x1,
x2)
U1_gga(
x1,
x2,
x3,
x4,
x5) =
U1_gga(
x1,
x2,
x3,
x5)
g_in_ggga(
x1,
x2,
x3,
x4) =
g_in_ggga(
x1,
x2,
x3)
U2_ggga(
x1,
x2,
x3,
x4,
x5) =
U2_ggga(
x1,
x2,
x3,
x5)
g_out_ggga(
x1,
x2,
x3,
x4) =
g_out_ggga(
x1,
x2,
x3,
x4)
Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog
(2) Obligation:
Pi-finite rewrite system:
The TRS R consists of the following rules:
f_in_gga([], RES, RES) → f_out_gga([], RES, RES)
f_in_gga(.(Head, Tail), X, RES) → U1_gga(Head, Tail, X, RES, g_in_ggga(Tail, X, .(Head, Tail), RES))
g_in_ggga(A, B, C, RES) → U2_ggga(A, B, C, RES, f_in_gga(A, .(B, C), RES))
U2_ggga(A, B, C, RES, f_out_gga(A, .(B, C), RES)) → g_out_ggga(A, B, C, RES)
U1_gga(Head, Tail, X, RES, g_out_ggga(Tail, X, .(Head, Tail), RES)) → f_out_gga(.(Head, Tail), X, RES)
The argument filtering Pi contains the following mapping:
f_in_gga(
x1,
x2,
x3) =
f_in_gga(
x1,
x2)
[] =
[]
f_out_gga(
x1,
x2,
x3) =
f_out_gga(
x1,
x2,
x3)
.(
x1,
x2) =
.(
x1,
x2)
U1_gga(
x1,
x2,
x3,
x4,
x5) =
U1_gga(
x1,
x2,
x3,
x5)
g_in_ggga(
x1,
x2,
x3,
x4) =
g_in_ggga(
x1,
x2,
x3)
U2_ggga(
x1,
x2,
x3,
x4,
x5) =
U2_ggga(
x1,
x2,
x3,
x5)
g_out_ggga(
x1,
x2,
x3,
x4) =
g_out_ggga(
x1,
x2,
x3,
x4)
(3) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem:
Pi DP problem:
The TRS P consists of the following rules:
F_IN_GGA(.(Head, Tail), X, RES) → U1_GGA(Head, Tail, X, RES, g_in_ggga(Tail, X, .(Head, Tail), RES))
F_IN_GGA(.(Head, Tail), X, RES) → G_IN_GGGA(Tail, X, .(Head, Tail), RES)
G_IN_GGGA(A, B, C, RES) → U2_GGGA(A, B, C, RES, f_in_gga(A, .(B, C), RES))
G_IN_GGGA(A, B, C, RES) → F_IN_GGA(A, .(B, C), RES)
The TRS R consists of the following rules:
f_in_gga([], RES, RES) → f_out_gga([], RES, RES)
f_in_gga(.(Head, Tail), X, RES) → U1_gga(Head, Tail, X, RES, g_in_ggga(Tail, X, .(Head, Tail), RES))
g_in_ggga(A, B, C, RES) → U2_ggga(A, B, C, RES, f_in_gga(A, .(B, C), RES))
U2_ggga(A, B, C, RES, f_out_gga(A, .(B, C), RES)) → g_out_ggga(A, B, C, RES)
U1_gga(Head, Tail, X, RES, g_out_ggga(Tail, X, .(Head, Tail), RES)) → f_out_gga(.(Head, Tail), X, RES)
The argument filtering Pi contains the following mapping:
f_in_gga(
x1,
x2,
x3) =
f_in_gga(
x1,
x2)
[] =
[]
f_out_gga(
x1,
x2,
x3) =
f_out_gga(
x1,
x2,
x3)
.(
x1,
x2) =
.(
x1,
x2)
U1_gga(
x1,
x2,
x3,
x4,
x5) =
U1_gga(
x1,
x2,
x3,
x5)
g_in_ggga(
x1,
x2,
x3,
x4) =
g_in_ggga(
x1,
x2,
x3)
U2_ggga(
x1,
x2,
x3,
x4,
x5) =
U2_ggga(
x1,
x2,
x3,
x5)
g_out_ggga(
x1,
x2,
x3,
x4) =
g_out_ggga(
x1,
x2,
x3,
x4)
F_IN_GGA(
x1,
x2,
x3) =
F_IN_GGA(
x1,
x2)
U1_GGA(
x1,
x2,
x3,
x4,
x5) =
U1_GGA(
x1,
x2,
x3,
x5)
G_IN_GGGA(
x1,
x2,
x3,
x4) =
G_IN_GGGA(
x1,
x2,
x3)
U2_GGGA(
x1,
x2,
x3,
x4,
x5) =
U2_GGGA(
x1,
x2,
x3,
x5)
We have to consider all (P,R,Pi)-chains
(4) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
F_IN_GGA(.(Head, Tail), X, RES) → U1_GGA(Head, Tail, X, RES, g_in_ggga(Tail, X, .(Head, Tail), RES))
F_IN_GGA(.(Head, Tail), X, RES) → G_IN_GGGA(Tail, X, .(Head, Tail), RES)
G_IN_GGGA(A, B, C, RES) → U2_GGGA(A, B, C, RES, f_in_gga(A, .(B, C), RES))
G_IN_GGGA(A, B, C, RES) → F_IN_GGA(A, .(B, C), RES)
The TRS R consists of the following rules:
f_in_gga([], RES, RES) → f_out_gga([], RES, RES)
f_in_gga(.(Head, Tail), X, RES) → U1_gga(Head, Tail, X, RES, g_in_ggga(Tail, X, .(Head, Tail), RES))
g_in_ggga(A, B, C, RES) → U2_ggga(A, B, C, RES, f_in_gga(A, .(B, C), RES))
U2_ggga(A, B, C, RES, f_out_gga(A, .(B, C), RES)) → g_out_ggga(A, B, C, RES)
U1_gga(Head, Tail, X, RES, g_out_ggga(Tail, X, .(Head, Tail), RES)) → f_out_gga(.(Head, Tail), X, RES)
The argument filtering Pi contains the following mapping:
f_in_gga(
x1,
x2,
x3) =
f_in_gga(
x1,
x2)
[] =
[]
f_out_gga(
x1,
x2,
x3) =
f_out_gga(
x1,
x2,
x3)
.(
x1,
x2) =
.(
x1,
x2)
U1_gga(
x1,
x2,
x3,
x4,
x5) =
U1_gga(
x1,
x2,
x3,
x5)
g_in_ggga(
x1,
x2,
x3,
x4) =
g_in_ggga(
x1,
x2,
x3)
U2_ggga(
x1,
x2,
x3,
x4,
x5) =
U2_ggga(
x1,
x2,
x3,
x5)
g_out_ggga(
x1,
x2,
x3,
x4) =
g_out_ggga(
x1,
x2,
x3,
x4)
F_IN_GGA(
x1,
x2,
x3) =
F_IN_GGA(
x1,
x2)
U1_GGA(
x1,
x2,
x3,
x4,
x5) =
U1_GGA(
x1,
x2,
x3,
x5)
G_IN_GGGA(
x1,
x2,
x3,
x4) =
G_IN_GGGA(
x1,
x2,
x3)
U2_GGGA(
x1,
x2,
x3,
x4,
x5) =
U2_GGGA(
x1,
x2,
x3,
x5)
We have to consider all (P,R,Pi)-chains
(5) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 2 less nodes.
(6) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
F_IN_GGA(.(Head, Tail), X, RES) → G_IN_GGGA(Tail, X, .(Head, Tail), RES)
G_IN_GGGA(A, B, C, RES) → F_IN_GGA(A, .(B, C), RES)
The TRS R consists of the following rules:
f_in_gga([], RES, RES) → f_out_gga([], RES, RES)
f_in_gga(.(Head, Tail), X, RES) → U1_gga(Head, Tail, X, RES, g_in_ggga(Tail, X, .(Head, Tail), RES))
g_in_ggga(A, B, C, RES) → U2_ggga(A, B, C, RES, f_in_gga(A, .(B, C), RES))
U2_ggga(A, B, C, RES, f_out_gga(A, .(B, C), RES)) → g_out_ggga(A, B, C, RES)
U1_gga(Head, Tail, X, RES, g_out_ggga(Tail, X, .(Head, Tail), RES)) → f_out_gga(.(Head, Tail), X, RES)
The argument filtering Pi contains the following mapping:
f_in_gga(
x1,
x2,
x3) =
f_in_gga(
x1,
x2)
[] =
[]
f_out_gga(
x1,
x2,
x3) =
f_out_gga(
x1,
x2,
x3)
.(
x1,
x2) =
.(
x1,
x2)
U1_gga(
x1,
x2,
x3,
x4,
x5) =
U1_gga(
x1,
x2,
x3,
x5)
g_in_ggga(
x1,
x2,
x3,
x4) =
g_in_ggga(
x1,
x2,
x3)
U2_ggga(
x1,
x2,
x3,
x4,
x5) =
U2_ggga(
x1,
x2,
x3,
x5)
g_out_ggga(
x1,
x2,
x3,
x4) =
g_out_ggga(
x1,
x2,
x3,
x4)
F_IN_GGA(
x1,
x2,
x3) =
F_IN_GGA(
x1,
x2)
G_IN_GGGA(
x1,
x2,
x3,
x4) =
G_IN_GGGA(
x1,
x2,
x3)
We have to consider all (P,R,Pi)-chains
(7) UsableRulesProof (EQUIVALENT transformation)
For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R.
(8) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
F_IN_GGA(.(Head, Tail), X, RES) → G_IN_GGGA(Tail, X, .(Head, Tail), RES)
G_IN_GGGA(A, B, C, RES) → F_IN_GGA(A, .(B, C), RES)
R is empty.
The argument filtering Pi contains the following mapping:
.(
x1,
x2) =
.(
x1,
x2)
F_IN_GGA(
x1,
x2,
x3) =
F_IN_GGA(
x1,
x2)
G_IN_GGGA(
x1,
x2,
x3,
x4) =
G_IN_GGGA(
x1,
x2,
x3)
We have to consider all (P,R,Pi)-chains
(9) PiDPToQDPProof (SOUND transformation)
Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.
(10) Obligation:
Q DP problem:
The TRS P consists of the following rules:
F_IN_GGA(.(Head, Tail), X) → G_IN_GGGA(Tail, X, .(Head, Tail))
G_IN_GGGA(A, B, C) → F_IN_GGA(A, .(B, C))
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
(11) QDPSizeChangeProof (EQUIVALENT transformation)
By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.
From the DPs we obtained the following set of size-change graphs:
- G_IN_GGGA(A, B, C) → F_IN_GGA(A, .(B, C))
The graph contains the following edges 1 >= 1
- F_IN_GGA(.(Head, Tail), X) → G_IN_GGGA(Tail, X, .(Head, Tail))
The graph contains the following edges 1 > 1, 2 >= 2, 1 >= 3
(12) TRUE
(13) PrologToPiTRSProof (SOUND transformation)
We use the technique of [LOPSTR]. With regard to the inferred argument filtering the predicates were used in the following modes:
f_in: (b,b,f)
g_in: (b,b,b,f)
Transforming
Prolog into the following
Term Rewriting System:
Pi-finite rewrite system:
The TRS R consists of the following rules:
f_in_gga([], RES, RES) → f_out_gga([], RES, RES)
f_in_gga(.(Head, Tail), X, RES) → U1_gga(Head, Tail, X, RES, g_in_ggga(Tail, X, .(Head, Tail), RES))
g_in_ggga(A, B, C, RES) → U2_ggga(A, B, C, RES, f_in_gga(A, .(B, C), RES))
U2_ggga(A, B, C, RES, f_out_gga(A, .(B, C), RES)) → g_out_ggga(A, B, C, RES)
U1_gga(Head, Tail, X, RES, g_out_ggga(Tail, X, .(Head, Tail), RES)) → f_out_gga(.(Head, Tail), X, RES)
The argument filtering Pi contains the following mapping:
f_in_gga(
x1,
x2,
x3) =
f_in_gga(
x1,
x2)
[] =
[]
f_out_gga(
x1,
x2,
x3) =
f_out_gga(
x3)
.(
x1,
x2) =
.(
x1,
x2)
U1_gga(
x1,
x2,
x3,
x4,
x5) =
U1_gga(
x5)
g_in_ggga(
x1,
x2,
x3,
x4) =
g_in_ggga(
x1,
x2,
x3)
U2_ggga(
x1,
x2,
x3,
x4,
x5) =
U2_ggga(
x5)
g_out_ggga(
x1,
x2,
x3,
x4) =
g_out_ggga(
x4)
Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog
(14) Obligation:
Pi-finite rewrite system:
The TRS R consists of the following rules:
f_in_gga([], RES, RES) → f_out_gga([], RES, RES)
f_in_gga(.(Head, Tail), X, RES) → U1_gga(Head, Tail, X, RES, g_in_ggga(Tail, X, .(Head, Tail), RES))
g_in_ggga(A, B, C, RES) → U2_ggga(A, B, C, RES, f_in_gga(A, .(B, C), RES))
U2_ggga(A, B, C, RES, f_out_gga(A, .(B, C), RES)) → g_out_ggga(A, B, C, RES)
U1_gga(Head, Tail, X, RES, g_out_ggga(Tail, X, .(Head, Tail), RES)) → f_out_gga(.(Head, Tail), X, RES)
The argument filtering Pi contains the following mapping:
f_in_gga(
x1,
x2,
x3) =
f_in_gga(
x1,
x2)
[] =
[]
f_out_gga(
x1,
x2,
x3) =
f_out_gga(
x3)
.(
x1,
x2) =
.(
x1,
x2)
U1_gga(
x1,
x2,
x3,
x4,
x5) =
U1_gga(
x5)
g_in_ggga(
x1,
x2,
x3,
x4) =
g_in_ggga(
x1,
x2,
x3)
U2_ggga(
x1,
x2,
x3,
x4,
x5) =
U2_ggga(
x5)
g_out_ggga(
x1,
x2,
x3,
x4) =
g_out_ggga(
x4)
(15) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem:
Pi DP problem:
The TRS P consists of the following rules:
F_IN_GGA(.(Head, Tail), X, RES) → U1_GGA(Head, Tail, X, RES, g_in_ggga(Tail, X, .(Head, Tail), RES))
F_IN_GGA(.(Head, Tail), X, RES) → G_IN_GGGA(Tail, X, .(Head, Tail), RES)
G_IN_GGGA(A, B, C, RES) → U2_GGGA(A, B, C, RES, f_in_gga(A, .(B, C), RES))
G_IN_GGGA(A, B, C, RES) → F_IN_GGA(A, .(B, C), RES)
The TRS R consists of the following rules:
f_in_gga([], RES, RES) → f_out_gga([], RES, RES)
f_in_gga(.(Head, Tail), X, RES) → U1_gga(Head, Tail, X, RES, g_in_ggga(Tail, X, .(Head, Tail), RES))
g_in_ggga(A, B, C, RES) → U2_ggga(A, B, C, RES, f_in_gga(A, .(B, C), RES))
U2_ggga(A, B, C, RES, f_out_gga(A, .(B, C), RES)) → g_out_ggga(A, B, C, RES)
U1_gga(Head, Tail, X, RES, g_out_ggga(Tail, X, .(Head, Tail), RES)) → f_out_gga(.(Head, Tail), X, RES)
The argument filtering Pi contains the following mapping:
f_in_gga(
x1,
x2,
x3) =
f_in_gga(
x1,
x2)
[] =
[]
f_out_gga(
x1,
x2,
x3) =
f_out_gga(
x3)
.(
x1,
x2) =
.(
x1,
x2)
U1_gga(
x1,
x2,
x3,
x4,
x5) =
U1_gga(
x5)
g_in_ggga(
x1,
x2,
x3,
x4) =
g_in_ggga(
x1,
x2,
x3)
U2_ggga(
x1,
x2,
x3,
x4,
x5) =
U2_ggga(
x5)
g_out_ggga(
x1,
x2,
x3,
x4) =
g_out_ggga(
x4)
F_IN_GGA(
x1,
x2,
x3) =
F_IN_GGA(
x1,
x2)
U1_GGA(
x1,
x2,
x3,
x4,
x5) =
U1_GGA(
x5)
G_IN_GGGA(
x1,
x2,
x3,
x4) =
G_IN_GGGA(
x1,
x2,
x3)
U2_GGGA(
x1,
x2,
x3,
x4,
x5) =
U2_GGGA(
x5)
We have to consider all (P,R,Pi)-chains
(16) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
F_IN_GGA(.(Head, Tail), X, RES) → U1_GGA(Head, Tail, X, RES, g_in_ggga(Tail, X, .(Head, Tail), RES))
F_IN_GGA(.(Head, Tail), X, RES) → G_IN_GGGA(Tail, X, .(Head, Tail), RES)
G_IN_GGGA(A, B, C, RES) → U2_GGGA(A, B, C, RES, f_in_gga(A, .(B, C), RES))
G_IN_GGGA(A, B, C, RES) → F_IN_GGA(A, .(B, C), RES)
The TRS R consists of the following rules:
f_in_gga([], RES, RES) → f_out_gga([], RES, RES)
f_in_gga(.(Head, Tail), X, RES) → U1_gga(Head, Tail, X, RES, g_in_ggga(Tail, X, .(Head, Tail), RES))
g_in_ggga(A, B, C, RES) → U2_ggga(A, B, C, RES, f_in_gga(A, .(B, C), RES))
U2_ggga(A, B, C, RES, f_out_gga(A, .(B, C), RES)) → g_out_ggga(A, B, C, RES)
U1_gga(Head, Tail, X, RES, g_out_ggga(Tail, X, .(Head, Tail), RES)) → f_out_gga(.(Head, Tail), X, RES)
The argument filtering Pi contains the following mapping:
f_in_gga(
x1,
x2,
x3) =
f_in_gga(
x1,
x2)
[] =
[]
f_out_gga(
x1,
x2,
x3) =
f_out_gga(
x3)
.(
x1,
x2) =
.(
x1,
x2)
U1_gga(
x1,
x2,
x3,
x4,
x5) =
U1_gga(
x5)
g_in_ggga(
x1,
x2,
x3,
x4) =
g_in_ggga(
x1,
x2,
x3)
U2_ggga(
x1,
x2,
x3,
x4,
x5) =
U2_ggga(
x5)
g_out_ggga(
x1,
x2,
x3,
x4) =
g_out_ggga(
x4)
F_IN_GGA(
x1,
x2,
x3) =
F_IN_GGA(
x1,
x2)
U1_GGA(
x1,
x2,
x3,
x4,
x5) =
U1_GGA(
x5)
G_IN_GGGA(
x1,
x2,
x3,
x4) =
G_IN_GGGA(
x1,
x2,
x3)
U2_GGGA(
x1,
x2,
x3,
x4,
x5) =
U2_GGGA(
x5)
We have to consider all (P,R,Pi)-chains
(17) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 2 less nodes.
(18) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
F_IN_GGA(.(Head, Tail), X, RES) → G_IN_GGGA(Tail, X, .(Head, Tail), RES)
G_IN_GGGA(A, B, C, RES) → F_IN_GGA(A, .(B, C), RES)
The TRS R consists of the following rules:
f_in_gga([], RES, RES) → f_out_gga([], RES, RES)
f_in_gga(.(Head, Tail), X, RES) → U1_gga(Head, Tail, X, RES, g_in_ggga(Tail, X, .(Head, Tail), RES))
g_in_ggga(A, B, C, RES) → U2_ggga(A, B, C, RES, f_in_gga(A, .(B, C), RES))
U2_ggga(A, B, C, RES, f_out_gga(A, .(B, C), RES)) → g_out_ggga(A, B, C, RES)
U1_gga(Head, Tail, X, RES, g_out_ggga(Tail, X, .(Head, Tail), RES)) → f_out_gga(.(Head, Tail), X, RES)
The argument filtering Pi contains the following mapping:
f_in_gga(
x1,
x2,
x3) =
f_in_gga(
x1,
x2)
[] =
[]
f_out_gga(
x1,
x2,
x3) =
f_out_gga(
x3)
.(
x1,
x2) =
.(
x1,
x2)
U1_gga(
x1,
x2,
x3,
x4,
x5) =
U1_gga(
x5)
g_in_ggga(
x1,
x2,
x3,
x4) =
g_in_ggga(
x1,
x2,
x3)
U2_ggga(
x1,
x2,
x3,
x4,
x5) =
U2_ggga(
x5)
g_out_ggga(
x1,
x2,
x3,
x4) =
g_out_ggga(
x4)
F_IN_GGA(
x1,
x2,
x3) =
F_IN_GGA(
x1,
x2)
G_IN_GGGA(
x1,
x2,
x3,
x4) =
G_IN_GGGA(
x1,
x2,
x3)
We have to consider all (P,R,Pi)-chains
(19) UsableRulesProof (EQUIVALENT transformation)
For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R.
(20) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
F_IN_GGA(.(Head, Tail), X, RES) → G_IN_GGGA(Tail, X, .(Head, Tail), RES)
G_IN_GGGA(A, B, C, RES) → F_IN_GGA(A, .(B, C), RES)
R is empty.
The argument filtering Pi contains the following mapping:
.(
x1,
x2) =
.(
x1,
x2)
F_IN_GGA(
x1,
x2,
x3) =
F_IN_GGA(
x1,
x2)
G_IN_GGGA(
x1,
x2,
x3,
x4) =
G_IN_GGGA(
x1,
x2,
x3)
We have to consider all (P,R,Pi)-chains
(21) PiDPToQDPProof (SOUND transformation)
Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.
(22) Obligation:
Q DP problem:
The TRS P consists of the following rules:
F_IN_GGA(.(Head, Tail), X) → G_IN_GGGA(Tail, X, .(Head, Tail))
G_IN_GGGA(A, B, C) → F_IN_GGA(A, .(B, C))
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.